if-statement

How to build a search form in googlesheets with query()?

时光怂恿深爱的人放手 提交于 2021-02-10 20:29:46
问题 Requested behaviour: I would like to create a search form in Google Sheets to query a table that I use as a database. The user should be able to query the table by multiple searches categories which the user can type into a cell of the sheet. If the user does not type in a search string, then all items should be displayed. Also, the user should be able to choose between an "including OR" and an "excluding AND" search. The original table is on a different sheet than the search form. The final

Regematch if, and, and date combined forumula

醉酒当歌 提交于 2021-02-10 18:24:50
问题 I need help trying to figure out a combination google sheets formula If Cell B5 contains "Rct" And today's date is 30 days after the date defined in cell C5 And if Cell D5 and D6 both says "2 weeks ago" or "1 week ago" or contains the words "day" "hour" or "minute" (not sure if possible but instead of the all those words could if be if the text in cell D5 and D6 are the color "green" and or "Yellow") Then Cell H5 will say "Y" if the above conditions are met or "N" if they aren't The following

Can I call a function inside a Lambda expression in python

[亡魂溺海] 提交于 2021-02-10 15:53:19
问题 I have a function with including if, else condition and for loop. I want to write this function inside a lambda expression. I tried from many ways to create this lambda function. But still I couldn't do it. This is my function with another rules. negation ='no,not,never'.split(',') list2 = 'miss,loss,gone,give up,lost'.split(',') def f(sentence): s = sentence.split() l = [s.index(word) for word in s if word in list2] # Will returns list of indices (of sentence) where word is in list2 if len(l

Can I call a function inside a Lambda expression in python

情到浓时终转凉″ 提交于 2021-02-10 15:52:10
问题 I have a function with including if, else condition and for loop. I want to write this function inside a lambda expression. I tried from many ways to create this lambda function. But still I couldn't do it. This is my function with another rules. negation ='no,not,never'.split(',') list2 = 'miss,loss,gone,give up,lost'.split(',') def f(sentence): s = sentence.split() l = [s.index(word) for word in s if word in list2] # Will returns list of indices (of sentence) where word is in list2 if len(l

A problem that I tried to solve with the help of strings and repetitive instructions, but on the console the result is not what I expected

删除回忆录丶 提交于 2021-02-10 14:31:00
问题 using System; class Program { static void Main(string[] args) { string candidateName = Console.ReadLine(); string input = Console.ReadLine(); int numberOfAdmittedPersons = Convert.ToInt32(input); string result = string.Empty; for (int i = 1; i <= numberOfAdmittedPersons; i++) { string listOfAllAdmittedPersons = Console.ReadLine(); { if (i != numberOfAdmittedPersons) { result += listOfAllAdmittedPersons; } } } if (result.Contains(candidateName)) { Console.WriteLine("true"); } else { Console

How to use HTML ID in a ruby if statement condition

百般思念 提交于 2021-02-10 14:17:49
问题 I'm trying to render a form depending on which checkbox has been ticked. I want to use an if statement with the checkbox's id in the condition, but rails is throwing up an error 'undefined method tab1. Is there a way to target html in an if statement? thanks <input id="tab1" type="radio" name="tabs" checked> <label class="label-header" for="tab1"> UK Address</label> <input id="tab2" type="radio" name="tabs"> <label class="label-header"for="tab2"> International Address </label> <!-- <section

How to use HTML ID in a ruby if statement condition

泪湿孤枕 提交于 2021-02-10 14:16:26
问题 I'm trying to render a form depending on which checkbox has been ticked. I want to use an if statement with the checkbox's id in the condition, but rails is throwing up an error 'undefined method tab1. Is there a way to target html in an if statement? thanks <input id="tab1" type="radio" name="tabs" checked> <label class="label-header" for="tab1"> UK Address</label> <input id="tab2" type="radio" name="tabs"> <label class="label-header"for="tab2"> International Address </label> <!-- <section

Compressing multiple conditions in Python

时光总嘲笑我的痴心妄想 提交于 2021-02-10 08:57:42
问题 Suppose I have a list of numbers mylist and that I would like execute some code if all the elements of mylist are greater than 10. I might try if mylist[0] > 10 and mylist[1] > 10 and ... : do something but this is obviously very cumbersome. I was wondering if Python has a way of compressing multiple conditions in an if statement. I tried if mylist[i] > 10 for i in range(len(mylist)): do something but this returned an error. I am using Python 3.4. 回答1: Your attempt is pretty close. You just

Codewars: Grasshopper - Grade book challenge

情到浓时终转凉″ 提交于 2021-02-10 08:53:34
问题 This is one of those times where the solution is staring me right in the face but I can't seem to find it! So please be patient with me. The kata instruction is the following: Complete the function so that it finds the mean of the three scores passed to it and returns the letter value associated with that grade. Numerical Score Letter Grade 90 <= score <= 100 'A' 80 <= score < 90 'B' 70 <= score < 80 'C' 60 <= score < 70 'D' 0 <= score < 60 'F' Tested values are all between 0 and 100. There

Codewars: Grasshopper - Grade book challenge

浪子不回头ぞ 提交于 2021-02-10 08:51:50
问题 This is one of those times where the solution is staring me right in the face but I can't seem to find it! So please be patient with me. The kata instruction is the following: Complete the function so that it finds the mean of the three scores passed to it and returns the letter value associated with that grade. Numerical Score Letter Grade 90 <= score <= 100 'A' 80 <= score < 90 'B' 70 <= score < 80 'C' 60 <= score < 70 'D' 0 <= score < 60 'F' Tested values are all between 0 and 100. There