exp

OpenCL Intel Iris Integrated Graphics exits with Abort Trap 6: Timeout Issue

由 两盒软妹~` 提交于 2021-02-07 19:19:16
问题 I am attempting to write a program that executes Monte Carlo simulations using OpenCL. I have run into an issue involving exponentials. When the value of the variable steps becomes large, approximately 20000, the calculation of the exponent fails unexpectedly, and the program quits with "Abort Trap: 6". This seems to be a bizarre error given that steps should not affect memory allocation. I have tried setting normal , alpha , and beta to 0 but this does not resolve the problem however

Getting error “Can only apply 'exp' function to dimensionless quantities”, Not sure how to fix this

由 守給你的承諾、 提交于 2020-05-17 08:46:38
问题 I have been working on converting some MatLab code over to python for one of my professors (not an assignment just working on putting together some stuff) and I am stuck on this one part. When I run the code I am getting UnitTypeError: "Can only apply 'exp' function to dimensionless quantities", all of the methods I have tried to fix this won't work. I imagine the error is caused by the linspace command but am not sure. Any help with this would be great. here is the line IM0 = ((2*h*c**2)/(l*

Getting error “Can only apply 'exp' function to dimensionless quantities”, Not sure how to fix this

由 ぐ巨炮叔叔 提交于 2020-05-17 08:46:27
问题 I have been working on converting some MatLab code over to python for one of my professors (not an assignment just working on putting together some stuff) and I am stuck on this one part. When I run the code I am getting UnitTypeError: "Can only apply 'exp' function to dimensionless quantities", all of the methods I have tried to fix this won't work. I imagine the error is caused by the linspace command but am not sure. Any help with this would be great. here is the line IM0 = ((2*h*c**2)/(l*

Getting error “Can only apply 'exp' function to dimensionless quantities”, Not sure how to fix this

由 本秂侑毒 提交于 2020-05-17 08:46:06
问题 I have been working on converting some MatLab code over to python for one of my professors (not an assignment just working on putting together some stuff) and I am stuck on this one part. When I run the code I am getting UnitTypeError: "Can only apply 'exp' function to dimensionless quantities", all of the methods I have tried to fix this won't work. I imagine the error is caused by the linspace command but am not sure. Any help with this would be great. here is the line IM0 = ((2*h*c**2)/(l*

exp、Exploit、Exploit Pack、exp-gui、Payload、MetaSplo

由 冷暖自知 提交于 2020-04-10 00:45:04
对于走在安全路上的小菜来说，这几个exp、Exploit、Exploit Pack、exp-gui、Payload、MetaSploit名词着实把人转的不轻，下面给大家解释下： Exp，就是Exploit，漏洞利用的意思，注意，有漏洞不一定就有 Exploit （利用)。有 Exploit 就肯定有漏洞。我们可以引申为利用的方式，通常是以各种代码出现的。可以参见： Debug Struts2 S2-021的一点心得体会 payload，则是基于exp的一些特定的利用方式，通常是对漏洞测试平台而言的，可以参见 MSF漏洞攻击练习系统 exp-gui，这个就是我们俗称的工具了，他基于exp，由流行的语言例如C，C++等等，写成的带有图形化界面的漏洞利用工具。出现这个的标志已经算是漏洞的青壮年期了。也预示的漏洞的爆发！ Exploit Pack ， 这里的pack可以是各种利用工具，漏洞也都是被成熟利用或者被用于商用的漏洞，以客户端的漏洞为主，如本地的IE，PDF阅读器，Flash等，它和MetaSploit属于一个层面上的分类，只不过MetaSploit侧重远程执行的漏洞，而且MetaSploit比较被人熟知。 MetaSploit ， Metasploit是一个免费的、可下载的框架，通过它可以很容易地获取、开发并对计算机软件漏洞实施攻击

expm1 for GNU gfortran [closed]

由 折月煮酒 提交于 2020-03-26 04:50:31
问题 Closed. This question is off-topic. It is not currently accepting answers. Want to improve this question? Update the question so it's on-topic for Stack Overflow. Closed 4 years ago . Is there any way to call a fast implementation of expm1 from GNU Fortran? Ideally, it would be great to have a function to calculate (exp(x)-1)/x directly to avoid extra check for zero argument. Elemental version of expm1 would be especially helpful. 回答1: This is how it's called from libm: use, intrinsic :: iso

Transform numbers with exponents to plotmath commands for beautiful legends in R

由 给你一囗甜甜゛ 提交于 2020-01-13 23:18:04
问题 I'm trying to generate a beautiful legend in R plots. I have a factor=1e-5 , that should appear nicely formatted in the legend. I found a nice function in the package sfsmisc , that transforms numbers to expressions. To add this expression to my bquote command, it seems that I need to transform itto a call. unfortunately, there are braces added at the end of the string ( 10^-5() ). Is there a way to avoid the addition of thoses braces? Or is there even an easier way to transform numbers to

Transform numbers with exponents to plotmath commands for beautiful legends in R

由 无人久伴 提交于 2020-01-13 23:15:00
问题 I'm trying to generate a beautiful legend in R plots. I have a factor=1e-5 , that should appear nicely formatted in the legend. I found a nice function in the package sfsmisc , that transforms numbers to expressions. To add this expression to my bquote command, it seems that I need to transform itto a call. unfortunately, there are braces added at the end of the string ( 10^-5() ). Is there a way to avoid the addition of thoses braces? Or is there even an easier way to transform numbers to

Transform numbers with exponents to plotmath commands for beautiful legends in R

由 不打扰是莪最后的温柔 提交于 2020-01-13 23:13:36
问题 I'm trying to generate a beautiful legend in R plots. I have a factor=1e-5 , that should appear nicely formatted in the legend. I found a nice function in the package sfsmisc , that transforms numbers to expressions. To add this expression to my bquote command, it seems that I need to transform itto a call. unfortunately, there are braces added at the end of the string ( 10^-5() ). Is there a way to avoid the addition of thoses braces? Or is there even an easier way to transform numbers to

EXP to Taylor series

由 家住魔仙堡 提交于 2020-01-13 19:21:10
问题 I'am trying to expand exp(x) function to Taylor series. Here is code: double CalcExp(){ double eps = 0.0000000000000000001; double elem = 1.0; double sum = 0.0; int i = 1; sum = 0.0; do { sum += elem; elem *= x / i; i++; } while (elem >= eps); return sum; } The problem is when I enter big X or negative X my program crashes. And when I enter X like "0.00000000001" the result is -1. Need advice. Thank's for help. 回答1: For big X values (around 700 and above), you'll hit the range limit for
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