fadein

css/javascript start faded out by default, then fade in

百般思念 提交于 2021-01-28 06:20:56
问题 I'm trying to make a button that causes a green check image to fade in then fade out again. It mostly works, but how do I make the check start out in the faded out position when the page loads? I tried to put opacity: 0; in its css, assuming that the fadeIn function changes the opacity, but then it doesn't show up at all. function green_check(check) { //fade in half a sec, hold 2 sec, fade out in 3 sec $(check).fadeIn(500, function() { $(this).delay(2000).fadeOut(3000); }); } <script src=

CSS animation, FadeIn / FadeOut 2 images continuously

心不动则不痛 提交于 2020-05-24 05:32:26
问题 I have created sample CodePen here. I tried below but didn't work. .elementToFadeInAndOut { width:200px; height: 200px; background: red; -webkit-animation: fadeinout 4s linear forwards; animation: fadeinout 4s linear forwards; } @-webkit-keyframes fadeinout { 0%,100% { opacity: 0; } 50% { opacity: 1; } } @keyframes fadeinout { 0%,100% { opacity: 0; } 50% { opacity: 1; } } As you will see this sample has 3 images. I give them id = "imge1" , "imge2" , "imge3" img3 keeps rotating using keyframe.

jquery problem?

点点圈 提交于 2020-02-04 05:11:13
问题 i have this jquery problems i have had for days, im so new to this, so excuse my dumbness in this subject. thanks :)) html code: <ul class="statuses"> <li id="set_23" class="message"> // this is meant to increase everytime you click the vote_up just like stackoverflow <span class="vote_count">27</span> <a href="#" class="vote_up"><img src="img/uparrow.png" /></a> <a href="#" class="vote_down"><img src="img/downarrow.png" /></a> </li> </ul> this is my jquery code: $(document).ready(function()

replaceWith() while elements fadeOut() and fadeIn() in JQuery

二次信任 提交于 2020-01-16 01:04:10
问题 What I'm trying to do is simply, fadeout all images inside containers, replace #next1's image to #active and after that fadein all images again. here is my code: $('.logo').fadeOut('slow', function() { $('#active>img').replaceWith( $('#next1>img') ); }).fadeIn('slow', function() {}); this does not work. i found myself looking at the empty #active but this however; $('.logo').fadeOut('slow', function() {}).fadeIn('slow', function() {}); $('#active>img').replaceWith( $('#next1>img') ); makes

jQuery fadeOut one div, fadeIn another on its place

别说谁变了你拦得住时间么 提交于 2020-01-15 01:21:43
问题 I'm trying a simple jQuery script to fadeout one div and fadein another one in it's place but for some reason the first div never fades out. It's probably an obvious problem with the code but I cannot seem to make it out. <style> #cuerpo { display: none; } </style> <div id="cuerpo"></div> <div id="inicio"></div> <script> function delayed() { $("div").fadeIn(3000, function () { $("cuerpo").fadeIn("slow"); }); } $("a").click(function () { $("inicio").fadeOut("slow"); setTimeout("delayed()",500)

jQuery callback not waiting on fadeOut

这一生的挚爱 提交于 2020-01-13 09:50:10
问题 It seems to me the following code should produce these results: mademoiselle demoiselle mesdemoiselles Instead, as "ma" fades out, "mes" fades in making the sequence: mademoiselle madesdemoiselles mesdemoiselles The code: <span class="remove">ma</span><span class="add">mes</span>demoiselle<span class="add">s</span> $(document).ready(function() { $(".remove").fadeOut(4000,function(){ $(".add").fadeIn(5000); }); }); Edit: I found an empty span that if I remove makes the bug go away: <span class

Show div at top of page, hide when scrolling, then show div at bottom of page

不羁的心 提交于 2020-01-07 05:02:12
问题 When a user is at the top of a page, the div is shown. When they scroll down the page, the div is hidden until they reach the bottom of the page, whereby the div is shown again. The div would be a fixed navigation menu Below is some code posted by another member, which successfully shows the div at the bottom of the page, but always hides it at the top. Original post can be found here: How to show div when user reach bottom of the page? Thanks! <script> $(document).ready(function() { $(window

jQuery fadeOut is not changing display property

送分小仙女□ 提交于 2020-01-06 19:31:27
问题 On http://judi.simpleupdates.com/ I am attempting to make a slideshow of images on a page using the jQuery fadeIn and fadeOut effects. Both items fadeIn without issue. However, fadeOut is not changing the display property of the div that is supposed to disappear. Any ideas why this might not be working as expected? This is the line that is failing: $( ".carousel_item:nth-child(" + selected + ")" ).fadeOut(600); UPDATE: The issue seems to be with fadeOut on a element that does not have a width

iphone UIview animation resize in like disappear in water and comes back floating

放肆的年华 提交于 2020-01-06 14:57:48
问题 I don't want to fade in and fade out like most common solution for the uiview animation. I would like to have the uiview resize to small until it disappear and comes back the same way. Another way to say it is having a camera pointing closely at the table with all the object in it (UIView) and camera backs up and the more it backs up the smaller the table gets. Which is why i titled which is mainly my app the whole uiview sinks into the water and floats back up. Hopefully i'll find a tutorial