feedparser

问题 So I'm attempting to write a Django reusable app that provides a method for displaying your Twitter feed on your page. I know well that it already exists 20 times. It's an academic exercise. :) Directory structure is pretty simple: myproject |__ __init__.py |__ manage.py |__ settings.py |__ myapp |__ __init__.py |__ admin.py |__ conf |__ __init__.py |__ appsettings.py |__ feedparser.py |__ models.py |__ templates |__ __init__.py |__ templatetags |__ __init__.py |__ twitterfeed.py |__ views.py

问题 I'm learning Python. To teach myself I've decided to try to build a tool which gathers RSS feeds and stores the output, title, URL and Summary in a database (I will later build a tool to access the data and scrape the pages) So far, I have created a local version that gathers gathers content from a list of RSS feeds and puts it into a pandas dataframe. What I'm trying to understand next is, what tools do I need to turn this local script into a script that runs every, for example, 30 mins and

问题 This is follow up to the question from here bozo_exception in Django / feedparser I would like to iterate through many feeds from models/DB and have each of them displayed in the html template. While I do understand that I need to iterate thought x.feed.entries in the html template, I assume that iteration through each rss source needs to happen in the view function correct? def feed5(request): source = Feed.objects.all() for item in source.url: rss = feedparser.parse(item) context = {'rss':

问题 I'm learning Python. I've set myself a wee goal of building a RSS scraper. I'm trying to gather the Author, Link and Title. From there I want to write to a CSV. I'm encountering some problems. I've search for the answer since last night but can't seem to find a solution. I do have a feeling that is a bit of knowledge that I'm missing between what feedparser is parsing and moving it to a CSV but I don't have the vocabulary yet to know what to Google. How do I remove special characters such as

问题 I use feedparser http://www.feedparser.org/ to parse Atom feeds and I do some manipulation on the resulting Python objetcs. After that, I would like to serialize the objects back to Atom. But feedparser does not seem to offer a way to do so? I noticed other Atom libraries like gdata http://code.google.com/p/gdata-python-client/ or demokritos http://jtauber.com/demokritos/ but, to tell the truth, they seem very difficult for the beginner. I use feedparser precisely because of its extreme

问题 I am using feedparser in order to get RSS data. Here is my code : >>> import datetime >>> import time >>> import feedparser >>> d=feedparser.parse("http://.../rss.xml") >>> datetimee_rss = d.entries[0].published_parsed >>> datetimee_rss time.struct_time(tm_year=2015, tm_mon=5, tm_mday=8, tm_hour=16, tm_min=57, tm_sec=39, tm_wday=4, tm_yday=128, tm_isdst=0) >>> datetime.datetime.fromtimestamp(time.mktime(datetimee_rss)) datetime.datetime(2015, 5, 8, 17, 57, 39) In my timezone (FR), the actual

问题 I'm trying to use feedparser to retrieve some specific information from feeds, but also retrieve the raw XML of each entry (ie. elements for RSS and for Atom), and I can't see how to do that. Obviously I could parse the XML by hand, but that's not very elegant, would require separate support for RSS and Atom, and I imagine it could fall out of sync with feedparser for ill-formed feeds. Is there a better way? Thanks! 回答1: I'm the current developer of feedparser. Currently, one of the ways you

问题 I am parsing several documments with the field Duration . But in the differents files, it is in differnt formats, ex: "Duration": "00:43" "Duration": "113.046" "Duration": "21.55 s" I want to parse all of them to the format "Duration": "113.046" , how could I check before any parsing in wich format it is?? Some conditions before this piece of code, because this is not right for all of them: Long duration; DateFormat sdf = new SimpleDateFormat("hh:mm:ss"); try { Date durationD = sdf.parse

问题 I'm trying to parse RSS feeds from a url using feedparser in python. >>> import feedparser >>> d = feedparser.parse('http://www.shop.inonit.in/RSSFeedDetails.aspx?PID=801') >>> d {'feed': {'summary': u'<span><h1>Server Error in \'/mobile\' Application.<hr color="silver" size="1" width="100%" /></h1>\n\n <h2> <i>Attempted to divide by zero.</i> </h2></span>\n\n <font face="Arial, Helvetica, Geneva, SunSans-Regular, sans-serif ">\n\n <b> Description: </b>An unhandled exception occurred during

问题 Refer this blog: http://johnsmallman.wordpress.com/author/johnsmallman/feed/ I want to fetch the RSS feed for my application. The above blog is a wordpress blog. I am using feedparser import feedparser feeds = feedparser.parse('http://johnsmallman.wordpress.com/author/johnsmallman/feed/') Now feeds['feed']['title'] Outputs u"Johnsmallman's Blog \xbb John Smallman" My question is How exactly i present this in my app. Lets say this blog contains 100s of articles. So i want to loop over and