feed

Google Reader API - Getting Feeds

我怕爱的太早我们不能终老 提交于 2020-01-29 04:12:07
问题 Does anyone know if there is a Google Reader service call that a user can make to get the name/uri of all feeds that fall under a certain label/category? Thanks! 回答1: You can use a variation of the code below to get access to the Google Reader system. You need to send the header ("Authorization", "auth=" +myauthvar) with each request. In order to edit items you will need the token which I also demo below. Once you have the auth id you can post (with that header intact) to http://www.google

Embed Instagram feed to website sidebar [closed]

荒凉一梦 提交于 2020-01-23 02:11:27
问题 Closed . This question needs to be more focused. It is not currently accepting answers. Want to improve this question? Update the question so it focuses on one problem only by editing this post. Closed 9 months ago . i am trying to integrate Instagram feed of client to website sidebar . I googled and did some research .I didn't find direct way to integrate feeds . I went through third party app like Snapwidget . Its pretty good but problem with that is that when i click on the feed displayed

Letting user specify recipients within Feed Dialog

别说谁变了你拦得住时间么 提交于 2020-01-22 12:59:05
问题 Currently, our app posts to users' friends' walls via Graph API. However, Facebook is deprecating this functionality so we are migrating to the Feed Dialog per Facebook's recommendations (see the February 6, 2013 section at https://developers.facebook.com/roadmap/). Now, we know we can specify the recipient as part of the Javascript SDK call (note FB.init() is called elsewhere earlier on the page): <p><a onclick="launchFeedDialog(); return false">Testing the Feed Dialog</a></p> <script>

feed dialog: picture not showing up

旧城冷巷雨未停 提交于 2020-01-21 10:59:08
问题 My Facebook feed dialog link correctly renders a dialog page, but the image set with the picture parameter does not show up -- just the gray line that indicates no picture. I've changed picture files and types a few times, but the image still doesn't show up. Here is the code: $share_url = "https://www.facebook.com/dialog/feed?app_id=$app_id"; $share_url .= "&link=http://www.doozeez.com"; $share_url .= "&picture=http://doozeez.com/images/halloweenloot.png"; $share_url .= "&caption=to spend in

feed dialog: picture not showing up

懵懂的女人 提交于 2020-01-21 10:58:08
问题 My Facebook feed dialog link correctly renders a dialog page, but the image set with the picture parameter does not show up -- just the gray line that indicates no picture. I've changed picture files and types a few times, but the image still doesn't show up. Here is the code: $share_url = "https://www.facebook.com/dialog/feed?app_id=$app_id"; $share_url .= "&link=http://www.doozeez.com"; $share_url .= "&picture=http://doozeez.com/images/halloweenloot.png"; $share_url .= "&caption=to spend in

Validating an RSS feed

时光总嘲笑我的痴心妄想 提交于 2020-01-15 12:15:33
问题 I'm working on an application that allows users to add their own RSS feeds to a simple reader of sorts. Currently, I'm using xml_domit_rss as the parser but I'm unsure if it's actually validating the URL before parsing. From what I can gather online, it looks as if validating is separate from the parse, either by using a service https://www.feedvalidator.org or some other method such as parse_url() . Anyone have some insight into either how xml_domit_rss validates, or a method by which I can

How to combine the data for the same post together?

我与影子孤独终老i 提交于 2020-01-15 10:23:09
问题 I'm getting some posts data from 2 websites, One website has the title, the date, the description and the link, While the other has the title and the image. So I want to add the image to the other posts data if the titles from both websites are identical. Here is what I tried: $articles = []; //Getting Data From 1st Website $rss = simplexml_load_file($website1); foreach ($rss->channel->item as $item) { $post = []; $post['title'] = (string)$item->title; $post['link'] = (string)$item->link;

running a “join” like FQL for getting a user name along the news feed posts

自闭症网瘾萝莉.ら 提交于 2020-01-14 14:55:13
问题 I am trying to get all the posts in the news feed for a specific user using FQL using the following FQL statement: SELECT post_id, actor_id, target_id, message, created_time, updated_time, permalink, description FROM stream WHERE filter_key in (SELECT filter_key FROM stream_filter WHERE uid=me() AND type='newsfeed') AND is_hidden = 0 AND created_time > xxx But i need the user name (first and last names) of every user that made a post that appears in my news feed (the user name that is

Need read XML and show it and save on Local storage.

こ雲淡風輕ζ 提交于 2020-01-11 04:09:05
问题 I need to read XML data and show this in HTML and at the same time save it in localStorage. When the user is ofline I need show the content using localStorage. ( NOTE: without PHP) ( NOTE: when user have internet read and show new items ) Does anyone have a good tutorial or any helpful website? 回答1: I found this article/tutorial. It shows how to parse and save a xml file. And how you can query it offline. It is done by using javascript. Article is on mantascode.com by Mantascode and describes

Check if a URL is a valid Feed

谁说胖子不能爱 提交于 2020-01-11 02:39:45
问题 I'm using Argotic Syndication Framework for processing feeds. But the problem is, if I pass a URL to Argotic, which is not a valid feed (for example, http://stackoverflow.com which is a html page, not feed), the program hangs (I mean, Argotic stays in an infinity loop) So, How to check if a URL is pointing to a valid feed? 回答1: From .NET 3.5 you can do this below. It will throw an exception if it's not a valid feed. using System.Diagnostics; using System.ServiceModel.Syndication; using System