implode

How to implode(reverse of pandas explode) based on a column

点点圈 提交于 2021-02-15 05:53:17
问题 I have a dataframe df like below NETWORK config_id APPLICABLE_DAYS Case Delivery 0 Grocery 5399 SUN 10 1 1 Grocery 5399 MON 20 2 2 Grocery 5399 TUE 30 3 3 Grocery 5399 WED 40 4 I want to implode( combine Applicable_days from multiple rows into single row like below) and get the average case and delivery per config_id NETWORK config_id APPLICABLE_DAYS Avg_Cases Avg_Delivery 0 Grocery 5399 SUN,MON,TUE,WED 90 10 using the groupby on network,config_id i can get the avg_cases and avg_delivery like

PHP explode and MySQL query to search in multiple columns

浪子不回头ぞ 提交于 2021-02-11 12:17:58
问题 I have a form where I want a user to enter one or more words. These words should then match mutiple columns in a MySQL database. I have started to build some code but I'm stuck. <?php $term = $_SESSION['session_searchstring']; //Let's say that session is John Doe $searchterm = explode(' ',$term); $searchFieldName = "name"; $searchCondition = "$searchFieldName LIKE '%" . implode("%' OR $searchFieldName LIKE '%", $searchterm) . "%'"; $sql = "SELECT * FROM students WHERE $searchCondition;"; echo

PHP explode and MySQL query to search in multiple columns

僤鯓⒐⒋嵵緔 提交于 2021-02-11 12:16:17
问题 I have a form where I want a user to enter one or more words. These words should then match mutiple columns in a MySQL database. I have started to build some code but I'm stuck. <?php $term = $_SESSION['session_searchstring']; //Let's say that session is John Doe $searchterm = explode(' ',$term); $searchFieldName = "name"; $searchCondition = "$searchFieldName LIKE '%" . implode("%' OR $searchFieldName LIKE '%", $searchterm) . "%'"; $sql = "SELECT * FROM students WHERE $searchCondition;"; echo

Easily Alternate Delimiters in a Join

放肆的年华 提交于 2021-02-07 20:13:04
问题 I have a list of tuples like so (the strings are fillers... my actual code has unknown values for these): list = [ ('one', 'two', 'one'), ('one', 'two', 'one', 'two', 'one'), ('one', 'two', 'one', 'two', 'one', 'two', 'one'...) ] I would like to wrap every other string (in this example, the 'two' strings) in <strong> </strong> tags. It's frustrating that I can't do '<strong>'.join(list) because every other one won't have the /. This is the only approach I can think of but the use of the flag

PHP:implode(),emplode() 字符串数组,数组字符串转换函数

给你一囗甜甜゛ 提交于 2020-04-06 08:11:57
1.implode()-Join array elements with a string( 把数组元素组合为一个字符串。 ) string implode([string $separator,] array $arr) separator 可选,规定数组元素之间放置的内容。默认呢是""(空字符串)。 arr 必选。要结合为字符串的数组。 虽然 separator 参数是可选的。但是为了向后兼容,推荐您使用使用两个参数。 注释:implode()可以接收两种参数顺序。但由于历史原因,explode()是不行的,必须保证separator必须在string之前 例子: <?php $arr=array('Hello','World!','Beautiful','Day!'); echo implode('',$arr); ?> 输出: Hello World! Beautiful Day! 2.explode()-把字符串分割为数组 explode(separator,string, limit) separator ,必需。规定在哪里分割字符串。string ,必需。要分割的字符串。limit,可选。规定锁返回的数组元素的最大数目。 本函数返回由字符串组成的数组,其中的每个元素都是由 separator 作为边界点分割出来的子字符串。 separator 参数不能是空字符串。如果

PHP中implode()和explode()

北慕城南 提交于 2020-04-06 08:11:03
1, implode()函数返回由数组元素组合成的字符串,函数语法:string implode(separator,array),separator参数可选,规定数组元素之间放置的内容,默认是空字符串;array参数表示要组合为字符串的数组。 实例: 1 <?php 2 $arr = array('Hello','World!','I','love','Shanghai!'); 3 echo implode(" ",$arr); 4 ?> 输出: Hello World! I love Shanghai! 2,explode()函数返回有字符串组成的数组,这些字符串都是另一个字符串被字符串 delimiter 作为边界点分割出来的。函数语法:array explode(string $delimiter,string $string),$delimiter表示边界上的分割字符;$string表示输入的字符串。 1 <?php 2 $data = "foo:*:1023:1000::/home/foo:/bin/sh"; 3 list($user, $pass, $uid, $gid, $gecos, $home, $shell) = explode(":", $data); 4 echo $user; // foo 5 echo $pass; // * 6 ?> 输出: foo

Inserting HTML Form $_POST Array Into MySQL Using Implode

a 夏天 提交于 2020-02-02 13:03:53
问题 I have the following html submit form. This form is a PHP_SELF and stores the input data as an array in $_POST. <html> <body> <form method="post" action="<?php echo htmlentities($PHP_SELF); ?>"> <fieldset> <legend>Direct Bill Information:</legend> DB #: <input type="int" name="db_num[]" /> DB Amount: <input type="int" name="db_amnt[]" /> </br> DB #: <input type="int" name="db_num[]" /> DB Amount: <input type="int" name="db_amnt[]" /> </br> DB #: <input type="int" name="db_num[]" /> DB Amount:

Inserting HTML Form $_POST Array Into MySQL Using Implode

一曲冷凌霜 提交于 2020-02-02 13:03:00
问题 I have the following html submit form. This form is a PHP_SELF and stores the input data as an array in $_POST. <html> <body> <form method="post" action="<?php echo htmlentities($PHP_SELF); ?>"> <fieldset> <legend>Direct Bill Information:</legend> DB #: <input type="int" name="db_num[]" /> DB Amount: <input type="int" name="db_amnt[]" /> </br> DB #: <input type="int" name="db_num[]" /> DB Amount: <input type="int" name="db_amnt[]" /> </br> DB #: <input type="int" name="db_num[]" /> DB Amount:

PHP转换IP地址到真实地址

与世无争的帅哥 提交于 2020-01-31 00:16:54
想要把IPv4地址转为真实的地址,肯定要参考IP数据库,商业的IP数据库存储在关系型数据库中,查询和使用都非常方便,但是成本不是个人和小公司愿意承受的,所以简单应用的思路就是利用一些免费的IP数据库或者一些大网站提供的查询API,他们的数据量足够我们使用了。 1. 利用纯真IP数据库 利用本地的QQWry.Dat文件,优点是查询速度非常快,缺点是数据库文件要放在自己的空间内并且要偶尔更新数据库。时间关系废话不多说,下面是使用这个文件的函数,如果是在wordpress里面使用这个功能,把下面的代码写入主题下面的functions.php里面,然后在comments-list的输出<?php echo convertip(get_comment_author_ip()); ?>即可;如果是其他程序引用,输入一个有效的IPv4地址就可以得到一个真实的地址。 function convertip($ip) { //IP数据文件路径 $dat_path = 'QQWry.Dat'; //检查IP地址 //if(!preg_match("/^d{1,3}.d{1,3}.d{1,3}.d{1,3}$/", $ip)) { // return 'IP Address Error'; //} //打开IP数据文件 if(!$fd = @fopen($dat_path, 'rb')){ return