inspect

How to use inspect to get the caller's info from callee in Python?

由 限于喜欢 提交于 2019-11-26 21:38:32
I need to get the caller info (what file/what line) from callee. I learned that I can use inpect module for that for purposes, but not exactly how. How to get those info with inspect? Or is there any other way to get the info? import inspect print __file__ c=inspect.currentframe() print c.f_lineno def hello(): print inspect.stack ?? what file called me in what line? hello() The caller's frame is one frame higher than the current frame. You can use inspect.currentframe().f_back to find the caller's frame. Then use inspect.getframeinfo to get the caller's filename and line number. import inspect

How can I read a function's signature including default argument values?

由 半腔热情 提交于 2019-11-26 21:28:59
Given a function object, how can I get its signature? For example, for: def myMethod(firt, second, third='something'): pass I would like to get "myMethod(firt, second, third='something')" . import inspect def foo(a, b, x='blah'): pass print(inspect.getargspec(foo)) # ArgSpec(args=['a', 'b', 'x'], varargs=None, keywords=None, defaults=('blah',)) However, note that inspect.getargspec() is deprecated since Python 3.0. Python 3.0--3.4 recommends inspect.getfullargspec() . Python 3.5+ recommends inspect.signature() . Arguably the easiest way to find the signature for a function would be help

Using a dictionary to select function to execute

由 混江龙づ霸主 提交于 2019-11-26 09:23:36
问题 I am trying to use functional programming to create a dictionary containing a key and a function to execute: myDict={} myItems=(\"P1\",\"P2\",\"P3\",....\"Pn\") def myMain(key): def ExecP1(): pass def ExecP2(): pass def ExecP3(): pass ... def ExecPn(): pass Now, I have seen a code used to find the defined functions in a module, and I need to do something like this: for myitem in myItems: myDict[myitem] = ??? #to dynamically find the corresponding function So my question is, How do I make a

How to use inspect to get the caller's info from callee in Python?

由 て烟熏妆下的殇ゞ 提交于 2019-11-26 08:02:30
问题 I need to get the caller info (what file/what line) from callee. I learned that I can use inpect module for that for purposes, but not exactly how. How to get those info with inspect? Or is there any other way to get the info? import inspect print __file__ c=inspect.currentframe() print c.f_lineno def hello(): print inspect.stack ?? what file called me in what line? hello() 回答1: The caller's frame is one frame higher than the current frame. You can use inspect.currentframe().f_back to find

How can I read a function's signature including default argument values?

由 泄露秘密 提交于 2019-11-26 07:56:26
问题 Given a function object, how can I get its signature? For example, for: def myMethod(firt, second, third=\'something\'): pass I would like to get \"myMethod(firt, second, third=\'something\')\" . 回答1: import inspect def foo(a, b, x='blah'): pass print(inspect.getargspec(foo)) # ArgSpec(args=['a', 'b', 'x'], varargs=None, keywords=None, defaults=('blah',)) However, note that inspect.getargspec() is deprecated since Python 3.0. Python 3.0--3.4 recommends inspect.getfullargspec(). Python 3.5+

How can I get a list of all classes within current module in Python?

由 岁酱吖の 提交于 2019-11-26 03:47:20
问题 I\'ve seen plenty of examples of people extracting all of the classes from a module, usually something like: # foo.py class Foo: pass # test.py import inspect import foo for name, obj in inspect.getmembers(foo): if inspect.isclass(obj): print obj Awesome. But I can\'t find out how to get all of the classes from the current module. # foo.py import inspect class Foo: pass def print_classes(): for name, obj in inspect.getmembers(???): # what do I do here? if inspect.isclass(obj): print obj #

How to list all functions in a Python module?

由 旧城冷巷雨未停 提交于 2019-11-26 03:15:01
问题 I have a python module installed on my system and I\'d like to be able to see what functions/classes/methods are available in it. I want to call the doc function on each one. In ruby I can do something like ClassName.methods to get a list of all the methods available on that class. Is there something similar in python? eg. something like: from somemodule import foo print foo.methods # or whatever is the correct method to call 回答1: The inspect module. Also see the pydoc module, the help()
订阅 inspect