increment

问题 This question already has answers here : Unexpected order of evaluation (compiler bug?) [duplicate] (3 answers) Closed 5 years ago . I'm new to C++ and study the increment and decrement operators. So I tried this example: int x = 4; cout << ++x << " " << x++ << " " << x++ << endl << endl; cout << x << endl; It returns this weird output on C++ .NET and QtCreator and 5 online C++ compilers: 7 5 4 7 The weird thing is that I expect something like this: 5 5 6 7 Can you explain what happens? 回答1:

问题 i wanted to search and replace, implement after the thread here, unfortunately it does not work. gVim find/replace with counter Can anyone help me? Working :let n=[0] | %s/|-\n|/\=map(n,'v:val+1')/g Not working :let n=[0] | %s/|-\n|/BLABLA\=map(n,'v:val+1')/g Why? how do I mask the functionon? Example {| class="wikitable" ! Number ! Name ! Type ! Default Value ! Duration ! Activation ! Status ! EDIT |- | | Adobe-Dummy-Cart-Total | Custom Script | | Pageview | Active | Approved | Edit |- | |

问题 I'm learning Python (slowly but surely) but need to write a program that (among other things) increments between two hex values e.g. 30D681 and 3227FF. I'm having trouble finding the best way to do this. So far I have seen a snippet of code on here that separates the hex into 30, D6 and 81, then works like this- char = 30 char2 = D6 char3 = 81 def doublehex(): global char,char2,char3 for x in range(255): char = char + 1 a = str(chr(char)).encode("hex") for p in range(255): char2 = char2 + 1 b

问题 i += a should be equivalent to i = i + a. In the case where a == 1, this is supposedly less efficient as ++i as it involves more accesses to memory; or will the compiler make it exactly the same as ++i? 回答1: It is easy to answer: the C# compiler translates C# source code to IL opcodes. There is no dedicated IL opcode that performs the equivalent of the ++ operator. Which is easy to see if you look at the generated IL with the ildasm.exe tool. This sample C# snippet: int ix = 0; ix++; ix = ix

问题 i += a should be equivalent to i = i + a. In the case where a == 1, this is supposedly less efficient as ++i as it involves more accesses to memory; or will the compiler make it exactly the same as ++i? 回答1: It is easy to answer: the C# compiler translates C# source code to IL opcodes. There is no dedicated IL opcode that performs the equivalent of the ++ operator. Which is easy to see if you look at the generated IL with the ildasm.exe tool. This sample C# snippet: int ix = 0; ix++; ix = ix

问题 i += a should be equivalent to i = i + a. In the case where a == 1, this is supposedly less efficient as ++i as it involves more accesses to memory; or will the compiler make it exactly the same as ++i? 回答1: It is easy to answer: the C# compiler translates C# source code to IL opcodes. There is no dedicated IL opcode that performs the equivalent of the ++ operator. Which is easy to see if you look at the generated IL with the ildasm.exe tool. This sample C# snippet: int ix = 0; ix++; ix = ix

来源： https://stackoverflow.com/questions/63670099/why-this-loop-runs-10-times-instead-of-5

来源： https://stackoverflow.com/questions/63670099/why-this-loop-runs-10-times-instead-of-5

来源： https://stackoverflow.com/questions/32729055/rotating-image-in-increments-on-click

来源： https://stackoverflow.com/questions/32729055/rotating-image-in-increments-on-click