floating-point-exceptions

“Floating-point invalid operation” when inputting float to a stringstream

由 限于喜欢 提交于 2019-12-24 01:24:19
问题 I have a simple piece of code that extracts a float from a FORTRAN-generated REAL array, and then inserts it into a stream for logging. Although this works for the first 30 cases, on the 31st it crashes with a "Floating-point invalid operation". The code is: int FunctionDeclaration(float* mrSwap) { ... float swap_float; stringstream message_stream; ... swap_float = *(mrSwap+30-1); ... message_stream.clear(); message_stream << 30 << "\t" << swap_float << "\tblah blah blah \t"; When debugging,

Do doubles suffer from overflow?

由 帅比萌擦擦* 提交于 2019-12-23 16:52:16
问题 Is it possible to have an overflow (wrap around) with a double or a float? What will happen if the maximum (or minimum) value is reached on x86 or x64 hardware? 回答1: On an IEEE-754 compliant system, overflow results in a special "infinity" (or "minus infinity") value, beyond which any further increment will have no effect. 回答2: No. Floats go to Inf or -Inf 来源： https://stackoverflow.com/questions/10239741/do-doubles-suffer-from-overflow

what languages expose IEEE 754 traps to the developer?

由 谁说胖子不能爱 提交于 2019-12-21 04:05:13
问题 I'd like to play with those traps for educational purpose. A common problem with the default behavior in numerical calculus is that we "miss" the Nan (or +-inf) that appeared in a wrong operation. Default behavior is propagation through the computation, but some operation (like comparisons) break the chain and loose the Nan, and the rest of the treatment continue without acknowledging the singularity in previous steps of the algorithm. Sometimes we have ways to react to this kind of event :

When does underflow occur?

由 谁说胖子不能爱 提交于 2019-12-17 19:21:00
问题 I get into a situation where calculating 1.77e-308/10 triggers an underflow exception, but calculating 1.777e-308/10 does not. This is strange because: Underflow occurs when the true result of a floating point operation is smaller in magnitude (that is, closer to zero) than the smallest value representable as a normal floating point number in the target datatype (from Arithmetic Underflow, Wikipedia) In other words, if we calculate x/y where both x and y are double , then underflow should

What leads to the floating point exception “1.#IO”

由 ≯℡__Kan透↙ 提交于 2019-12-13 02:36:46
问题 I'm debugging a simulation with many calculations in many Fortran files. I am used to seeing some floating point exceptions (-1.#QNB or 1.#QNAN) for errors that involve division by zero or operations that exceed the maximum size for floating point number. I'm assuming -1.#IO means invalid operation, but I'm not sure mathematically what would cause this and not QNB or QNAN or QINF. What would lead to the exception -1.#IO? 回答1: According to the IEEE 754 Standard for Floating Point Operations,

Questions on “forrtl: error (65): floating invalid”

由 女生的网名这么多〃 提交于 2019-12-11 12:02:15
问题 I've been running a huge Fortran code with Intel compiler version 13.1.3.192 under the debug mode (with -O0 -g -traceback -fpe3 flags being turned on). It gave me the following output message: ... ... forrtl: warning (402): fort: (1): In call to MPI_ALLGATHER, an array temporary was created for argument #1 forrtl: error (65): floating invalid Image PC Routine Line Source arts 00000000016521D9 pentadiagonal_ser 385 pentadiagonal.f90 arts 0000000001644862 pentadiagonal_ 62 pentadiagonal.f90

x86 Assembly: Division Floating Point Exception dividing by 11

由 让人想犯罪 __ 提交于 2019-12-11 06:46:20
问题 I'm trying to divide 859091 by 11 to obtain the quotient and the remainder, but I'm getting Floating Point Exception on line: div bx This is my code for SASM : %include "io.inc" section .data dividend dd 859091 divisor dw 11 section .text global CMAIN CMAIN: push ebp mov ebp, esp xor eax, eax xor ebx, ebx xor edx, edx mov ax, word [dividend] mov dx, word [dividend + 2] mov bx, word [divisor] test bx, bx jz exit div bx exit: leave ret 回答1: You're getting divide overflow because the quotient

Delphi XE2, TWebBrowser, float divide by zero

由 拟墨画扇 提交于 2019-12-04 03:54:08
问题 In Delphi 2010 and Delphi 2007 I am using Set8087CW on WebBrowserBeforeNavigate / WebBrowserDocumentComplete to prevent FPU errors inside ActiveX to cripple my application. But somehow this is not working in Delphi XE2, at least when in 64bit mode. When clicking links (any) I get "float divide by zero". (The initial loading of a website address or content into TWebBrowser works fine.) The callstack shows this to happen inside system32\D3D10Warp.dll (maybe used by IE9?) in response to

x86 Assembly: Division Floating Point Exception dividing by 11

由 梦想的初衷 提交于 2019-12-03 18:14:27
问题 I'm trying to divide 859091 by 11 to obtain the quotient and the remainder, but I'm getting Floating Point Exception on line: div bx This is my code for SASM : %include "io.inc" section .data dividend dd 859091 divisor dw 11 section .text global CMAIN CMAIN: push ebp mov ebp, esp xor eax, eax xor ebx, ebx xor edx, edx mov ax, word [dividend] mov dx, word [dividend + 2] mov bx, word [divisor] test bx, bx jz exit div bx exit: leave ret 回答1: You're getting divide overflow because the quotient

what languages expose IEEE 754 traps to the developer?

由 为君一笑 提交于 2019-12-03 12:41:19
I'd like to play with those traps for educational purpose. A common problem with the default behavior in numerical calculus is that we "miss" the Nan (or +-inf) that appeared in a wrong operation. Default behavior is propagation through the computation, but some operation (like comparisons) break the chain and loose the Nan, and the rest of the treatment continue without acknowledging the singularity in previous steps of the algorithm. Sometimes we have ways to react to this kind of event : prolongating a function ("0/0 = 12 in my case"), or in time-domain simulation throwing the step away and
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