elements

jQuery serialize

由 为君一笑 提交于 2019-12-31 09:02:01
jQuery serialize模块是对象数组序列化模块。 首先我们先看一下《JavaScript高级程序设计》中的序列化函数，专门用于form参数序列化的。 serialize函数 function serialize(form){ var parts = [], field = null, i, len, j, optLen, option, optValue; for(i = 0, len = form.elements.length; i < len; i++){ field = form.elements[i]; switch(field.type){ case "select-one": case "select-multiple": if(field.name.length){ for(j = 0, optLen = field.options.length; j < optLen; j++){ option= field.options[j]; if(option.selected){ optValue = ""; if(option.hasAttribute){ optValue = (option.hasAttribute("value")) ? option.value : ooption.text); }else{ optValue = (option

jquery find element by specific class when element has multiple classes

由 我们两清 提交于 2019-12-31 08:29:24
问题 So I am working on something that wasn't well thought out in the build from the backend team. That leaves me with a document full of divs. What I am doing is rolling back from the element I need to click on, get the parent container then find an element within the parent which has class="alert-box warn" , class="alert-box dead" , etc... Essentially, I'm trying to use multiple class selectors on each element. When I try to find just alert-box it doesn't seem to be working right. I'm assuming

jquery find element by specific class when element has multiple classes

由 与世无争的帅哥 提交于 2019-12-31 08:29:13
问题 So I am working on something that wasn't well thought out in the build from the backend team. That leaves me with a document full of divs. What I am doing is rolling back from the element I need to click on, get the parent container then find an element within the parent which has class="alert-box warn" , class="alert-box dead" , etc... Essentially, I'm trying to use multiple class selectors on each element. When I try to find just alert-box it doesn't seem to be working right. I'm assuming

Most common values in an array

由 放肆的年华 提交于 2019-12-30 11:31:25
问题 How would I go about finding the three most common elements in an array? I am working with an array of length 10,000 with elements = random integer from 0-100. I was thinking of using two arrays, one of length 100 and just incrementing by using an if statement. However, I was wondering if there is a way that only one for/if loop(statement) could be used to find these values. 回答1: If you are going to do this in a constant number of passes over the list, you need a second data structure. If you

数据结构（堆）源码

由 故事扮演 提交于 2019-12-29 13:14:08
#include <stdio.h> #define MaxData 200 typedef struct Heap *MaxHeap; struct Heap{ int *Elements;//存储堆的数组 int size;//当前元素个数 int capacity;//堆的最大容量 }; MaxHeap create(int Maxsize){ MaxHeap H=new Heap; H->Elements=new int; H->size=0; H->capacity=Maxsize; H->Elements[0]=MaxData;//定义哨兵，为大于堆中所有可能元素的值 return H; } void Insert(MaxHeap H,int item){ int i; if(H->size==H->capacity){ printf("堆已经满了"); return; } i=++H->size; for(;H->Elements[i/2]<item;i=i/2){ H->Elements[i]=H->Elements[i/2];//让父节点移动下来 } H->Elements[i]=item; } int DeleteMax(MaxHeap H){ int parent,child; int Maxitem,temp; if(H->size==0){ printf(

Python List of Dictionaries Only See Last Element

由 纵然是瞬间 提交于 2019-12-25 07:42:16
问题 Struggling to figure out why this doesn't work. It should. But when I create a list of dictionaries and then look through that list, I only ever see the final entry from the list: alerts = [] alertDict = {} af=open("C:\snort.txt") for line in af: m = re.match(r'([0-9/]+)-([0-9:.]+)\s+.*?(\d{1,3}\.\d{1,3}\.\d{1,3}\.\d{1,3}):(\d{1,5})\s+->\s+(\d{1,3}\.\d{1,3}\.\d{1,3}\.\d{1,3}):(\d{1,5})', line) if m: attacktime = m.group(2) srcip = m.group(3) srcprt = m.group(4) dstip = m.group(5) dstprt = m

WebDriverIO select using elements index

由 ╄→尐↘猪︶ㄣ 提交于 2019-12-24 19:56:17
问题 I am using WebDriverIO to try to access (ie. getText, getAttribute, click, etc) an element after creating a list of elements. I am easily able to implement this element if I am using the browser.element() method, but the moment I use browser.elements() , I cannot access the individual objects in the array. According to the WebDriverIO docs, I should be able to access them using the value property. Here is my pseudo-code. I assumed that these two functions should return the same thing:

Fragment Shared Element showing abnormal behaviour in transition

由 最后都变了- 提交于 2019-12-24 13:24:01
问题 Here is my code: DetailsFragment fragment = new DetailsFragment(); Transition changeTransform = TransitionInflater.from(getActivity()).inflateTransition(R.transition.change_image_transform); Transition explodeTransform = TransitionInflater.from(getActivity()). inflateTransition(android.R.transition.explode); setSharedElementReturnTransition(changeTransform); setExitTransition(explodeTransform); // Setup enter transition on second fragment fragment.setSharedElementEnterTransition

XSLT 2.0 - Using Grouping To Nest Elements

由 China☆狼群 提交于 2019-12-24 12:23:42
问题 I'm working on a stylesheet that outputs in a hierarchical format from an input file with almost none. Each section has an extremely flat hierarchy, so I've been using a grouping method that was suggested to me - it groups each set by the first node name, and thus makes a nice heirarchy out of flat sections. This method works great - I just need to modify it to account for elements I want to skip over. Sample input file (note: there are multiple Header elements per Section): <Root>

Compare Tuples and find next index in it's same position in python

由 落爺英雄遲暮 提交于 2019-12-24 08:39:17
问题 R=[(1,10,14,34),(2,5,19,21),(3,7,31,32),(1,9,12,31),(2,10,11‌​,22),(4,8,14,32),(13‌​,15,19,34),(1,5,15,2‌​0),(3,26,19,25),(4,1‌​7,19,21),(4,1‌​7,20,21)] For each tuple in R, find the next index of each elements with the same element position where other elements should not be present in both tuples. FOR Index 0 and 1 here is expected sample results 0: 4,5,6,7 1: 2,5,6,8 . . . . . so on Here is my code is going too detail and too lengthy and taking too long to run for my actual project. so i
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