du

##df命令 使用 df -h 命令可以查看磁盘各分区大小、已使用空间以及挂载点等信息. ##du命令 使用 du 命令可以查看某个目录所占用的磁盘空间大小。常见的用法是: du -sh folder. 来源： oschina 链接： https://my.oschina.net/u/941605/blog/726119

more /proc/partitions 查看所有分区信息 more /proc/scsi 查看scsi设备（移动硬盘或U盘）信息 more /proc/diskstats 查看磁盘io信息 查看文件占用的内存： 当磁盘大小超过标准时会有报警提示，这时如果掌握df和du命令是非常明智的选择。 df可以查看一级文件夹大小、使用比例、档案系统及其挂入点，但对文件却无能为力。 du可以查看文件及文件夹的大小。 两者配合使用，非常有效。比如用df查看哪个一级目录过大，然后用df查看文件夹或文件的大小，如此便可迅速确定症结。 [yayug@yayu ~]$ df -h Filesystem Size Used Avail Use% Mounted on /dev/sda1 3.9G 300M 3.4G 8% / /dev/sda7 100G 188M 95G 1% /data0 /dev/sdb1 133G 80G 47G 64% /data1 /dev/sda6 7.8G 218M 7.2G 3% /var /dev/sda5 7.8G 166M 7.2G 3% /tmp /dev/sda3 9.7G 2.5G 6.8G 27% /usr tmpfs 2.0G 0 2.0G 0% /dev/shm 参数 -h 表示使用「Human-readable」的输出，也就是在档案系统大小使用 GB

I'm trying to use du command for every directory in the current one. So I'm trying to use code like this: ls | du -sb But its not working as expected. It outputs only size of current '.' directory and thats all. The same thing is with echo ls | echo Outputs empty line. Why is this happening? FatalError Using a pipe sends the output ( stdout ) of the first command, to stdin (input) of the child process (2nd command). The commands you mentioned don't take any input on stdin . This would work, for example, with cat (and by work, I mean work like cat run with no arguments, and just pass along the

I'm trying to check with Disk Usage tool how big are my home directory folders but it also prints out folders and files starting with dot. I can't seem to filter them out. du -h --exclude="?" du -h | grep -v "?" du -h | grep -ve "?" du -h | sed "?" Thanks in advance. edit> Thank you SiegeX for you answer. du -h --max-depth=1 | grep -v "./\\." Since dot matches any character we have to prefix it with double backslash since its also a special character. If running du with no specified path (current dir), use this: du -h --exclude "./.*" 来源： https://stackoverflow.com/questions/5463884/excluding

PLEASE SEE BELOW THE ORIGINAL QUESTION FOR SOME TEST COMPARISONS OF DIFFERENT WAYS: So I tried 2 ways so far: 1.Iterate through directory using the code from Get Folder Size from Windows Command Line : @echo off set size=0 for /r %%x in (folder\*) do set /a size+=%%~zx echo %size% Bytes 2.Save output of a 'dir %folder% /s /a' into a text file, and then read in the size at the bottom 3.The last way I am trying right now is using du (disk utility tool from MS - https://technet.microsoft.com/en-us/sysinternals/bb896651.aspx ). Now with exception of #3 both of those ways seem way too slow for what

I have a large set of directories for which I'm trying to calculate the sum total size of several hundred .txt files. I tried this, which mostly works: find . -name *.txt | xargs du -hc But instead of giving me one total at the end, I get several. My guess is that the pipe will only pass on so many lines of find's output at a time, and du just operates on each batch as it comes. Is there a way around this? Thanks! Alex How about using the --files0-from option to du? You'd have to generate the null-terminated file output appropriately: find . -name "*txt" -exec echo -n -e {}"\0" \; | du -hc -

I am trying to evaluate the disk usage of a number of Unix user accounts. Simply, I am using the following command: du -cBM --max-depth=1 | sort -n But I’ve seen many error message like below. How can I exclude all such “Permission denied” messages from display? du: `./james/.gnome2': Permission denied My request could be very similar to the following list, by replacing “find” to “du”. How can I exclude all "permission denied" messages from "find"? The following thread does not work. I guess I am using bash. Excluding hidden files from du command output with --exclude, grep -v or sed du -cBM -