infinite-loop

问题 Can't figure out how to stop this while loop from repeating infinitely. I'm using hasNextInt to check if user input is an int. If an int is not entered the loop repeats infinitely. public static void validatingInput(){ Scanner scan = new Scanner(System.in); boolean valid = false; int userNumber = 0; while(!valid) { System.out.println("Enter number between 1 and 20: "); if (scan.hasNextInt()) { userNumber = scan.nextInt(); valid = true; } else System.out.print("Not an int. "); } } 回答1: You

问题 I'm trying to implement my own Applicative parser, here's the code I use: {-# LANGUAGE ApplicativeDo, LambdaCase #-} module Parser where -- Implementation of an Applicative Parser import Data.Char import Control.Applicative (some, many, empty, (<*>), (<$>), (<|>), Alternative) data Parser a = Parser { runParser :: String -> [(a, String)] } instance Functor Parser where -- fmap :: (a -> b) -> (Parser a -> Parser b) fmap f (Parser p) = Parser (\s -> [(f a, s') | (a,s') <- p s]) instance

问题 I have an array of pointers (this is algorithmic, so don't go into language specifics). Most of the time, this array points to locations outside of the array, but it degrades to a point where every pointer in the array points to another pointer in the array. Eventually, these pointers form an infinite loop. So on the assumption that the entire array consists of pointers to another location in the array and you start at the beginning, how could you find the length of the loop with the highest

问题 I was looking all over the web there is a very known issue with Flexslider either with the slider or the carousel when it gets to the last item in the slider it flys back to the first one instead of keeping the infinite loop smoothly I can't believe no one has a solution for that this is the flexSlider code I am using: $(document).ready(function() { $(window).load(function() { $('#carousel-two').flexslider({ animation : "slide", controlNav : false, animationLoop : true, slideshow : true,

问题 I was wondering if it was possible to create an infinite loop which does not crash the browser I am working on a gallery type thing which will pulse as it scrolls across the screen. This is what I have so far (which obviously crashes the browser): var i = 0; while (i < 1){ $('.block').each(function(index) { $(this).css('left', $(this).position().left - 10) if (($(this).position().left) < ($(window).width() * 0.4)) { $(this).html('<p>Test 1</p>'); $(this).animate({ width: "500px", height:

问题 Is there any way to kill a running OpenCL kernel through the OpenCL API? I haven't found anything in the spec. The only solutions I could come up with are 1) periodically checking a flag in the kernel that the host writes to when it wants the kernel to stop, or 2) running the kernel in a separate process and killing the entire process. I don't think either of those are very elegant solutions, and I'm not sure #1 would even work reliably. 回答1: No, the OpenCL API doesn't allow to interrupt a

问题 I want to be able to retrieve the value of an array by using the numeric key. The catch is that if the key is beyond the array length, I need it to loop through the array again. $my_array = array('zero','one','two','three','four','five','six','seven'); function loopArrayValues($array,$key){ //this is what is needed to return return } echo "Key 2 is ".loopArrayValues($my_array,2)."<br />"; echo "Key 11 is ".loopArrayValues($my_array,11)."<br />"; echo "Key 150 is ".loopArrayValues($my_array,11

问题 I know what an Infinite Loop error is. Is a stack overflow error the same thing. If not, what is the difference? Can you give example code as well? 回答1: If, instead of infinite loop, you have infinite (or very deep) recursion (function invoking itself), then you will get stack overflow. Whenever a function is invoked, some part of stack memory is consumed. Once all the stack is exhausted, you get - stack overflow error. 回答2: These are not the same thing. Infinite loop error is dealing with

问题 This question already has answers here : Seemingly endless loop terminates, unless System.out.println is used (6 answers) Closed 2 years ago . I was messing around with stuff in my eclipse when, to my surprise, I found that this piece of code when run gets terminated without any error / exception public class Test { public static void main(String[] args) { for(int i = 2; i > 0; i++){ int c = 0; } } } while his piece of code keeps on executing public class Test { public static void main(String

问题 I am looking at somebody else's code and I found this piece of code: for (;;) { I'm not a Java expert; what is this line of code doing? At first, I thought it would be creating an infinite loop, but in the very SAME class this programmer uses while(true) Which (correct me if I'm wrong) IS an infinite loop. Are these two identical? Why would somebody change their method to repeat the same process? Any insight would help, Thanks! 回答1: Remember the three clauses of the for() are [1]