filenames

问题 I’m getting the following error in VSCode in my Angular 6 application: ERROR in src/app/providers/dynamic-data/dynamic-data.service.ts(5,26): error TS1149: File name '/Users/gibranshah/repos/eva/EVA/src/app/model/endpoint.ts' differs from already included file name '/Users/gibranshah/repos/eva/EVA/src/app/model/Endpoint.ts' only in casing. It’s telling me that this line in dynamic-data.service.ts: import { Endpoint } from '../../model/endpoint'; …refers to a file whose name is Endpoint.ts.

问题 Im pretty new to zenity and bash. Im trying to make file selection window that will display only the ones with .ogg, .aac and .wav extension. I tried this, but it doesn't work. option=`zenity --file-selection --file-filter=*.ogg | *.aac` For one extension it's working as intented: option=`zenity --file-selection --file-filter=*.ogg` Zenity man provides information: --file-filter=NAME | PATTERN1 PATTERN2 Sets a filename filter I dont really understand how am I supposed to use it. Can someone

问题 How should I replace dots with underlines without losing the file extension? $str = $_FILES['files']['name']; //file.name.word.jpg $ext = end(explode('.', $str)); $filename = explode('.', $str); //output file_name_word.jpg ps: it needs to be before upload.. if the user uploads a file with dots it must to be renamed and inserted on db 回答1: Use pathinfo() to extract the file name and str_replace() to remove all the dots out of it. $filename = pathinfo('/path/to/your/file'); echo str_replace('.'

问题 I have 3 appenders in my config file for creating 3 different types of logs. I am using dynamic naming of file in each of the 3 appenders by setting the global context properties. In some cases, i need to set the log file name dynamically for just 1 appender. When i set the file name for just 1 appender, it creates another file named "null" with no data in addition to the actual logfile whose name has been set dynamically . I have created the config file as shown. <appender name=

问题 I use this line below for create my Bitmap: Bitmap b = new Bitmap(@"C:\<file name>"); After I modify this bitmap and I want to save it as in line below: b.Save(@"C:\\<other file name>") My question is - how to get the file name bitmap from property. Simply put, I need to save the bitmap with the same name with whom I had initiated it. Thanks 回答1: Perhaps you can do this with Metadata - but I'm not familiar with this subject so I'm not completely sure it's possible, nor do I how to do it. What

问题 I use this line below for create my Bitmap: Bitmap b = new Bitmap(@"C:\<file name>"); After I modify this bitmap and I want to save it as in line below: b.Save(@"C:\\<other file name>") My question is - how to get the file name bitmap from property. Simply put, I need to save the bitmap with the same name with whom I had initiated it. Thanks 回答1: Perhaps you can do this with Metadata - but I'm not familiar with this subject so I'm not completely sure it's possible, nor do I how to do it. What

问题 What is the best way to combine a path with a filename? That is, given c:\foo and bar.txt , I want c:\foo\bar.txt . Given c:\foo and ..\bar.txt , I want either an error or c:\foo\bar.txt (so I cannot use Path.Combine() directly). Similarly for c:\foo and bar/baz.txt , I want an error or c:\foo\baz.txt (not c:\foo\bar\baz.txt ). I realize, I could check that the filename does not contain '\' or '/', but is that enough? If not, what is the correct check? 回答1: If you want "bad" filenames to

问题 I want to add an index to a filename if the file already exists, so that I don't overwrite it. Like if I have a file myfile.txt and same time myfile.txt exists in destination folder - I need to copy my file with name myfile_1.txt And same time if I have a file myfile.txt , but destintation folder contains myfile.txt and myfile_1.txt - generated filename has to be myfile_2.txt So the functionality is very similar to the creation of folders in Microsoft operating systems. What's the best

问题 I want to add an index to a filename if the file already exists, so that I don't overwrite it. Like if I have a file myfile.txt and same time myfile.txt exists in destination folder - I need to copy my file with name myfile_1.txt And same time if I have a file myfile.txt , but destintation folder contains myfile.txt and myfile_1.txt - generated filename has to be myfile_2.txt So the functionality is very similar to the creation of folders in Microsoft operating systems. What's the best

问题 Is there a way to get the filename from a BufferedImage? I don't seem to see any methods for it. 回答1: A BufferedImage doesn't necessarily have to be backed by a file. It could be a byte array in a database, or even backed by a stream. 回答2: A BufferedImage is not necessarily associated with a file. Just as you can read a String from a file, but there is no getFilename() method on String objects, there is no such method on BufferedImage . 来源： https://stackoverflow.com/questions/4611303/getting