function-pointers

问题 This question already has answers here : How does dereferencing of a function pointer happen? (5 answers) Closed last month . According to the GNU C manual, functions can be called using function pointers like so: func (j); /* (*func) (j); would be equivalent. */ So my reasoning here is: func itself is a pointer to the func(int) function. When you call func(j) , you are implicitly accessing the value of the pointer func (you are moving to the memory location where func is), in the same way as

问题 I'm struggling with mapping addresses to their symbols for debugging purposes (getting the callstack). The MS dbghelp.dll can tell the symbol from an address (see SymFromAddr , MSDN). However, it doesn't work and I wonder how this could ever work, because addresses seem to change with every run of the program: #include <iostream> void Foo() {} int _tmain(int argc, _TCHAR* argv[]) { const long unsigned int addr = reinterpret_cast<long unsigned int>(&Foo); std::cout << "Address: " << std::hex <

来源： https://stackoverflow.com/questions/64502926/how-to-add-standard-routine-to-every-function-in-array-of-function-pointers

来源： https://stackoverflow.com/questions/64502926/how-to-add-standard-routine-to-every-function-in-array-of-function-pointers

来源： https://stackoverflow.com/questions/64438613/whats-the-practical-difference-between-fn-item-and-fn-pointer

来源： https://stackoverflow.com/questions/60547115/how-to-store-stdsqrt-in-stdfunction

问题 While following some tutorials and reading about function pointers I learned that evidently assigning a void pointer to a function pointer in ISO C is undefined, is there any way to resolve the warning I receive during compile time (e.g. a better way of coding it) or should I just ignore it? Warning: ISO C forbids assignment between function pointer and 'void *' [-pedantic] Example Code: void *(*funcPtr)(); funcPtr = GetPointer(); GetPointer is a function that returns a void pointer E.G. void

问题 While following some tutorials and reading about function pointers I learned that evidently assigning a void pointer to a function pointer in ISO C is undefined, is there any way to resolve the warning I receive during compile time (e.g. a better way of coding it) or should I just ignore it? Warning: ISO C forbids assignment between function pointer and 'void *' [-pedantic] Example Code: void *(*funcPtr)(); funcPtr = GetPointer(); GetPointer is a function that returns a void pointer E.G. void

问题 I'm doing a parsser for a class call virtual_machine, I'm trying to build a vectors of function for it, but some of those function on vm takes arguments (different numbers/types of arguments) can i still put those in my vector of fuction since they where only void (*f)(); here's the code class Virtual_Machine { public: /***/ void clear(); void pop(); void clear(); void assert(std::string const &value); void push(eOperandType const &e, std::string const &str); /***/ } class Parser { public: /*

问题 I am trying to replace an existing function pointer in a shared library with a callback defined in Python, through ctypes. The source of the shared library in C: #include <assert.h> #include <stdio.h> void (*plot)(); int c_main(int argc, void** argv) { printf("plot is %p\n", (void*)plot); assert(plot != NULL); plot(); return 0; } The source of the Python script: from sys import platform from pathlib import Path import ctypes import _ctypes FUNCTYPE = ctypes.WINFUNCTYPE if platform == 'win32'