getopts

问题 while getopts \"hd:R:\" arg; do case $arg in h) echo \"usgae\" ;; d) dir=$OPTARG ;; R) if [[ $OPTARG =~ ^[0-9]+$ ]];then level=$OPTARG else level=1 fi ;; \\?) echo \"WRONG\" >&2 ;; esac done level refers to parameter of -R , dir refers to parameters of -d when I input ./count.sh -R 1 -d test/ it works rightly when I input ./count.sh -d test/ -R 1 it works rightly but I want to make it work when I input ./count.sh -d test/ -R or ./count.sh -R -d test/ This means that I want -R has a default

问题 Why does this option only work the first time it\'s used, then ignored every other time? It\'s like it\'s being reset when the option is not used. Here\'s my function: testopts() { local var=\"o false\" while getopts \"o\" option; do case \"${option}\" in o) var=\"o true\" ;; esac done echo $var } When running it, it only returns true when passing the option for the first time. $ testopts o false $ testopts -o o true $ testopts -o o false 回答1: You need to add this line at top of your function

问题 I\'d like to use getopts inside a function that I have defined in my .bash_profile. The idea is I\'d like to pass in some flags to this function to alter its behavior. Here\'s the code: function t() { echo $* getopts \"a:\" OPTION echo $OPTION echo $OPTARG } When I invoke it like this: t -a bc I get this output: -a bc ? What\'s wrong? I\'d like to get the value bc without manually shifting and parsing. How do I use getopts correctly inside a function? EDIT: corrected my code snippet to try

问题 Say, I have a script that gets called with this line: ./myscript -vfd ./foo/bar/someFile -o /fizz/someOtherFile or this one: ./myscript -v -f -d -o /fizz/someOtherFile ./foo/bar/someFile What\'s the accepted way of parsing this such that in each case (or some combination of the two) $v , $f , and $d will all be set to true and $outFile will be equal to /fizz/someOtherFile ? 回答1: Update: It's been more than 5 years since I started this answer. Thank you for LOTS of great edits/comments

问题 I wish to have long and short forms of command line options invoked using my shell script. I know that getopts can be used, but like in Perl, I have not been able to do the same with shell. Any ideas on how this can be done, so that I can use options like: ./shell.sh --copyfile abc.pl /tmp/ ./shell.sh -c abc.pl /tmp/ In the above, both the commands mean the same thing to my shell, but using getopts , I have not been able to implement these? 回答1: There are three implementations that may be