imei

In my application I used to lock application with IMEI code. I mean during startup application checks device IMEI and compares it with list of allowed devices. If device is in list user can continue to work, otherwise it bails out: public boolean checkIMEI(Activity activity) { TelephonyManager tm=(TelephonyManager )activity.getSystemService(Context.TELEPHONY_SERVICE); if(tm==null) { Log.v(TAG, "Can't get telephony service"); new MessageBox(activity, "Can't get telephony service. Forcing shut down!"); return false; } //encrypted IMEIs list String[] vals=activity.getResources().getStringArray(R

For some specific reasons I need to get the IMEI at some point in my Android app. Here is the code I use: TelephonyManager tm = (TelephonyManager) getSystemService(Context.TELEPHONY_SERVICE); if (android.os.Build.VERSION.SDK_INT >= android.os.Build.VERSION_CODES.M){ // API available only >= 6.0 // Get first slot to avoid issue if we have multiple sim cards String imei = tm.getDeviceId(0); } else { String imei = tm.getDeviceId(); } It works fine in most cases. However some devices (like the Huawei Honor 7) offer dual-sim capability. In the settings, the user has the possibility to switch

I am trying to find imei number in windows phone 8.1 application programmatically and i have referred many links but cannot find anything clear.I am unable to find tapi.dll for windows 8.1 phone application so is there any alternative for tapi library. Following are few links which i have refferred: http://www.codeproject.com/Questions/779684/How-to-use-tapi-lib-in-Csharp-windows-application Get IMSI and IMEI in Windows Phone 8.1 https://social.msdn.microsoft.com/Forums/windowsapps/en-US/c80fad35-df82-4c39-b263-93ea3758cadf/getting-imei-number-in-windows-phone?forum=wpdevelop It is possible to

　　Device模块管理设备信息，用于获取手机设备的相关信息，如IMEI、IMSI、型号、厂商等。通过plus.device获取设备信息管理对象。 imei : 设备的国际移动设备身份码 imsi : 设备的国际移动用户识别码 model : 设备的型号 vendor : 设备的生产厂商 uuid : 设备的唯一标识 　　直接上代码： 　　document.addEventListener('plusready', function(){ 　　　　function device(name){ 　　　　　　return plus.device.name 　　　　} 　　　　console.log(device('uuid')) 　　　　console.log(device('imei')) 　　　　console.log(device('model')) 　　　　console.log(device('vendor')) 　　　　console.log(device('imsi')) 　　}) 来源： https://www.cnblogs.com/xbfxzzq/p/11720246.html

IMEI是国际移动通讯设备识别号(International Mobile Equipment Identity)的缩写，用于GSM系统。 由15位数字组成，前6位(TAC)是型号核准号码，代表手机类型。接着2位(FAC)是最后装配号，代表产地。后6位(SNR)是串号，代表生产顺序号。最后1位(SP)是检验码。 ———————————————— IMEI校验码算法： (1).将偶数位数字分别乘以2，分别计算个位数和十位数之和 (2).将奇数位数字相加，再加上上一步算得的值 (3).如果得出的数个位是0则校验位为0，否则为10减去个位数 如：35 89 01 80 69 72 41 偶数位乘以2得到5*2=10 9*2=18 1*2=02 0*2=00 9*2=18 2*2=04 1*2=02,计算奇数位数字之和和偶数位个位十位之和，得到 3+(1+0)+8+(1+8)+0+(0+2)+8+(0+0)+6+(1+8)+7+(0+4)+4+(0+2)=63 => 校验位 10-3 = 7 ———————————————— #!/usr/bin/python3def getlastbit(): imei_str = input("input imei:") if 14 != len(imei_str): print("ERROR!Please input 14 bit IMEI!")

数组类型： shamDeviceData: [ { "projectKey":"5555", "productKey":"55555555", "deviceId":"555555555", "deviceName":"55555555", "imei":"5555555", "devReturnAlarmList":[{ "statusCode":"55555", "statusValue":"5555", "alarmDesc":"5555", "alarmType": '1' }] }, { "projectKey":"6666666", "productKey":"6666", "deviceId":"6666", "deviceName":"helo", "imei":"how are you", "devReturnAlarmList":[ { "statusCode":"6666", "statusValue":"6666", "alarmDesc":"8888888", "alarmType": '1' }, { "statusCode":"67677677", "statusValue":"676767", "alarmDesc":"99999", "alarmType": '1' }, { "statusCode":"67677677",

I am working on an app where I need details of user's SIM his phone number, imei number and operator . so far I have achieved his IMEI's numbers refering this answer , is his device single sim or dual SIM. How do I get his number of both the SIM and the name of operator for both the connections. Ana Llera Try this, works for me: TelephonyManager manager = (TelephonyManager) getSystemService(Context.TELEPHONY_SERVICE); String carrierName = manager.getNetworkOperatorName(); Fortunately there are several native solutions. Hope this will help somebody. For API >=17: TelephonyManager manager =