inline

问题 I have this html that contains two inline divs: HTML div.inline { display: inline-block; } <div class="inline"> <img src="http://via.placeholder.com/350x150" /> </div> <div class="inline"> <h1 class="title"> TOPIC </h1> </div> The image and the h1 are shown correctly side by side. Now i would like the h1 to be vertically centered. It should be somthing like this +----------+ | | | IMG | TOPIC | | +----------+ How do i do this? 回答1: you can use flex .container { display: flex; align-items:

问题 I'm writing code (using GCC 4.7.2), where I'm excessively logging stuff during the testing phase in countless positions of the code. These loggings should disappear on the release binary. I'm doing the logging via a function just like void log(std::string msg); . As these function calls are many and distributed via the whole code in many files, I had the idea to make it an inline function and just give it an empty body for the release binary. No my question is: what does the compiler do with

问题 The question is basically already stated in the title, but to clarify: I'm trying to horizontally center an anchor <a> in a main content area. I would like to do this without : Using fixed widths Adding extra markup (an extra parent div for example) Styling the parent container (so setting the parent to text-align:center for example) Setting the <a> as a full width block (I would like to keep the clickable area a big as the link itself) So basically I would like to do this just by styling the

问题 The question is basically already stated in the title, but to clarify: I'm trying to horizontally center an anchor <a> in a main content area. I would like to do this without : Using fixed widths Adding extra markup (an extra parent div for example) Styling the parent container (so setting the parent to text-align:center for example) Setting the <a> as a full width block (I would like to keep the clickable area a big as the link itself) So basically I would like to do this just by styling the

问题 If I have a header foo.h which I include all over my project, it seems to work fine when all it contains is: template<typename T> void foo(const T param) { cout << param << endl; } But I get one definition rule (ODR) errors when I add a specalization to foo.h: template<> void foo(const bool param) { cout << param << endl; } Obviously I can solve this by inline 'ing the specialization. My question is, why do I need to? If the template doesn't violate ODR, why does a specialization? 回答1: An

问题 If I have a header foo.h which I include all over my project, it seems to work fine when all it contains is: template<typename T> void foo(const T param) { cout << param << endl; } But I get one definition rule (ODR) errors when I add a specalization to foo.h: template<> void foo(const bool param) { cout << param << endl; } Obviously I can solve this by inline 'ing the specialization. My question is, why do I need to? If the template doesn't violate ODR, why does a specialization? 回答1: An

问题 If I have a header foo.h which I include all over my project, it seems to work fine when all it contains is: template<typename T> void foo(const T param) { cout << param << endl; } But I get one definition rule (ODR) errors when I add a specalization to foo.h: template<> void foo(const bool param) { cout << param << endl; } Obviously I can solve this by inline 'ing the specialization. My question is, why do I need to? If the template doesn't violate ODR, why does a specialization? 回答1: An

问题 If I have a header foo.h which I include all over my project, it seems to work fine when all it contains is: template<typename T> void foo(const T param) { cout << param << endl; } But I get one definition rule (ODR) errors when I add a specalization to foo.h: template<> void foo(const bool param) { cout << param << endl; } Obviously I can solve this by inline 'ing the specialization. My question is, why do I need to? If the template doesn't violate ODR, why does a specialization? 回答1: An

问题 I am creating a simple Matrix class. I am trying to add an unnamed template parameter to make sure it is used with integral types #include <string> #include <vector> #include <boost/utility/enable_if.hpp> #include <boost/type_traits/is_scalar.hpp> template <typename T, typename = typename boost::enable_if<boost::is_scalar<T> >::type> class Matrix { public: Matrix(const size_t nrow, const size_t ncol); private: const size_t nrow_; const size_t ncol_; std::vector<std::string> rownames_; std:

问题 I am creating a simple Matrix class. I am trying to add an unnamed template parameter to make sure it is used with integral types #include <string> #include <vector> #include <boost/utility/enable_if.hpp> #include <boost/type_traits/is_scalar.hpp> template <typename T, typename = typename boost::enable_if<boost::is_scalar<T> >::type> class Matrix { public: Matrix(const size_t nrow, const size_t ncol); private: const size_t nrow_; const size_t ncol_; std::vector<std::string> rownames_; std: