infinity

Why is infinity's floating point representation apparently 0^n?

空扰寡人 提交于 2019-12-25 04:04:52
问题 I am trying to understand floating point representations. I do not understand the 'infinity' 'NaN' representations in floating point. I am looking at the table provided by TopCoder. Infinity is represented by an exponent of all 1s and a Mantissa of all 0s. I can only read it as 0^n, and I'm not sure how that tends to infinity. 回答1: You should simply ignore the bit patterns used and treat infinities and NaNs as special values. Unless you do bit-fiddling on your floats (for which I see very

Is there is a more concise representation of Infinity in JSON than 1e309?

半世苍凉 提交于 2019-12-24 07:18:49
问题 It's the smallest I could find. 回答1: The JSON RFC ( http://tools.ietf.org/html/rfc4627 ) states that NaN, Positive Infinity and Negative Infinity cannot be represented in JSON: Numeric values that cannot be represented as sequences of digits (such as Infinity and NaN) are not permitted. I don't know where you're getting 1*10^309 from, because Javascript's maximum exact integer value is 2^53. When you say "concise" do you actually mean "succinct"? 来源: https://stackoverflow.com/questions

positive and negative infinity for integral types in c++

不打扰是莪最后的温柔 提交于 2019-12-24 00:09:25
问题 I am reading about positive and negative infinity in c++. I read that integral types dont have a infinite value ie. std::numeric_limits<int>::infinity(); wont work, but std::numeric_limits<int>::max(); will work and will represent the maximum possible value that can be represented by the integral type. so the std::numeric_limits<int>::max(); of the integral type could be taken as its positive infinite limit ? Or the integral type has only the max value and the infinity value is not true ? 回答1

double d=1/0.0 vs double d=1/0

雨燕双飞 提交于 2019-12-23 17:38:14
问题 double d=1/0.0; System.out.println(d); It prints Infinity , but if we will write double d=1/0; and print it we'll get this exception: Exception in thread "main" java.lang.ArithmeticException: / by zero at D.main(D.java:3) Why does Java know in one case that diving by zero is infinity but for the int 0 it is not defined? In both cases d is double and in both cases the result is infinity. 回答1: Floating point data types have a special value reserved to represent infinity, integer values do not.

What is the difference between IND and NAN numbers

只愿长相守 提交于 2019-12-23 10:25:13
问题 A NAN value means Not A Number and IND value means Indeterminate number. But what is the difference between these two. How can we represent both in c++. 回答1: But what is the difference between these two. They are both the same thing. Some platforms choose to display a non-number as some variant of NaN , while others choose to display it as some variant of IND . How can we represent both in c++. std::numeric_limits<double>::quiet_NaN() (or float or long double , if you prefer). 回答2: If your

Infinity generated in python code

谁都会走 提交于 2019-12-23 09:30:11
问题 I'm looking over some complex Python 2.6 code which is occasionally resulting in an infinity being generated (at least an Infinity being serialized by the json library -- which checks w/ math.isinf). What is especially baffling is that Python (as far as I can tell) shouldn't be able to ever produce computation results set to infinity. Am I wrong with this assumption? I was aware you can only get infinities from constants: k = float('inf') k = 1e900 回答1: Somewhere between 1e308 and 1e309 the

Javascript Infinity Object

核能气质少年 提交于 2019-12-23 06:09:37
问题 I'm caclulating the mean value of a function's request/sec, appearently the result number sometimes is too long so it displays as Infinity, is there a way to round it so it show a number only? Or make a sleep()/wait() while it's on Infinity? well to be exactly, im monitoring req/sec on a graph, when it's infinity the line goes up not towards zero 回答1: It's not too long to display. If you get Inf then you can't do anything with it other than know that it is something larger than the maximum

Why does the use of integer variables throw an exception?

谁说我不能喝 提交于 2019-12-22 04:39:11
问题 I have come across with the following two codes. Why does it not throw an exception for floating point where as in other case it will throw a runtime exception. class FloatingPoint { public static void main(String [] args) { float a=1000f; float b=a/0; System.out.println("b=" +b); } } OUTPUT:b=Infinity . If I try with int values then it will throw a runtime exception. Why is it like this? 回答1: The short answer Integral types (JLS 4.2.1) are categorically different from floating point types

What is the Infinity property used for in Javascript?

梦想与她 提交于 2019-12-19 19:49:51
问题 Why is the Infinity property used as a command (rather than a result) For example, this code below works, but the result isn't what I expected. alert(isOdd(Infinity)); function isOdd(num) { return num%2==1; } 回答1: MDN REFERENCE Infinity is a property of the global object, i.e. it is a variable in global scope. The initial value of Infinity is Number.POSITIVE_INFINITY. The value Infinity (positive infinity) is greater than any other number. This value behaves mathematically like infinity; for

What is the Infinity property used for in Javascript?

拟墨画扇 提交于 2019-12-19 19:48:54
问题 Why is the Infinity property used as a command (rather than a result) For example, this code below works, but the result isn't what I expected. alert(isOdd(Infinity)); function isOdd(num) { return num%2==1; } 回答1: MDN REFERENCE Infinity is a property of the global object, i.e. it is a variable in global scope. The initial value of Infinity is Number.POSITIVE_INFINITY. The value Infinity (positive infinity) is greater than any other number. This value behaves mathematically like infinity; for