elements

R - Create a ordered list from a matrix

由 丶灬走出姿态 提交于 2020-01-16 18:39:33
问题 Hi there! I have this 24x24 matrix with a lot of numbers from 1-24. Where I want to turn every cell with the value of X (eg. 3) into the row.name of the X'th row (eg. name3) What I have row.names V1 V2 V3 name1 1 3 10 name2 3 20 1 name3 5 13 2 ... .. .. .. name24 19 3 4 What I want to do now, is turn all these numbers into a character string equvivalent to the i'th row name so a 1 should be converted to name1 and so forth. What I need row.names V1 V2 V3 name1 name1 name3 name10 name2 name3

Deleting array elements in python

由 旧城冷巷雨未停 提交于 2020-01-13 05:13:44
问题 All, I want to delete specific array elements of one array from the other. Here is an example. The arrays are a long list of words though. A = ['at','in','the'] B = ['verification','at','done','on','theresa'] I would like to delete words that appear in A from B. B = ['verification','done','theresa'] Here is what I tried so far for word in A: for word in B: B = B.replace(word,"") I am getting an error: AttributeError: 'list' object has no attribute 'replace' What should I use to get it? 回答1:

Python: how to remove/delete every n-th element from list?

由 ╄→尐↘猪︶ㄣ 提交于 2020-01-11 09:15:56
问题 I had already looked through this post: Python: building new list from existing by dropping every n-th element, but for some reason it does not work for me: I tried this way: def drop(mylist, n): del mylist[0::n] print(mylist) This function takes a list and n . Then it removes every n-th element by using n-step from list and prints result. Here is my function call: drop([1,2,3,4],2) Wrong output: [2, 4] instead of [1, 3] Then I tried a variant from the link above: def drop(mylist, n): new

how to delete an element that contains a letter in array using swift

由 放肆的年华 提交于 2020-01-07 09:25:10
问题 I am having trouble trying to figure this topic out. Like the topic, How do I delete an element that contains a letter in Array. This is the code I have so far. let newline = "\n" let task = Process() task.launchPath = "/bin/sh" task.arguments = ["-c", "traceroute -nm 18 -q 1 8.8.8.8"] let pipe = Pipe() task.standardOutput = pipe task.launch() let data = pipe.fileHandleForReading.readDataToEndOfFile() let output = NSString(data: data, encoding: String.Encoding.utf8.rawValue) as! String var

How to count unique elements in the array? Need only idea

由 我怕爱的太早我们不能终老 提交于 2020-01-07 05:48:09
问题 For example: String[] str = {"M1","M1","M1","M2","M3"}; The most recommended is the answer - HashSet . Which methods or you have better idea? 回答1: Unless you want to implement this yourself, a Set is the way to go. A set will only allow unique elements to be added and will automatically filter duplicates. The HashSet functionality works as follows: The hash is computed for the object. Next the set checks if any of the objects with the same hash-value .equals() the new value. If so, the new

How to create and append multiple dom elements efficiently

由 Deadly 提交于 2020-01-07 02:52:07
问题 I'm building 10 buttons on the DOM and want to see if there is a more efficient way of building them because it seems strange to be calling createElement and appendChild 10 times. <script> function makeAlertButtons () { var container = document.createElement("div") container.setAttribute('id', "container") document.getElementsByTagName('body')[0].appendChild(container) for (var x = 1; x <=10; x++) { var butt = document.createElement("button") butt.appendChild(document.createTextNode(x))

203. Remove Linked List Elements (E)

由 别来无恙 提交于 2020-01-07 02:45:39
Remove Linked List Elements (E) Remove all elements from a linked list of integers that have value val . Example: Input: 1->2->6->3->4->5->6, val = 6 Output: 1->2->3->4->5 题意 将给定链表中所有含有指定值的结点删除。 思路 注意需要连续删除结点的情况。 代码实现 /** * Definition for singly-linked list. * public class ListNode { * int val; * ListNode next; * ListNode(int x) { val = x; } * } */ class Solution { public ListNode removeElements ( ListNode head , int val ) { ListNode dumb = new ListNode ( 0 ) ; dumb . next = head ; ListNode pre = dumb ; ListNode cur = head ; while ( cur != null ) { if ( cur . val == val ) { pre . next = cur .

XPath, select two consecutive elements and transform them into one data frame

由 青春壹個敷衍的年華 提交于 2020-01-05 07:10:37
问题 I am really new to Path and R in general and am trying to convert an XML file using XPath into a data frame in R. With some help I managed to transform most of the information in the XML already . However, now I am trying to take two consecutive elements and merge them into one data frame. Somehow I can't seem to get it right. This is an excerpt of the xml data: </customer-bootstrap-data> <customer-bootstrap-data id="970911" customerName="HighIncome-1_4" powerType="ELECTRIC_VEHICLE">

Delete a specific element from a Fortran array

由 风格不统一 提交于 2020-01-03 02:37:05
问题 Is there a function in Fortran that deletes a specific element in an array, such that the array upon deletion shrinks its length by the number of elements deleted? Background: I'm currently working on a project which contain sets of populations with corresponding descriptions to the individuals (i.e, age, death-age, and so on). A method I use is to loop through the array, find which elements I need, place it in another array, and deallocate the previous array and before the next time step,

document.querySelectorAll get innerText of ALL selected elements at once pure javascript

由 ℡╲_俬逩灬. 提交于 2020-01-01 03:32:12
问题 I want to get all innerText of a whole column of a very long html table (random length). I'm using this code: var tbEls = document.querySelectorAll('#tBodyID tr td:nth-child(cidx)'); Where cidx = the column index I want to extract content from. But such code extracts all the td elements (with the innerText inside them of course). But it doesn't extract directly all the innerText inside them. Cause of this I have to reprocess the returned tdEls array with a for loop to extract from each tbEls
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