indexoutofboundsexception

问题 This question already has an answer here: Split string with dot as delimiter 13 answers Why does the second line of this code throw ArrayIndexOutOfBoundsException ? String filename = \"D:/some folder/001.docx\"; String extensionRemoved = filename.split(\".\")[0]; While this works: String driveLetter = filename.split(\"/\")[0]; I use Java 7. 回答1: You need to escape the dot if you want to split on a literal dot: String extensionRemoved = filename.split("\\.")[0]; Otherwise you are splitting on

问题 I have this code in C which takes in bunch of char s #include<stdio.h> # define NEWLINE \'\\n\' int main() { char c; char str[6]; int i = 0; while( ((c = getchar()) != NEWLINE)) { str[i] = c; ++i; printf(\"%d\\n\", i); } return 0; } Input is: testtesttest Output: 1 2 3 4 5 6 7 8 117 118 119 120 My questions are: Why don\'t I get an out of bounds (segmentation fault) exception although I clearly exceed the capacity of the array? Why do the numbers in the output suddenly jump to very big

问题 I\'m telling my program to print out line 53 of an output. Is this error telling me that there aren\'t that many lines and therefore can not print it out? 回答1: If you have a list with 53 items, the last one is thelist[52] because indexing start at 0. 回答2: Yes, You are trying to access an element of the list that does not exist. MyList = ["item1", "item2"] print MyList[0] # Will work print MyList[1] # Will Work print MyList[2] # Will crash. Have you got an off-by-one error? 回答3: Yes. The

问题 Why does ArrayIndexOutOfBoundsException occur and how to avoid it in Android? 回答1: This exception is thrown when you try to access an array item that doesn't exist: String [] myArray = new String[2]; myArray[2] = "something"; // Throws exception myArray[-1] = "something"; // Throws exception You should check that your index is not negative and not higher than the array length before accessing an array item. 回答2: Why does ArrayIndexOutOfBoundsException occur [...] Here is a quotation from the

问题 This question already has an answer here: What causes a java.lang.ArrayIndexOutOfBoundsException and how do I prevent it? 25 answers If your question is I am getting a java.lang.ArrayIndexOutOfBoundsException in my code and I do not understand why it is happening. What does it mean and how can I avoid it? This is meant to be the most comprehensive Canonical collection of information on this java.lang.ArrayIndexOutOfBoundsException topic as well as the java.lang.IndexOutOfBoundsException .

问题 What does ArrayIndexOutOfBoundsException mean and how do I get rid of it? Here is a code sample that triggers the exception: String[] name = { \"tom\", \"dick\", \"harry\" }; for (int i = 0; i <= name.length; i++) { System.out.println(name[i]); } 回答1: Your first port of call should be the documentation which explains it reasonably clearly: Thrown to indicate that an array has been accessed with an illegal index. The index is either negative or greater than or equal to the size of the array.