increment

问题 I was browsing Google Code when I chanced upon this project called JSpeed - optimization for Javascript. I noticed one of the optimization was to change i++ to ++i in for loop statements. Before Optimization for (i=0;i<1;i++) {} for (var i = 0, j = 0; i < 1000000; i++, j++) { if (i == 4) { var tmp = i / 2; } if ((i % 2) == 0) { var tmp = i / 2; i++; } } var arr = new Array(1000000); for (i = 0; i < arr.length; i++) {} After optimization for(var i=0;i<1;++i){} for(var i=0,j=0;i<1000000;++i,++j

问题 I was browsing Google Code when I chanced upon this project called JSpeed - optimization for Javascript. I noticed one of the optimization was to change i++ to ++i in for loop statements. Before Optimization for (i=0;i<1;i++) {} for (var i = 0, j = 0; i < 1000000; i++, j++) { if (i == 4) { var tmp = i / 2; } if ((i % 2) == 0) { var tmp = i / 2; i++; } } var arr = new Array(1000000); for (i = 0; i < arr.length; i++) {} After optimization for(var i=0;i<1;++i){} for(var i=0,j=0;i<1000000;++i,++j

问题 can you help me with this? $(document).ready(function(){ $("ul.fam:eq(0) li:eq(2)").addClass("redbold"); }); In this code, is there a way to loop or increment the '0' value in -> $("ul.fam:eq(0) ? Like making it 0,1,2,3,4,5 and so on... and stop the loop for example when it reaches '3' Thank you. 回答1: You can use the :lt() (less than index) selector, like this: $(document).ready(function(){ $("ul.fam:lt(4) > li:nth-child(3)").addClass("redbold"); }); You can test it out here. This will be the

问题 I have some PHP code here: $a = 1; echo "<div>$a</div> <div class='alert alert-info' style='border-radius: 20px'> <div style='padding: 10px; span5'> <span class='label label-info' font-size='30px'><em>Tournament | Year | Round | Question # | Category</em></span><span style='margin-left: 500px; text-align: right'>ID: $id</span></div> <b>$tournament |</b> <b>$year |</b> <b>$round |</b> <b>$num |</b> <b>$category</b> <p><em>Question:</em> $question</p> <div class='row'><div class='alert alert

问题 In this question i asked how to perform a conditional increment. The provided answer worked, but does not scale well on huge data-sets. The Input: <Users> <User> <id>1</id> <username>jack</username> </User> <User> <id>2</id> <username>bob</username> </User> <User> <id>3</id> <username>bob</username> </User> <User> <id>4</id> <username>jack</username> </User> </Users> The desired output (in optimal time-complexity): <Users> <User> <id>1</id> <username>jack01</username> </User> <User> <id>2</id

问题 I am totally lost why I get these results: int i = 1; int[] a = new int[6]; a[0] = 0; a[1] = 1; a[2] = 2; a[3] = 3; a[4] = 4; a[5] = 5; i += i + a[i++] + a[i++]; //i is 5 i = 1; i += i + a[i++] + a[i++] + a[i++]; // i is 8 I (wrongly) thought that there are these options: i = i(=1) + a[i++] + etc - meaning that i = 1 is cached and not changed then. Expression evaluation order is exactly from left to right, I guess (?!). i is increased, which results (for first example) in i = i(=3) + a[1] + a

问题 Here im having a bit of an issue with this very simple script Ive written up. The aim for this script is to simply reduce the given number by one each time the button is clicked. I cannot appear to do this.. My global variable being the Number=100 doesnt appear to change, or change more than once.. Apologies for not being able to explain this well. Here is the part im working on..: <script> var Number = 100; // Number i want changed and to keep changing each button click function outcome() {

问题 my code is: public class Box { public static void main(String[] args) { Integer z = new Integer(43); z++; Integer h = new Integer(44); System.out.println("z == h -> " + (h == z )); } } Output:- z == h -> false why the output is false when the values of both the objects is equal? Is there any other way in which we can make the objects equal? 回答1: You are trying to compare two different object and not their values. z and h points to two different Integer object which hold same value. z == h

问题 I want to increment an Int? Currently I have written this : return index != nil ? index!+1 : nil Is there some prettier way to write this ? 回答1: For the sake of completeness, Optional has a map() method: /// If `self == nil`, returns `nil`. Otherwise, returns `f(self!)`. @warn_unused_result @rethrows public func map<U>(@noescape f: (Wrapped) throws -> U) rethrows -> U? Therefore index != nil ? index! + 1 : nil is equivalent to index.map { $0 + 1 } 回答2: You can call the advanced(by:) function

问题 I want to increment an Int? Currently I have written this : return index != nil ? index!+1 : nil Is there some prettier way to write this ? 回答1: For the sake of completeness, Optional has a map() method: /// If `self == nil`, returns `nil`. Otherwise, returns `f(self!)`. @warn_unused_result @rethrows public func map<U>(@noescape f: (Wrapped) throws -> U) rethrows -> U? Therefore index != nil ? index! + 1 : nil is equivalent to index.map { $0 + 1 } 回答2: You can call the advanced(by:) function