fortify-source

Below is my code, both the vulnerable program (stack.c) and my exploit (exploit.c). This code works on a pre-packaged Ubuntu 9 that the prof sent out for windows users (I had a friend test it on his computer), but on Ubuntu 12 that I run on my iMac, i get segfaults when I try and do this in a normal user. here's stack: //stack.c #include <stdio.h> int bof(char *str) { char buffer[12]; //BO Vulnerability strcpy(buffer,str); return 1; } int main(int argc, char* argv[]) { char str[517]; FILE *badfile; badfile = fopen("badfile","r"); fread(str, sizeof(char),517, badfile); bof(str); printf(

I want to run a Fortify scan against a Maven Eclipse project. Where should I start? I understand that I need to update my pom.xml file to include the Fortify plugin however do I also require to have Fortify SCA installed on my machine? (I'm running MacOS X). I have been trying to find a place to download Fortify SCA but have not been able find it. I would appreciate it if someone could share some links to point me in the right direction in getting the setup complete. I don't think the Fortify installation is required, but it's pretty hard to get the maven sca plugin without it. If you install

I'm trying to learn about stack base overflow and write a simple code to exploit stack. But somehow it doesn't work at all but showing only Abort trap on my machine (mac os leopard) I guess Mac os treats overflow differently, it won't allow me to overwrite memory through c code. for example, strcpy(buffer, input) // lets say char buffer[6] but input is 7 bytes on Linux machine, this code successfully overwrite next stack, but prevented on mac os (Abort trap) Anyone know how to perform a simple stack-base overflow on mac machine? include int main(int argc, char **argv) { char buffer[4]; puts(

{ char buf[8]; sprintf(buf,"AAAA%3s","XXXXXXXX"); printf("%s\n",buf); } what will happen? The buffer have 8 characters space and only 3 free characters left, however, "XXXXXXXX" is 8 characters long. I take a test with Visual Studion 2008 on Windows 7. As a result, the program printed:AAAXXXXXXX, and a run-time error happened. It makes a lot of sense to consider what happens in your and, more importantly, similar, cases. As other posters have noted, it invokes UB. That's probably true. However, the world does not stop simply because someone did not define what exactly should happen next. And

I have a small C program to be exploited. And I also understood the logic behind the attack to be performed. However, as much as I try, it is just not working for me. #include <stdio.h> #include <stdlib.h> #define SECRET1 0x44 #define SECRET2 0x55 int main(int argc, char *argv[]) { char user_input[100]; int *secret; int int_input; int a, b, c, d; /* other variables, not used here.*/ /* The secret value is stored on the heap */ secret = (int *) malloc(2*sizeof(int)); /* getting the secret */ secret[0] = SECRET1; secret[1] = SECRET2; printf("Please enter a decimal integer\n"); scanf("%d", &int