instance

问题 I am trying to create a system which enables user to upload a zipfile, and then extract it using post_save signal. class Project: .... file_zip=FileField(upload_to='projects/%Y/%m/%d') @receiver(post_save, sender=Project) def unzip_and_process(sender, **kwargs): #project_zip = FieldFile.open(file_zip, mode='rb') file_path = sender.instance.file_zip.path with zipfile.ZipFile(file_path, 'r') as project_zip: project_zip.extractall(re.search('[^\s]+(?=\.zip)', file_path).group(0)) project_zip

问题 I am trying to create a system which enables user to upload a zipfile, and then extract it using post_save signal. class Project: .... file_zip=FileField(upload_to='projects/%Y/%m/%d') @receiver(post_save, sender=Project) def unzip_and_process(sender, **kwargs): #project_zip = FieldFile.open(file_zip, mode='rb') file_path = sender.instance.file_zip.path with zipfile.ZipFile(file_path, 'r') as project_zip: project_zip.extractall(re.search('[^\s]+(?=\.zip)', file_path).group(0)) project_zip

问题 What I want to achieve: when I run application from start menu, app starts (if app not running). If an app is already running, then don't create another instance, just show the previous running app window. What I've tried: created a .txt file in a directory, write ' running ' & ' not running ' into the file while opening & exiting the window. And checking the file contents at very start. For ex: When starting app: 1.) Check the file content, 2.) If file content is ' running ', show warning &

问题 I am learning android MVVM pattern android development. I wanted to create a recycclerview activity to show data from server. But it's not accepting my viewmodel class. Bellow is my logcat errors. LOGCAT 2020-04-12 21:03:18.026 2008-2008/com.shovon.mvvm E/AndroidRuntime: FATAL EXCEPTION: main Process: com.shovon.mvvm, PID: 2008 java.lang.RuntimeException: Unable to start activity ComponentInfo{com.shovon.mvvm/com.shovon.mvvm.activity.RecyclerActivity}: java.lang.RuntimeException: Cannot

问题 I am learning android MVVM pattern android development. I wanted to create a recycclerview activity to show data from server. But it's not accepting my viewmodel class. Bellow is my logcat errors. LOGCAT 2020-04-12 21:03:18.026 2008-2008/com.shovon.mvvm E/AndroidRuntime: FATAL EXCEPTION: main Process: com.shovon.mvvm, PID: 2008 java.lang.RuntimeException: Unable to start activity ComponentInfo{com.shovon.mvvm/com.shovon.mvvm.activity.RecyclerActivity}: java.lang.RuntimeException: Cannot

问题 In the code below, is it possible to convert x to the type you're passing into Activator.CreateInstance without knowing what it is ahead of time? I tried passing in typeof... but that doesn't work. var testClasses = AppDomain.CurrentDomain.GetAssemblies() .Single(a=>a.FullName.StartsWith("VerifyStuff")).GetTypes() .Where(t=>t.UnderlyingSystemType.Name.StartsWith("VerifyXXX")); var x = Activator.CreateInstance(testClasses.ElementAt(0)); Thanks! 回答1: You simply need to cast it: MyObject x =

问题 I know you can start / stop container instance from Azure CLI using below command az container stop --name mycontainer --resource-group myResourceGroupVM but since in my org azure cli gives "Access is denied" error i want to know how to do same using powershell or ARM. I am unable to get any powershell cmdlet to start or stop conrainer instance from documentation. Please help. I referred below documentation for same: https://docs.microsoft.com/en-us/powershell/module/azurerm.containerinstance

问题 This question already has answers here : Getting the name of a variable as a string (25 answers) Getting an instance name inside class __init__() [duplicate] (10 answers) Closed 5 years ago . I understand that you should never use variable names within the program, but I am using is strictly for debug purposes and would like to convey the name of the variable to the user for readability. I have a file like this: class MyClass(object): def __init__(self): pass def foo(msg=""): debug("Called

问题 This question already has answers here : Getting the name of a variable as a string (25 answers) Getting an instance name inside class __init__() [duplicate] (10 answers) Closed 5 years ago . I understand that you should never use variable names within the program, but I am using is strictly for debug purposes and would like to convey the name of the variable to the user for readability. I have a file like this: class MyClass(object): def __init__(self): pass def foo(msg=""): debug("Called

问题 This question already has answers here : Getting the name of a variable as a string (25 answers) Getting an instance name inside class __init__() [duplicate] (10 answers) Closed 5 years ago . I understand that you should never use variable names within the program, but I am using is strictly for debug purposes and would like to convey the name of the variable to the user for readability. I have a file like this: class MyClass(object): def __init__(self): pass def foo(msg=""): debug("Called