extends

Extend Activity and ActivityGroup

由 ℡╲_俬逩灬. 提交于 2019-12-10 12:35:19
问题 I'm writing an application in which i have a set of code which i want to be available in all of my Activities and ActivityGroups. However, to achieve this, I have extended my activities as: //custom Activity public abstract class BaseActivity extends Activity //custom ActivityGroup public abstract class BaseActivityGroup extends ActivityGroup //implemented activities in my app public class PickUser extends BaseActivity //and public class Home extends BaseActivityGroup Now the thing is,

How to extends Sonata\DoctrineORMAdminBundle\Model\ModelManager

由 陌路散爱 提交于 2019-12-10 10:37:41
问题 I want some changes in ModelMangaer then I was extending ModelManager but It's not working. I don't know why ? Any one tell me why it is not working? File where I extend Sonata\DoctrineORMAdminBundle\Model\ModelManager-> <?php use Sonata\DoctrineORMAdminBundle\Model\ModelManager; class ModelManager extends ModelManager { /** * {@inheritdoc} */ public function getSortParameters(FieldDescriptionInterface $fieldDescription, DatagridInterface $datagrid) { $values = $datagrid->getValues(); $values

declare parameter subtype in Java interface, use subtypes in Java implementing methods

由 偶尔善良 提交于 2019-12-10 10:18:03
问题 I want to declare a method in an interface where the parameter of the method defined in implementing classes can be a subtype of a specific java class for example: interface Processor{ processRequest( Request r); } public class SpecialRequest extends Request{...} public class SpecialProcessor implements Processor{ processRequest(SpecialRequest r){...} } but I get errors in the SpecialProcessor because it doesn't properly implement the Processor interface. What can I change in the Processor

Generics in Java

由 二次信任 提交于 2019-12-10 04:06:51
问题 I would like to understand the following type of syntax. Example: public interface A < T extends A < T> > { } What is the logic of this interface ? 回答1: This would be used as follows: class X implements A<X> { /* ... */ } In other words, you are forced to make the parameter of A the class X itself, and something like class X implements A<Unrelated> is forbidden. This construction gives the interface access to X through the generic parameter, and the type restriction makes sure that it doesn't

Java: Extending inner classes

由 孤人 提交于 2019-12-10 03:39:55
问题 I am trying to understand extending inner classes in Java. I have read around but nothing I found quite answers my question. So here goes... I have... public class Pie{ protected Slice[] slices; // Pie constructor public Pie(int n){ sliceGenerator(n) } private void sliceGenerator(int n){ slices = new Slice[n]; final float sweepAngle = 360.0f/(float)n; float startAngle = 0; for (int i=0;i<n;i++){ slices[i] = new Slice(startAngle); startAngle += sweepAngle; } } @Override public String toString(

Java - Interface extending itself

由 偶尔善良 提交于 2019-12-09 15:08:39
问题 I've been using this site for about 6 months now, and its time to ask my first question, because I cant find the answer to this, atleast not an answer that I can understand! In this bit of code, why is this interface extending itself? public interface PositionedVertex<V extends PositionedVertex<V>> { /** * @return Position for node data. */ public Point getPosition(); } Wouldnt this code do the same?: public interface PositionedVertex<V> { /** * @return Position for node data. */ public Point

inner class extending

由 别说谁变了你拦得住时间么 提交于 2019-12-09 14:40:24
问题 In java, say I have the following class: public class A{ protected class B{ } } can I extend the inner class by doing the following? public class C extends A{ protected class D extends B{ } } What I want to do is that I have the class C above and I need to change something in A's inner class so I was thinking that I need to extend the inner class to do so but I wasn't sure how exactly to do that. 回答1: According to this page, you have the right way figured out to extend inner classes. A few

class attribute type pass by extends in typescript

由 点点圈 提交于 2019-12-09 03:51:00
问题 In this case the type of state is correct. export type Flatten<T> = T extends infer U ? { [K in keyof U]: U[K] } : never class Foo<S> { state?: Partial<S> } class Bar<S> extends Foo<Flatten<S & { b: string }>> { async getInitialState(initialState: S) { return { ...initialState, b: 'bar' } } } const initialState = { a: 'baz' } class Baz extends Bar<typeof initialState> { } let baz = new Baz() baz.state // Partial<{ // a: string; // b: string; // }> | undefined but in this case, the type of

Java - Calling functions in extended classes through an object array

由 血红的双手。 提交于 2019-12-08 05:05:29
I've got an array of objects, some of which use an extended version which contains a function not available in the base class. How can I call that function through the array when the array is defined by the base class? Example Shape[] shapes = new Shape[10]; shapes[0] = new Circle(10) //10 == radius, only exists in circle class which extends Shape shapes[0].getRadius(); //Gives me a compilation error as getRadius() doesn't exist in the Shape class, only in the extended Circle class. Is there a way around this? Shape class does not contain the method getRadius and hence without casting the

Java - Calling functions in extended classes through an object array

由 ￡可爱￡侵袭症＋ 提交于 2019-12-08 03:15:02
问题 I've got an array of objects, some of which use an extended version which contains a function not available in the base class. How can I call that function through the array when the array is defined by the base class? Example Shape[] shapes = new Shape[10]; shapes[0] = new Circle(10) //10 == radius, only exists in circle class which extends Shape shapes[0].getRadius(); //Gives me a compilation error as getRadius() doesn't exist in the Shape class, only in the extended Circle class. Is there
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