hibernate-entitymanager

Hibernate SessionFactory vs. EntityManagerFactory

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问题 I am new to Hibernate and am unclear of whether to use a SessionFactory or EntityManagerFactory to obtain the hibernate session. What is the difference between the two? Pros & Cons? 回答1: Prefer EntityManagerFactory and EntityManager . They are defined by the JPA standard. SessionFactory and Session are hibernate-specific. The EntityManager invokes the hibernate session under the hood. And if you need some specific features that are not available in the EntityManager , you can obtain the

How can i get the session object if i have the entitymanager

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问题 I have private EntityManager em; public List getAll(DetachedCriteria detachedCriteria) { return detachedCriteria.getExecutableCriteria( ??? ).list(); } How can i retrieve the session if am using entitymanager or how can i get the result from my detachedcriteria ? 回答1: To be totally exhaustive, things are different if you're using a JPA 1.0 or a JPA 2.0 implementation. JPA 1.0 With JPA 1.0, you'd have to use EntityManager#getDelegate(). But keep in mind that the result of this method is

How can i get the session object if i have the entitymanager

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Declared metamodel attributes work fine BUT Inherited Metamodel Attributes are NULL. Why?

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问题 I am not able to run the following test:- @Test public void test() { EntityManager em = entityManagerFactory.createEntityManager(); em.getTransaction().begin(); CriteriaBuilder builder = em.getCriteriaBuilder(); CriteriaQuery<Project> query = builder.createQuery(Project.class); Root<Project> project = query.from(Project.class); Path<String> name = project.get(Project_.name); Assert.assertNotNull(name); Path<EntityLifeCycleImpl> lifeCycle = project.get(Project_.lifeCycle); // problem is here,

Not able to wire entityManager with applicationContext bean

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问题 I am facing a problem to wire entity manager with the bean present in application context. whenever i do some operation it gives NullPointerException. this is my applicationContext.xml file <?xml version="1.0" encoding="UTF-8"?> <beans xmlns="http://www.springframework.org/schema/beans" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:context="http://www.springframework.org/schema/context" xmlns:tx="http://www.springframework.org/schema/tx" xsi:schemaLocation="http://www

Spring JPA repository Converter not found

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问题 I have an entity class UserModel.java @Entity @Table @Data @EqualsAndHashCode( of = { "id" } ) @ToString( of = { "id" } ) public class UserModel { @Id @GeneratedValue( strategy = GenerationType.AUTO ) @Column( name = "u_id" ) private Long id; @Column( name = "u_first_name" ) private String firstName; @Column( name = "u_last_name" ) private String lastName; @Column( name = "u_email_id" ) private String emailId; @Column( name = "u_password" ) private String password; @Column( name = "u_mobile

Usage of mule-module-jpa 1.2.0 with Hibernate in 3.4.0 CE. How to define EntityManager?

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问题 Could anyone point me to a working example of the mule-module-jpa suitable for Mule 3.4 CE? I have looked high and low and spent the better part of a day trying to get a test running and am stuck trying to get a properly defined entityManagerFactory set inside a mule app. I got excited when I saw the article here describing the modules features. http://blogs.mulesoft.org/getting-started-with-jpa-and-mule/ Unfortunately that article lacks any details about configuration of the module. I next

Different SQL using find and createQuery from Hibernate entity manager

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问题 I'm using Hibernate 3.3.0.GA and I noticed some strange behavior, not documented (I think). I noticed that entityManager.find resolve the EAGER relationships of my entity and entityManager.createQuery not. Per example, if I have an entity: @Entity public class Person { @Id private int id; private String name; @ManyToOne //EAGER by default in JPA private Address address; } The generated SQL with entityManager.find(Person.class, 1L) : select person0_.id as id1_1_, person0_.address_id as

Tune method in Controller. [PersistenceUnit: default] Unable to build Hibernate SessionFactory

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问题 how to realize the idea? Send me information: {"idBanner":2, "fullnameClient":"Aria"}. If click don't contain in database, then click save and send email businesscenter. Else, send a message: "you responsed". Error maybe version dependences? (Entity) : Click bind Banner, Banner bind Businesscentr. 回答1: Schema-validation: wrong column type encountered in column [id_bc] in table [banner]; found [int (Types#INTEGER)], but expecting [bigint (Types#BIGINT)] This is the problem which is causing

JPA with Hibernate 5: programmatically create EntityManagerFactory

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This question is specifically about programmatically creating a JPA EntityManagerFactory backed by Hibernate 5, meaning without configuration xml files and without using Spring . Also, this question is specifically about creating an EntityManagerFactory with a Hibernate Interceptor . I know how to create a Hibernate SessionFactory the way I want, but I do not want a Hibernate SessionFactory , I want a JPA EntityManagerFactory backed by a Hibernate SessionFactory . Given an EntityManagerFactory there is a way to obtain the underlying SessionFactory , but if what you have is a SessionFactory and