http-post-vars

Post method not working in PHP

℡╲_俬逩灬. 提交于 2021-02-07 19:42:06
问题 I've tried some other posts, but never made it. My php form inside html file is : <form action="test.php" method="POST"> VAR:<input type="text" name="var"><br> <input type="submit"> </form> I'm receiving the variable in test.php as <br> $_POST['var'] ---- > doesn't work! <br> Tried, $_REQUEST['var'] ----> doesn't work! I tried the form using get request, it works like a charm on the other end at test.php by using both $_GET['var'] and $_REQUEST['var'] Any way I can parse the request in the

Post method not working in PHP

微笑、不失礼 提交于 2021-02-07 19:42:02
问题 I've tried some other posts, but never made it. My php form inside html file is : <form action="test.php" method="POST"> VAR:<input type="text" name="var"><br> <input type="submit"> </form> I'm receiving the variable in test.php as <br> $_POST['var'] ---- > doesn't work! <br> Tried, $_REQUEST['var'] ----> doesn't work! I tried the form using get request, it works like a charm on the other end at test.php by using both $_GET['var'] and $_REQUEST['var'] Any way I can parse the request in the

How to pass parameters from command line to $_POST in php-script?

坚强是说给别人听的谎言 提交于 2019-12-28 02:44:06
问题 I know this could sound a little weird but I need to pass some parameters to a $_POST array. Similar to the way apache does it, or any other web server. Unfortunately I couldn't find libapache2-mod-php5 anywhere for my Ubuntu. 回答1: That's not easily doable. You can invoke the php-cgi binary and pipe a fake POST request in. But you'll need to set up a whole lot of CGI environment variables: echo 'var1=123&var2=abc' | REQUEST_METHOD=POST SCRIPT_FILENAME=script.php REDIRECT_STATUS=CGI CONTENT

keeping radio button value after post

梦想的初衷 提交于 2019-12-24 02:50:20
问题 HI i'm using a php page and i need to keep the value of and check box and radio button (checked or not checked) after post page. how could i make it? thanks 回答1: First get the radio button value. $radiobuttonvalue = $_POST['radiobuttoname'] Then for each radio button with the same name, do this <input type="radio" name="radiobuttonname" value="value" id="radiobuttonname" <?php if($radiobuttonvalue == "value") { echo 'checked="checked"';} ?> 回答2: You need something like:- <?php

AJAX POST - how to use a js variable in PHP

▼魔方 西西 提交于 2019-12-20 06:25:14
问题 The first time the page loads, there will not be anything in the POST data array. After it runs I want to be able to use whatever variable I send in the POST data in the PHP code so I can query my database based on parameters sent. Do I need to reload the page somehow to do this? PHP: if(isset($_POST['boarder'])){ $boarder = $_POST['boarder']; function boarderCheck($boarder){ echo "<script type ='text/javascript'>alert('$boarder');</script>"; } boarderCheck($boarder); } else { ?> <script

Should I use “[FromBody]” values or custom params when responding to an HTTP Post call in a Web API app?

Deadly 提交于 2019-12-11 12:16:36
问题 Is POST the right HTTP method/verb to use for telling the server which criteria to use to retrieve data and then save it locally? I want to send an URL from a client (Windows Forms) app/util to my Web API app to tell it to retrieve data via a Stored Proc, then store the results in a local table. No data is returned to the caller, it's just a notification to do some work. To prepare for this, I added a new route to WebApiConfig: // Some reports (monthly) only need a begindate, such as "201509"

How to modify a request in Fiddler?

我的梦境 提交于 2019-12-03 01:37:38
问题 I'm looking for a simple way to intercept a web request and modify the contents of the request (mainly POSTs ) using Fiddler . This is to test server-side validation. I have to use Fiddler , however I haven't found a good simple way to do so. There have been several documented ways to write scripts to intercept traffic and change headers, but I would like to do it without writing a script - this tool needs to be used by the testers and writing/modifying scripts all the time by different

Invalid arguements in php

两盒软妹~` 提交于 2019-12-02 18:07:58
问题 When I run a script in Wamp I get the following Warning Notifications for line 17 and 21. What is this telling me and what can/should be done to resolve the issue ? Warning: Invalid argument supplied for foreach() in C:\wamp\www\eCardScript\ecard_lib.php on line 17 * Warning: * Invalid argument supplied for foreach() in C:\wamp\www\eCardScript\ecard_lib.php on line 21 <?php include('htmlMimeMail.php'); function getPostGetVars() { global $HTTP_POST_VARS,$HTTP_GET_VARS; foreach ($HTTP_POST_VARS

Invalid arguements in php

半世苍凉 提交于 2019-12-02 11:45:18
When I run a script in Wamp I get the following Warning Notifications for line 17 and 21. What is this telling me and what can/should be done to resolve the issue ? Warning: Invalid argument supplied for foreach() in C:\wamp\www\eCardScript\ecard_lib.php on line 17 * Warning: * Invalid argument supplied for foreach() in C:\wamp\www\eCardScript\ecard_lib.php on line 21 <?php include('htmlMimeMail.php'); function getPostGetVars() { global $HTTP_POST_VARS,$HTTP_GET_VARS; foreach ($HTTP_POST_VARS as $key => $value) { // This is Line 17 global $$key; $$key = $value; } foreach ($HTTP_GET_VARS as

AJAX POST - how to use a js variable in PHP

只愿长相守 提交于 2019-12-02 10:49:35
The first time the page loads, there will not be anything in the POST data array. After it runs I want to be able to use whatever variable I send in the POST data in the PHP code so I can query my database based on parameters sent. Do I need to reload the page somehow to do this? PHP: if(isset($_POST['boarder'])){ $boarder = $_POST['boarder']; function boarderCheck($boarder){ echo "<script type ='text/javascript'>alert('$boarder');</script>"; } boarderCheck($boarder); } else { ?> <script defer src="http://ajax.googleapis.com/ajax/libs/jquery/3.1.1/jquery.min.js"></script> <script src="map.js">