enumeration

问题 Is it possible to distinct xs:choices in xsd by using fixed values? I have a simple type: <xs:simpleType name="datatypeCategory"> <xs:restriction base="xs:string"> <xs:enumeration value="SIMPLE"/> <xs:enumeration value="COMPLEX"/> <xs:enumeration value="COLLECTION"/> </xs:restriction> </xs:simpleType> And what I want to achieve is <xs:element name="datatype"> <xs:complexType> <xs:choice> <xs:sequence> <xs:element id="category" type="datatypeCategory" fixed="SIMPLE"/> <!-- some fields specific

问题 On Exercise 39 of Learn Python The Hard Way, lines 37 to 39 look like this: print "-"*10 for state, abbrev in states.items(): print "%s has the city %s" % (state, abbrev) I thought I understood this. I thought Python was taking the KEY:VALUE from "states" and assigning the KEY to "state" and the VALUE to "abbrev". However, I found something strange happened when I entered the following code: print "-"*10 for test in states.items(): print "%s has the city %s" % (test) It produces the same

问题 I looked around but I couldn't find anything that suited for this. $n = 3;//number of events $k = array(0,1);//possible outcomes I'd like to have an array containing all the possible outcomes: $result = array([0] => array(0,0,0), [1] => array(1,0,0)... [7] =>array(1,1,1)); I tried this long and static method that leads me to nothing useful: for($a=0;$a<count($k);$a++) { for($b=0;$b<count($k);$b++) { for($c=0;$c<count($k);$c++) { $push = array($a,$b,$c); array_push($result,$push); }}} How can

问题 Say I have a project ~10 tables with ~30 entries each, which enumerate values. What are possible advantages/disadvantages with regard to scenario 1 vs scenario 2? And is there a turning point for these (dis)advantages based on the amount of enumeration tables/amount of rows per table? Scenario 1: Table 1: ID Value --------- 1 - Value1 2 - Value2 3 - Value3 Table2: ID Value --------- 1 - Value4 2 - Value5 3 - Value6 Scenario 2: Table1: ID Value Category --------------------- 1 - Value1 - 1 2 -

问题 Just as the title says. I tried messing around a bit with Collections.sort() on a List[] and the .sort() function of an ArrayList but I was never able to parse it back to an Enumeration. Thanks! EDIT: Here's some pseduocode and further explanation. My goal is to take the keys() from a Hashtable and do complex operations involving each one, alphabetically. My current process is: Take a hash table I'm given Form an enumeration from the ht Run a while loop until the enumeration is empty So the

问题 This question already has answers here : Compare a string input to an Enumerated type (3 answers) Closed 2 years ago . I am reading input from the keyboard. The input is supposed to match one of the elements defined in an enumeration type. Here is an example of the enum type: type NameType is (Bob, Jamie, Steve); If I receive an input that is not one of these 3, ada raises an IO exception. How do I handle this to where I can simply display a "try again" message and not have the program stop?

问题 An interview question for a .NET 3.5 job is "What is the difference between an iterator and an enumerator"? This is a core distinction to make, what with LINQ, etc. Anyway, what is the difference? I can't seem to find a solid definition on the net. Make no mistake, I can find the meaning of the two terms but I get slightly different answers. What would be the best answer for an interview? IMO an iterator "iterates" over a collection, and an enumerator provides the functionality to iterate,

问题 object TestEnum extends Enumeration{ val One = Value("One") val Two,Three= Value } println(TestEnum.One.getClass) println(TestEnum.One.getClass.getDeclaringClass)//get Enumeration So my question is how to get Class[TestEnum] from TestEnum.One? Thanks. 回答1: I don't think you can unfortunately. TestEnum.One is really just an instance of the class Enumeration#Value . In fact, it's lots worse than just this - your enumeration values are all erased by type to the same thing: object Weekday extends

问题 Example. I've got an array with 15 objects. I want to start enumerating from a given index. Say start at index 5 and then the index above, the index under, above, under etc... I don't want it to wrap around, but rather stop and continue in unexplored direction. So the order of indexes in my example would be. 5, 6, 4, 7, 3, 8, 2, 9, 1, 10, 0, 11, 12, 13, 14 How can this be done? 回答1: Here's a more compact implementation that doesn't require creating subarrays: @implementation NSArray

问题 It's my first time, so let me know if I'm doing something wrong with the layout of my question. I have a lot of JSON files with filenames that follow a naming convention, i.e. file1.json, file2.json, etc. Each of which are likely to have multiple objects which look like: [ { "Forename": "Jim", "Surname": "Cook", "Gender": "M", "DOB": "12-03-1994" }, { "Forename": "Sarah", "Surname": "Parker", "Gender": "F", "DOB": "01-02-1983" }, { "Forename": "Alan", "Surname": "Flemming", "Gender": "M",