filepath

问题 Given a fix path and a very limited directories from year. I'm trying to obtain each combination of path between this initial combination ( fixPath - year ) and the different, non-fixed and non-equally quantity , subdirectories contained in each combination of fixPath - year fixPath <- "C:/Users/calcazar/Desktop/example" year <- 2008:2010 pathVector <- paste(fixPath, year, sep = "/") pathVector [1] "C:/Users/calcazar/Desktop/example/2008" "C:/Users/calcazar/Desktop/example/2009" [3] "C:/Users

问题 Given a fix path and a very limited directories from year. I'm trying to obtain each combination of path between this initial combination ( fixPath - year ) and the different, non-fixed and non-equally quantity , subdirectories contained in each combination of fixPath - year fixPath <- "C:/Users/calcazar/Desktop/example" year <- 2008:2010 pathVector <- paste(fixPath, year, sep = "/") pathVector [1] "C:/Users/calcazar/Desktop/example/2008" "C:/Users/calcazar/Desktop/example/2009" [3] "C:/Users

问题 I would like to zip folder in my project from CMake . For that I use following code snippet: ADD_CUSTOM_COMMAND ( TARGET ${PROJECT_NAME} PRE_BUILD COMMAND ${CMAKE_COMMAND} ARGS -E tar cvf ${ZIP_OUT_DIR}/my_archive.zip --format=zip -- ${FOLDER_TO_ZIP}/another_folder/ ) The problem with this code is that the files after unzipping contain path component ( ../../my_file.txt in my case). I tried to use tar cvf -C ${FOLDER_TO_ZIP}/another_folder but unfortunatelly CMake doesn't accept this option.

问题 I am following a youtube tutorial on how to make an android (probably not but I can hope for compatability) and iOS game using LibGDX and I have encountered a problem accessing a .tmx file from my res folder. tileMap = new TmxMapLoader().load("res/level1.tmx"); using the above code I figured that the application would find my .tmx file in my res folder but I must be giving it incorrect information on how to find a file I have open in another tab. here is a screenshot of the search method

问题 I am following a youtube tutorial on how to make an android (probably not but I can hope for compatability) and iOS game using LibGDX and I have encountered a problem accessing a .tmx file from my res folder. tileMap = new TmxMapLoader().load("res/level1.tmx"); using the above code I figured that the application would find my .tmx file in my res folder but I must be giving it incorrect information on how to find a file I have open in another tab. here is a screenshot of the search method

问题 I am trying to read a file from my bundle. I know this has been asked before but I have read the other SO solutions and not of them seem to be of my situation. I have an XML file. I can see it in the project navigator: and I can also check that it is included in the bundle by going to Project/Build Phases/Copy Bundle Resource I've tried to get its path using the file manager with no luck, using inDirectory and not using inDirectory: let filePath = Bundle.main.path(forResource: "config",

问题 I am trying to read a file from my bundle. I know this has been asked before but I have read the other SO solutions and not of them seem to be of my situation. I have an XML file. I can see it in the project navigator: and I can also check that it is included in the bundle by going to Project/Build Phases/Copy Bundle Resource I've tried to get its path using the file manager with no luck, using inDirectory and not using inDirectory: let filePath = Bundle.main.path(forResource: "config",

问题 I have a Delphi application that uses ShellExecute to call a second Delphi Application on a button press. The applications are stored on the same server, on the same network share. Their paths are in the format: const JobManager = 'Z:\Apps\Application 1\Application1.exe'; FeeManager = 'Z:\Apps\Application 2\Application2.exe'; The call to ShellExecute is made as follows: rh := FindWindow(PChar('TMF'), PChar('Edit Job Details')); if rh = 0 then begin ShellExecute(Handle, 'open', JobManager, nil

问题 I find myself needing to get a parent directory of a python file in a source tree that is multiple directories up with some regularity. Having to call dirname many times is clunky. I looked around and was surprised to not find posts on this. The general scenario is: import os.path as op third_degree_parent = op.dirname(op.dirname(op.dirname(op.realpath(__file__)))) Is there a more idiomatic way to do this that doesn't require nested dirname calls? 回答1: Normalize a relative path; os.pardir is

问题 I find myself needing to get a parent directory of a python file in a source tree that is multiple directories up with some regularity. Having to call dirname many times is clunky. I looked around and was surprised to not find posts on this. The general scenario is: import os.path as op third_degree_parent = op.dirname(op.dirname(op.dirname(op.realpath(__file__)))) Is there a more idiomatic way to do this that doesn't require nested dirname calls? 回答1: Normalize a relative path; os.pardir is