function

问题 I made a variable and added new values with the push attribute but when the for-loop calls it one-by-one it only prints the last value(name) that is "Pranav". Can you help me to know how to fix it and print all the values one-by-one. function tryme() { var names = new Array(); names.push("Bhavesh", "Ajay", "Rahul", "Vinod", "Bobby", "Pranav"); var tryit = document.getElementById("tryit"); for (i = 0; i < names.length; i++) { tryit.innerHTML = "The values are " + names[i] + " . <br>" }; }; 回答1

问题 I need to write a function that will count the number of working days (minus weekends, and a vector of other local bank holidays), but the problem I'm coming up against is more simply illustrated with just counting the number of weekdays. Here is a function that will give the number of weekdays between two dates: removeWeekends <- function(end, start){ range <- as.Date(start:end, "1970-01-01") range<- range[sapply(range, function(x){ if(!chron::is.weekend(x)){ return(TRUE) }else{ return(FALSE

问题 I am using the R programming language. I used the "rpart" library and fit a decision tree using some data: #from a previous question : https://stackoverflow.com/questions/65678552/r-changing-plot-sizes library(rpart) car.test.frame$Reliability = as.factor(car.test.frame$Reliability) z.auto <- rpart(Reliability ~ ., car.test.frame) plot(z.auto) text(z.auto, use.n=TRUE, xpd=TRUE, cex=.8) This is good, but I am looking for an easier way to summarize the results of this tree in case the tree

问题 I am using the R programming language. I used the "rpart" library and fit a decision tree using some data: #from a previous question : https://stackoverflow.com/questions/65678552/r-changing-plot-sizes library(rpart) car.test.frame$Reliability = as.factor(car.test.frame$Reliability) z.auto <- rpart(Reliability ~ ., car.test.frame) plot(z.auto) text(z.auto, use.n=TRUE, xpd=TRUE, cex=.8) This is good, but I am looking for an easier way to summarize the results of this tree in case the tree

问题 I am using the R programming language. I used the "rpart" library and fit a decision tree using some data: #from a previous question : https://stackoverflow.com/questions/65678552/r-changing-plot-sizes library(rpart) car.test.frame$Reliability = as.factor(car.test.frame$Reliability) z.auto <- rpart(Reliability ~ ., car.test.frame) plot(z.auto) text(z.auto, use.n=TRUE, xpd=TRUE, cex=.8) This is good, but I am looking for an easier way to summarize the results of this tree in case the tree

问题 I am using the R programming language. I used the "rpart" library and fit a decision tree using some data: #from a previous question : https://stackoverflow.com/questions/65678552/r-changing-plot-sizes library(rpart) car.test.frame$Reliability = as.factor(car.test.frame$Reliability) z.auto <- rpart(Reliability ~ ., car.test.frame) plot(z.auto) text(z.auto, use.n=TRUE, xpd=TRUE, cex=.8) This is good, but I am looking for an easier way to summarize the results of this tree in case the tree

问题 How does a function know that something is a callback; something that needs to be executed once certain prior I/O has completed. How does it know that it shouldn't execute right away? Is it defined in a function in a (standardized) way? As far as I know the 'callback' keyword that is often used in an argument is just common practise, but does not automatically let the function interpret the argument as something that should start once certain I/O has completed. Taking the below example, I

问题 I am new to r and I wanted to aggregate the following matrix k n m s 1 g 10 11.8 2.4 2 g 20 15.3 3.2 3 g 15 8.4 4.1 4 r 14 3.0 5.0 5 r 16 6.0 7.0 6 r 5 8.0 15.0 results : k n s m 1 g 15 3.233333 7.31667 2 r 11.66667 9 4.16667 This was my attempt : k <- c("g", "g", "g", "r","r","r") n <- c(10,20,15,14,16,5) m <- c(11.8, 15.3, 8.4,3,6,8) s <- c(2.4, 3.2, 4.1,5,7,15) data1 <- data.frame(k,n,m,s) data2 <- aggregate(m ~ k, FUN = function(t) ********* , data=data1) I am more interested in m here is

问题 I would like to write a function that creates a binning variable based on some raw data. Specifically, I have a dateset with the age values for each respondent and I would like to write a function that classifies that person into an age group, where the age group is a parameter of that function. This is what I started with: data <- data.frame(age = 18:100) foo <- function(data, brackets = list(18:24, 25:34, 35:59)) { require(tidyverse) tmp <- data %>% drop_na(age) %>% mutate(age_bracket =

问题 This question already has answers here : warning: return type defaults to ‘int’ [-Wreturn-type] (3 answers) Closed 5 years ago . #include <stdio.h> int w=7,v=0; shortf(short a, short *b) { a++;(*b)++;w++;v++; printf("13: %d %d %d",a,v,w); return a; } int main() { return 0; } This is part of my code. It was given to me by a teacher in my University, but when I write it I get 10+ warnings and errors, this is one of them. I get a " return type defaults to 'int' " warning for Line 4. Why? Note: I