fgets

Why fgets is not inputting first value?

假如想象 提交于 2020-01-06 13:53:05
问题 I am writing a program to write my html files rapidly. And when I came to write the content of my page I got a problem. #include<stdio.h> int main() { int track; int question_no; printf("\nHow many questions?\t"); scanf("%d",&question_no); char question[question_no][100]; for(track=1;track<=question_no;track++) { printf("\n<div class=\"question\">%d. ",track); printf("\nQuestion number %d.\t",track); fgets(question[track-1],sizeof(question[track-1]),stdin); printf("\n\n\tQ%d. %s </div>",track

Segmentation Fault while trying to parse an excel style .CSV file [C programming]

一笑奈何 提交于 2020-01-06 08:16:51
问题 I've been stuck on this project for the better part of the week and while I have been grinding through syntax errors. The gist of the project is to read through the headers and stopping at a certain column and finding certain characteristics like the min, max and average of the column. However, I am having a tough time with memory allocation for this job. I have been unable to further my code so far because I keep getting an error labeled Segmentation Fault: 11 . The bolded section is what I

C fgets strtok and atoi to read a line in C

五迷三道 提交于 2020-01-06 06:40:46
问题 #include <stdio.h> #include <string.h> int main(void) { char string[10000],*token; int garden[100],i=0; fgets(string,10000,stdin); token = strtok(string," "); while(strcmp(token,"\n") != 0){ garden[i] = atoi(token); i++; token = strtok(NULL," "); } return 0; } What is wrong with this code ? Why can't I read space separated integers from a line ? 回答1: Change while(strcmp(token,"\n") != 0){ to while(token != NULL){ 回答2: Your code only works when there's a space after the final number. Otherwise

C fgets strtok and atoi to read a line in C

好久不见. 提交于 2020-01-06 06:40:23
问题 #include <stdio.h> #include <string.h> int main(void) { char string[10000],*token; int garden[100],i=0; fgets(string,10000,stdin); token = strtok(string," "); while(strcmp(token,"\n") != 0){ garden[i] = atoi(token); i++; token = strtok(NULL," "); } return 0; } What is wrong with this code ? Why can't I read space separated integers from a line ? 回答1: Change while(strcmp(token,"\n") != 0){ to while(token != NULL){ 回答2: Your code only works when there's a space after the final number. Otherwise

【PHP】文件写入和读取详解

自闭症网瘾萝莉.ら 提交于 2020-01-05 23:52:53
文章提纲: 一.实现文件读取和写入的基本思路 二.使用fopen方法打开文件 三.文件读取和文件写入操作 四.使用fclose方法关闭文件 五.文件指针的移动 六.Windows和UNIX下的回车和换行 一.实现文件读取和写入的基本思路: 1.通过fopen方法打开文件:$fp =fopen(/*参数,参数*/),fp为Resource类型 2.进行文件读取或者文件写入操作(这里使用的函数以1中返回的$fp作为参数) 3. 调用fclose($fp)关闭关闭文件 二:使用fopen方法打开文件 fopen(文件路径[string],打开模式[string]) <1>fopen的第一个参数为文件路径 写文件路径的方式:1绝对路径,2相对路径 1绝对路径: 在windows下工作的小伙伴们应该很熟悉,windows下的路径分隔符是“\”而不是“/”,但我们在写入路径时不能以钦定的“\”为分隔符 那如果我们以“\”分隔符写入路径会怎样呢? <?php $fp = fopen("C:\wamp64\www\text.txt",'w'); ?> 运行后报错,提示路径参数无效 所以我们要把分隔符“\”换成“/”: <?php $fp = fopen("C:/wamp64/www/text.txt",'w'); ?> 运行时无报错,说明参数是有效的。 【注意】fopen函数不能理解“\”分隔符

PHP:读写文件一些说明

 ̄綄美尐妖づ 提交于 2020-01-05 23:52:31
一,PHP如何读取文件 PHP读取文件可以读取当前服务器或远程服务器中的文件。其步骤是:打开文件、读文件和关闭文件。 1,PHP如何打开文件 使用PHP 函数fopen() 打开一个文件,fopen()一般使用2个参数表示打开文件的路径和文件模式。比如: $fp=fopen("../cnbruce.txt",'w'); 其中 "../cnbruce.txt" 就表示打开的cnbruce.txt文件的路径(相对当前执行程序文件的路径),'w'表示以只写的方式打开该文本文件。 附录:fopen()函数的文件模式总结 r 只读——读模式,打开文件,从文件头开始读 r+ 可读可写方式打开文件,从文件头开始读写 w 只写——写方式打开文件,同时把该文件内容清空,把文件指针指向文件开始处。如果该文件已经存在,将删除文件已有内容;如果该文件不存在,则建立该文件 w+ 可读可写方式打开文件,同时把该文件内容清空,把文件指针指向文件开始处。如果该文件不存在,则建立该文件 a 追加 以只写方式打开文件,把文件指针指向文件末尾处。如果该文件不存在,则建立该文件 a+ 追加 以可读可写方式打开文件,把文件指针指向文件末尾处。如果该文件不存在,则建立该文件 b 二进制 用于于其他模式进行连接。建议使用该选项,以获得更大程度的可移植性 注意,如果fopen()函数调用失败,函数将返回false

How to clear input buffer after fgets overflow?

∥☆過路亽.° 提交于 2020-01-03 19:30:27
问题 I'm facing a little problem with fgets when the input string exceeds its predefined limit. Taking the example below: for(index = 0; index < max; index++) {printf(" Enter the %d string : ",index+1) if(fgets(input,MAXLEN,stdin)) { printf(" The string and size of the string is %s and %d \n",input,strlen(input) + 1); removeNewLine(input); if(strcmp(input,"end") != 0) { //Do something with input } } Now when I exceed the length MAXLEN and enter a string, I know that the input will append a '\0' at

Reading in a string with spaces in C

怎甘沉沦 提交于 2020-01-03 10:55:09
问题 I am trying to read in a string that may or may not include spaces ex. "hello world". By doing the following with a number select menu that is inputted by the user. This is just a small replica of what I am trying to do. #include <stdio.h> #include <string.h> int main(void){ char line[3][80]; strcpy(line[0],"default line 1\n"); strcpy(line[1],"default line 2\n"); strcpy(line[2],"default line 3\n"); for(int i = 0; i < 3; i++){ printf("%s", line[i]); } int option = 0; printf("would you like to

Removing newline from fgets [duplicate]

冷暖自知 提交于 2020-01-02 21:49:48
问题 This question already has answers here : Removing trailing newline character from fgets() input (12 answers) Closed 4 years ago . I am sorry if this question is obvious, or if I am making a simple logic mistake. I have searched for various ways of getting rid of the newline that comes from using fgets, but I continue running into problems while building. I think I am not understanding something properly and applying my "solution" incorrectly. I would like to be transparent and say that this

Code not reaching statements using fgets?

安稳与你 提交于 2020-01-02 08:38:00
问题 I have written code that uses the fgets function with multiple conditions that call other functions within the code, namely aMethod and bMethod. int main(void) { char buffer[1024]; while (fgets(buffer, 1024, stdin)) { if ((strcasecmp(buffer,"a")) == 0) { aMethod(); } if ((strcasecmp(buffer, "b")) == 0) { bMethod(); } } } I'm not sure why it doesn't reach the if statements. Any help would be great, thankyou. 回答1: If in doubt, print it out: int main(void) { char buffer[1024]; while (fgets