form-editing | 易学教程

JQGrid Edit Form Closing When Click Off Form

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问题 hopefully this is a simple question. In the JQGrid form edit mode, the edit form pops up in the middle of the screen for editing. When I click off of the form, like on the background area, the form closes like I clicked "cancel". I know I can use the "onClose" event to catch this, but I am wondering how I tell the grid not to close unless you click the "cancel" button. I want the editing form to stay there if you click off the form, just close if you click cancel. I guess I am being a bit

jqgrid Form editing : questions about actions after deleting a row

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问题 After long searches, I succeed to delete a row in a jqgrid with form editing. But, there are two little things left : How to reload the grid with the row deleted ? If the row can't be deleted, how to display the information and the reason why ? I tried to search in the arguments passed to the function in the event "afterSubmit", but there is no real explanations about how to manipulate these arguments. The creation of the grid : tableToGrid("#TabUser", { caption: 'Gestion des Utilisateurs',

Using $dirty in angularjs in order to check whenever a form is being edited

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问题 I was trying to check whenever my form is being edited by writing some fields of it. I read $dirty should work for that task but I can't figure out what I'm missing here: <!DOCTYPE html> <html lang="en"> <script src= "http://ajax.googleapis.com/ajax/libs/angularjs/1.3.14/angular.min.js"></script> <body> <div ng-app="myApp" ng-controller="formCtrl"> <form name = "myForm" novalidate> First Name:<br> <input type="text" ng-model="user.firstName"><br> Last Name:<br> <input type="text" ng-model=

jqGrid: Form edits saved to row but all changes lost when paging back or forth

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问题 I am using form editing for local data. I am able to edit the values in the form and set the values back to the row (using setRowData). But when I page back or forth, the changes are lost. How do I save the changes to the row and the underlying source in the grid? Later I have to iterate the rows, validate all the errors are corrected (using the edit form), and post it to server. Code: var gridId = 'mygrid'; var pagerId = 'mygridpager'; var grid = $('#mygrid'); var pager = $('#mygridpager');

Using $dirty in angularjs in order to check whenever a form is being edited

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I was trying to check whenever my form is being edited by writing some fields of it. I read $dirty should work for that task but I can't figure out what I'm missing here: <!DOCTYPE html> <html lang="en"> <script src= "http://ajax.googleapis.com/ajax/libs/angularjs/1.3.14/angular.min.js"></script> <body> <div ng-app="myApp" ng-controller="formCtrl"> <form name = "myForm" novalidate> First Name:<br> <input type="text" ng-model="user.firstName"><br> Last Name:<br> <input type="text" ng-model="user.lastName"> <br><br> <button ng-click="reset()">RESET</button> </form> <p> is Form dirty? {{isDirty}}

jqGrid - How to modify form_editing construction?

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In the jqGrid documentation to form_editing, I see how the form_editing is constructed. <form ...> <table> <tr id='tr_myfield'> <td> Caption</td> <td>edited element named, in colModel, as "myfield"</td> </tr> ... </table> </form> Can I change this construction ? It's necessary to me because I have too many columns to edit in my form and I want to display the form in most userfriendly way. E.g when I have twenty columns to edit in my table. I have twenty rows in my form. But I would obtain one row for two columns. I understood that each rows are identifying by their index, so I can't just have

jqGrid - How to modify form_editing construction?

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问题 In the jqGrid documentation to form_editing, I see how the form_editing is constructed. <form ...> <table> <tr id=\'tr_myfield\'> <td> Caption</td> <td>edited element named, in colModel, as \"myfield\"</td> </tr> ... </table> </form> Can I change this construction ? It\'s necessary to me because I have too many columns to edit in my form and I want to display the form in most userfriendly way. E.g when I have twenty columns to edit in my table. I have twenty rows in my form. But I would

Adding new row to jqGrid using modal form on client only

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问题 There appear to be many solutions that are very close to addressing my problem but of the dozens and dozens of questions I\'ve poured through not one seems to exactly address what I\'m trying to do. Although I have seen nearly the same question asked without an answer. I have tried so many combinations of options and functions to no avail. I want to use the modal form to add a new row with the inputted values to the jqGrid but I do not want it to post to the server upon Submit. I do want to