getopt-long

#include <iostream> #include <getopt.h> #define no_argument 0 #define required_argument 1 #define optional_argument 2 int main(int argc, char * argv[]) { std::cout << "Hello" << std::endl; const struct option longopts[] = { {"version", no_argument, 0, 'v'}, {"help", no_argument, 0, 'h'}, {"stuff", required_argument, 0, 's'}, {0,0,0,0}, }; int index; int iarg=0; //turn off getopt error message opterr=1; while(iarg != -1) { iarg = getopt_long(argc, argv, "svh", longopts, &index); switch (iarg) { case 'h': std::cout << "You hit help" << std::endl; break; case 'v': std::cout << "You hit version" <

I'm making a perl script which uses Getopt::Long to parse command line arguments. However, I have an argument which can accept a string (with spaces). How can I get the whole string into a variable. For example: ./script.pl --string=blah blah blah blah yup --another-opt I need "blah blah blah blah yup" in variable $string. I know Getopt::Long supports multiple inputs for one argument when you know how many you will have (which I do not). Is this possible? You need to either put quotes around the argument: ./script.pl --string="blah blah blah blah yup" --another-opt or escape the spaces: .

I'm making a small program in C that deals with a lot of command line arguments, so I decided to use getopt to sort them for me. However, I want two non-option arguments (source and destination files) to be mandatory, so you have to have them as arguments while calling the program, even if there's no flags or other arguments. Here's a simplified version of what I have to handle the arguments with flags: while ((c = getopt(argc, argv, "i:d:btw:h:s:")) != -1) { switch (c) { case 'i': { i = (int)atol(optarg); } case 'd': { d = (int)atol(optarg); } case 'b': buf = 1; break; case 't': time = 1;

If I have a command line like: my_script.pl -foo -WHATEVER My script knows about --foo , and I want Getopt to set variable $opt_foo , but I don't know anything about -WHATEVER . How can I tell Getopt to parse out the options that I've told it about, and then get the rest of the arguments in a string variable or a list? An example: use strict; use warnings; use Getopt::Long; my $foo; GetOptions('foo' => \$foo); print 'remaining options: ', @ARGV; Then, issuing perl getopttest.pl -foo -WHATEVER gives Unknown option: whatever remaining options: You need to configure "pass_through" option via

This question already has an answer here: Using getopts to process long and short command line options 32 answers I want to support both short and long options in bash scripts, so one can: $ foo -ax --long-key val -b -y SOME FILE NAMES is it possible? Brian Clements getopt supports long options. http://man7.org/linux/man-pages/man1/getopt.1.html Here is an example using your arguments: #!/bin/bash OPTS=`getopt -o axby -l long-key: -- "$@"` if [ $? != 0 ] then exit 1 fi eval set -- "$OPTS" while true ; do case "$1" in -a) echo "Got a"; shift;; -b) echo "Got b"; shift;; -x) echo "Got x"; shift;;