directory

SQLite: Create Directory Structure Table from A List Of Paths

荒凉一梦 提交于 2021-02-10 16:14:12
问题 I want to create a directory structure table as described in this question where: Directory = "Primary Key" id field, typically an integer Directory_Parent = "Foreign Key" id field, which points to the id of another Directory in the same table Value = string containing the directory/folder name Given Tree/Fruit/Apples/ Directory | Directory_Parent | Value 0 null Root 1 0 Tree 2 1 Fruit 3 2 Apples A Root folder has been created at Primary Key 0 with a null parent. My paths are being imported

batch script - write all files found in one directory into one command line?

老子叫甜甜 提交于 2021-02-10 15:00:57
问题 I have a directory with a bunch of files with a mix of extension. I only want to work with files with extension *.abc. Each *.abc file should then be handed over to another software with some parameters. The parameters are always the same for each file. One of the parameters needs to be defined by the user, though. So my first try was this: @ECHO OFF set /p value="Enter required imput value: " for %%f in (*.abc) do ( START C:\"Program Files"\Software\startsoftware.exe -parameter1 "%%~nf.abc"

batch script - write all files found in one directory into one command line?

两盒软妹~` 提交于 2021-02-10 15:00:26
问题 I have a directory with a bunch of files with a mix of extension. I only want to work with files with extension *.abc. Each *.abc file should then be handed over to another software with some parameters. The parameters are always the same for each file. One of the parameters needs to be defined by the user, though. So my first try was this: @ECHO OFF set /p value="Enter required imput value: " for %%f in (*.abc) do ( START C:\"Program Files"\Software\startsoftware.exe -parameter1 "%%~nf.abc"

How to manipulate windows file and folder attribute with PHP?

六月ゝ 毕业季﹏ 提交于 2021-02-10 14:22:54
问题 Is this any possible way to set or change windows file and folder attribute with php? I'm creating desktop.ini file in some folders with php. But I need to make it HSA - Hidden, System file, Archive - In addition I need to make folder read-only which is a R flag. Is there anyway to do that with PHP ? please help me! 回答1: Finally I find the answer, exec("attrib +r <any directory>"); exec("attrib +h +s +a desktop.ini"); 来源: https://stackoverflow.com/questions/49629856/how-to-manipulate-windows

Wordpress/htaccess - allow access to subdirectory

北慕城南 提交于 2021-02-10 07:34:33
问题 I have a subdirectory ( app ) I want to access that is in the root folder of my wordpress site. I have looked here: https://wordpress.stackexchange.com/questions/20152/cannot-access-non-wordpress-subdirectories-as-wordpress-overrides-them-with-a-40 I have tried the solutions and nothing worked. I also tried adding a separate .htaccess file to the app subdirectory that looks like this: DirectoryIndex index.php index.html index.htm Options +Indexes But it didn't seem to help: The main .htaccess

Flask on nginx + uWSGI returns a 404 error unless the linux directory exists

主宰稳场 提交于 2021-02-10 06:34:26
问题 This might be kind of a strange problem, but I'm not too experienced with these things and I don't know how to search for this kind of error. I have a server configured with nginx and uWSGI. Everything runs fine, no errors in the logs that I can see. However, when I'm executing the below code: from flask import Flask app = Flask(__name__) @app.route('/test/') def page1(): return 'Hello World' @app.route('/') def index(): return 'Index Page' I can not view http://ezte.ch/test/ UNLESS the /test

Get specific level of directory

一笑奈何 提交于 2021-02-10 04:36:41
问题 i would like to get the original folder name by dynamic path and username, and without Windows default directory For example, C:\Users\dynamic user\Desktop\History\2014-11-03\Spreadsheets\excel.xls C:\Users\dynamic user\Desktop\History\record.xls In this case, i want it to return "History" for excel.xls & record.xls. I tried to use GetFilename() method. But it just returns Spreadsheets - excel.xls History - record.xls Is it possible to achieve? Thanks for your help. 回答1: Yes, as documented of

C++ Load DLL From a Subdirectory?

核能气质少年 提交于 2021-02-08 13:44:38
问题 I'm new to the "hidden/dark places" of C++ and I was wondering how to load a .dll file from a different directory or a sub-directory inside the one where my current executable is running Ex: ./MyAppDirectory /MyApp.exe /SomeDLL.dll /AnotherDLL.dll /SubDirectory /SomeDLL2.dll /AnotherDLL2.dll /YetAnotherDLL.dll /... So "MyApp.exe" automatically loads "SomeDLL.dll" and "AnotherDLL.dll" from it's root folder "MyAppDirectory" however I also want to be able to load "SomeDLL2.dll", "AnotherDLL2.dll

Invalid 'length' argument Error

穿精又带淫゛_ 提交于 2021-02-08 12:13:47
问题 I want to calculate the mean of column of all the csv in one directory, but when I run the function it give me the error of "Error in numeric(nc) : invalid 'length' argument". I believe that CSV files have n/a value but it shouldn't affect the calculate the number of column? pollutantmean <- function(directory, pollutant, id =1:332, removeNA = TRUE){ nc <- ncol(pollutant) means <- numeric(nc) for(i in 1:nc){ means[i] <- mean(pollutant[, i], na.rm = removeNA) } means } So here is my update

Directory Handle in Perl Not Working Properly

a 夏天 提交于 2021-02-08 10:58:35
问题 I am trying to read files inside a folder in Perl using Directory Handle. The script is able to show the file name but it is throwing two errors: readdir() attempted on invalid dirhandle DIR and closedir() attempted on invalid dirhandle DIR . I am calling a subroutine and passing two values: if($fileEnding eq "directory") { print "$fileName is a directory\n"; FolderInvestigator1($a, $fileName); } $a holds the directory name and its path which is being passed via command-line argument. I am