hibernate

问题 I have to modify design of the existing application according to following manner, According to above design each project contains it's own schema and that mapping table (project_schema_table) is under main schema. All schemas are under one Postgresql database and in future users will create another new schemas (on demand) for their new projects. Before displaying login window I have to list all existing projects and once user select his project I have to direct to that project with relevant

问题 As you can see I am using soft/logical deletion on my system: My entities: @Where(clause = "deleted='false'") public class Person { //... } My services: @Override public ServiceResponse DeletePerson (Person entity) { ServiceResponse sr = new ServiceResponse<>(); try { sr = ValidateDeletePerson(entity); //Business logic treatment if (sr.hasError()) return sr; Person dbEntity = GetPerson(entity.getPersonID()); dbEntity.setDeleted(true); _repository.save(dbEntity); } catch (Exception ex) { sr

问题 As you can see I am using soft/logical deletion on my system: My entities: @Where(clause = "deleted='false'") public class Person { //... } My services: @Override public ServiceResponse DeletePerson (Person entity) { ServiceResponse sr = new ServiceResponse<>(); try { sr = ValidateDeletePerson(entity); //Business logic treatment if (sr.hasError()) return sr; Person dbEntity = GetPerson(entity.getPersonID()); dbEntity.setDeleted(true); _repository.save(dbEntity); } catch (Exception ex) { sr

问题 What is the difference between filters and criteria in hibernate? criteria is used to filter the records by greater than,less than or equal etc.It is kind of filters.Can somebody show me what is difference by simple example 回答1: Short answer: A filter allows you to define a restriction clause similar to the existing "where" attribute available on the class and various collection elements. These filter conditions, however, can be parameterized. The application can then decide at runtime

问题 I am using the below Hibernate code to filter workFlowName . crt.add(Restrictions.like("workFlowName", workFlow, MatchMode.ANYWHERE)); // crt is the criteria The problem is when I pass the value to workFlow from web (TextBox).it fetching the value correctly (I am passing sym in text box if fetch 10 records.if i pass the same value like %sym% again it is fetching same record). Whether the criteria will omit when it see %% as argument? 回答1: Hibernate does not escape special chars in like (e.g.

问题 I have this entity class, called "Pagina" and I want to update the entry in the database based on the changes made to the entity. This isn't working. I get no errors, but the db is not changed. @Entity @Table(name = "PAGINA") @NamedQueries({@NamedQuery(name = "Pagina.findAll", query = "SELECT p FROM Pagina p"), @NamedQuery(name = "Pagina.findHashByURL", query= "SELECT p.chash FROM Pagina p WHERE p.url = :url"), @NamedQuery(name = "Pagina.findTimestampByURL", query= "SELECT p.timestamp FROM

问题 I have this entity class, called "Pagina" and I want to update the entry in the database based on the changes made to the entity. This isn't working. I get no errors, but the db is not changed. @Entity @Table(name = "PAGINA") @NamedQueries({@NamedQuery(name = "Pagina.findAll", query = "SELECT p FROM Pagina p"), @NamedQuery(name = "Pagina.findHashByURL", query= "SELECT p.chash FROM Pagina p WHERE p.url = :url"), @NamedQuery(name = "Pagina.findTimestampByURL", query= "SELECT p.timestamp FROM

问题 I'm struggling on transaction magement using DAO. The scenario is to create new quote that contains a list of quote_line and a customer. If the customer doesn't exist, it will insert it in the table customer. My code is architectures as follow : @Entity @Table(name = "quote") public class Quote { @Id @GeneratedValue(strategy = GenerationType.AUTO) private Long id; //....properties @ManyToOne(fetch = FetchType.EAGER) @JoinColumn(name = "customer_id", nullable = true) private Customer customer;

问题 My question can be trival, but documentation for hibernate-envers say I need just 2 steps to make hibernate envers work: the hibernate-envers jar on the classpath, an @Audited annotation on the entity. First of all I added: <dependency> <groupId>org.hibernate</groupId> <artifactId>hibernate-envers</artifactId> <version>5.2.12.Final</version> </dependency> Second I added @Audited annotation above my entity: @Entity @Audited @Table(name = "users") public class User {...} After those 2 steps I

问题 I would like to persist inner class into database. But it dosnt work. Is there possibilty to do that? Or should i put that inner class into new plain file? Now I am getting an error [IllegalArgumentException: Unknown entity: models.foo$bar] My class file: package models; public class foo { @Required public String report; @Required public String reportType; @Entity public static class bar{ @Required public int year; @Required public int month; public void toDataBase() { JPA.em().persist(this);