hibernate-5.x

问题 I am using Spring 4.3.0.RELEASE together with Hibernate 5.0.9.Final in my app and I keep getting java.lang.NoSuchMethodError: org.hibernate.engine.spi.SessionFactoryImplementor.getProperties()Ljava/util/Map; If I update the Hibernate 5.2.0.Final, everything works fine. It seems that Spring 4.3.0 is not compatible with Hibernate 5.0, is that correct ? I was not able to find anything about not supporting Hibernate 5.0. In Hibernate 5.2, such method exists, in Hibernate 5.0 the method doesn't

问题 I'm a little confused about SpringBoot's (1.3.0) support of Hibernate5. The reference lists a dependency on hibernate 4.3.11.Final but it also lists a dependency on SpringFramework 4.2.3 which includes Hibernate5 support. Is it just a matter of adding the extra Hibernate5 dependencies to override what Boot bundles? Can someone please clarify for me? 回答1: You can use either Hibernate 4.3 or Hibernate 5.0 with Spring Boot 1.3. As you've observed, Hibernate 4.3.x is the default version. To use

问题 I am writing application using postgresql database and spring + hibernate frameworks. I upgraded spring framework from 4.1.5.RELEASE to 4.2.0.RELEASE version and upgraded hibernate framework from 4.3.7.Final to 5.0.0.Final version. After upgrade I have problems with NamingStrategy. In postgresql database, table column names are in lowercase separated by underscore, in application layer, bean properties are in camelcase. This is working spring configuration file for older version: <?xml

问题 I have simple spring-jpa configuration where I have configured Hibernate's ImprovedNamingStrategy . This means if my entity class has a variable userName , then Hibernate should convert it to user_name for querying the database. But this naming conversion stopped working after I upgraded to Hibernate 5. I am getting the error: ERROR: Unknown column 'user0_.userName' in 'field list' This is my Hibernate config: @Configuration @EnableJpaRepositories("com.springJpa.repository")

问题 I'm trying to create a very simple Jersey REST webservice project with Hibernate 5. The problem is that when I debloy the WAR-file to JBoss EAP 6.4, I'm getting following exception: "The exception contained within MappableContainerException could not be mapped to a response, re-throwing to the HTTP container: java.lang.NoSuchMethodError: org.hibernate.internal.CoreMessageLogger.debugf(Ljava/lang/String;I)V" When running the project as a Java Application on Eclipse, Hibernate works perfectly.

问题 For my new project I plan to use Hibernate 5 and Spring 4 and as always like to separate into different layers / projects. Gradle dependencies: "org.springframework:spring-webmvc:4.2.1.RELEASE", "org.springframework:spring-orm:4.2.1.RELEASE", 'org.hibernate:hibernate-core:5.0.2.Final', 'mysql:mysql-connector-java:5.1.36' There is an API project, that contains a User.class. From my opinion this user class must not use any annotations for a database layer. It must not specify @Table(name =

问题 Aftre migrate my application from hibernate 4 to hibernate 5 .my sequence dose not work and hibernate use our default sequence instead of my sequence .my mapping config in hbm like this my database is oracle . <id name="id" column="Id" type="java.lang.Long"> <generator class="sequence" > <param name="sequence">SEQ_APP_Login_Log</param> </generator> </id> after google some people say change class to org.hibernate.id.enhanced.SequenceStyleGenerator but dose not work again. 回答1: It's simple. The

问题 I'm using Hibernate 5.0.2.Final with a Data-Source connection (On a Tomcat 8.0.15) and started to ask myself if it's necessary to not only close the Session but also the SessionFactory? Right now it looks like this: public static List<HibernateList> getHibernateList() { Session session = null; final String hql = "SELECT H FROM myhibernate.MyHibernate"; try { SessionFactory factory = HibernateUtil.getSessionFactory(); session = factory.openSession(); session.beginTransaction(); Query query =

问题 Hibernate version: 5.2 I am trying to use subqueries to do, and use setMaxResults(int). session.createQuery( "FROM ( SELECT * FROM tickets ORDER BY id DESC limit 3) sub ORDER BY id ASC" ); However, HQL subqueries can occur only in the select or where clauses, and limit can't be used in hibernate. How can I do it in hibernate? Update - To make it clear For eg, there are 10 data entries from id=1 to id=10. I want to select last 3 data in ascending order of id by only one query + without further

问题 I have the class Person mapped with annotations with enum Sex reffering to the sex if is male or female. Let's see: @Entity @Table(name = "PERSON") public class Person { @Id @GeneratedValue(strategy = GenerationType.IDENTITY) private int id; @Enumerated(EnumType.STRING) @Column(name = "SEX") private Sex sex; private enum Sex { M, F; } // Getters, setters & constructors } When I test getting all the rows from the MySQL database, it works and the mapping is correct. The database is already