duplicates

问题 Following my previous question, I am now trying to remove duplicates from my database. I am first running a sub-query to identify the almost identical records (the only difference would be the index column "id"). My table has roughly 9 million records and the below code had to be interrupted after roughly 1h30 DELETE FROM public."OptionsData" WHERE id NOT IN ( SELECT id FROM ( SELECT DISTINCT ON (asofdate, contract, strike, expiry, type, last, bid, ask, volume, iv, moneyness, underlying,

问题 I want to set up only one instance of the CHM file when clicking on "Help" in the menubar and stopping it from opening twice when clicked again - therefore how do I code it? I've tried to use it with process.isAlive(), but after I close it I want a counter set to zero, which only opens another CHM file when the counter is 0. helpMenu.addMouseListener(new MouseAdapter() { // do this after clicked openCHM(); }); So MouseEvent is fired once. openCHM() { Process p; if(cnt == 0) { p = Runtime

问题 I wanted to know how I can find duplicate values in a dictionary and the return the keys that contain those values. So here is an example: d = {'happy':['sun', 'moon', 'chocolate'], 'sad':['fail', 'test', 'bills'], 'random': ['baloon', 'france', 'sun'] } As you can see the key's happy and random have the same/duplicate value in them, which is 'sun' , so the output I was looking for is: random, happy I cant really understand how I can find duplicate values like that. If I had a particular

问题 My MySQL table has below records, ID Name Account ----------------------------------------- 1 ABC PQR 2 DEF PQR 3 ABC PQR 4 XYZ ABC 5 DEF PQR 6 DEF ABC I am looking for an output like ID Name Account Duplicate Sr No. ----------------------------------------- 1 ABC PQR 1 2 DEF PQR 1 3 ABC PQR 2 4 XYZ ABC 1 5 DEF PQR 2 6 DEF ABC 1 Here i mean that each duplicate should have a Sr Number or number the duplicates. Name : ABC and Account : PQR when repeated in the table, there is an increment in

问题 I have a row of ten numbers for example: 5 5 6 7 5 9 4 2 2 7 Now I want a program that finds all duplicates and gives them out in the console like 3 times 5, 2 times 2, 2 times 7. While I did code an algorithm that finds duplicates in a row of numbers I can't give them out in the console as described. My program will output: 3 times 5 2 times 5 2 times 7 2 times 2 How can I solve this problem? #include <iostream> using namespace std; int main() { int arr[10]; int i,j; int z = 1; for(i = 0; i

问题 I'm using the following SQL to identify duplicates in the table 'transaction_list'. This works perfectly. Now I want to delete all duplicates from that table based on these criteria and leave only the latest entries. These can be identified by the column 'last_update'. I tried different DELETE statements but it didn't work. Any suggestions are highly appreciated. SELECT par_num ,tran_num ,COUNT(*) AS num_duplicates FROM transaction_list WHERE last_update >= to_date('01-mar-2020 00:00:00', 'dd

问题 There are loads of ways to find to find Duplicates in a list, is There any way to find continuous duplicates in a List. For example List<string> stringList = new List<string>(); stringList.Add("Name1"); stringList.Add("Name2"); stringList.Add("Name1"); Shouldn't find any but stringList.Add("Name1"); stringList.Add("Name1"); stringList.Add("Name2"); Should return 1 Entry This returns duplicates. var q = listString.GroupBy(x => x) .Select(g => new { Value = g.Key, Count = g.Count() })

问题 I need a UNION of two queries, each of them works separatly, but not together, I get error: duplicate column name zipcode_id , please help. (SELECT * FROM ( (SELECT * FROM jobs AS j LEFT JOIN zipcode AS z ON z.zipcode_id=j.zipcode_id WHERE 1 AND source='student' ORDER BY postdate DESC LIMIT 20) ORDER BY search_order DESC ) s1) UNION ALL (SELECT * FROM ( (SELECT * FROM jobs AS j LEFT JOIN zipcode AS z ON z.zipcode_id=j.zipcode_id WHERE 1 AND source='manager' ORDER BY postdate DESC LIMIT 30,

问题 I am trying to remove duplicates values of specific columns based on a single column, while keeping the rest of the row. df = pd.DataFrame({'A':[1,2,3,4],'B':[5,5,6,7],'C':['a','a','b',c'], D:['c','d','e','f']}) I want to delete the values in column A & B based off the duplicates in column C, but keeping all of column D. Expected output: A B C D 1 5 a c d 3 6 b e 4 7 c f 回答1: Using simple loc df.loc[df.C.duplicated(), ['A', 'B']] = '' A B C D 0 1 5 a c 1 a d 2 3 6 b e 3 4 7 c f Can also use

问题 I have a list in python that contains duplicate dataframes. The goal is to remove these duplicate dataframes in whole. Here is some code: import pandas as pd import numpy as np ##Creating Dataframes data1_1 =[[1,2018,80], [2,2018,70]] data1_2 = [[1,2017,77], [3,2017,62]] df1 = pd.DataFrame(data1_1, columns = ['ID', 'Year', 'Score']) df2 = pd.DataFrame(data1_2, columns = ['ID', 'Year', 'Score']) ###Creating list with duplicates all_df_list = [df1,df1,df1,df2,df2,df2] The desired result is this