digits | 易学教程

Inserting spaces between digits in C

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问题 How would I go about taking a number like 123456 and having it print as 1 2 3 4 5 6 ? 回答1: As 'jamesdlin' has mentioned in his comment, GMan's approach would work, however you will need to store it in a buffer in order to print out in the correct order (his algorithm would print out "6 5 4 3 2 1" for input 123456). At this point I'd say that it would be much simpler to just use sprintf as 'therefromhere' suggested in his answer (if this is not an algorithm class assignment of course). In my

Simple Number to Array with Individual Digits

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问题 I am exceptionally new to programming, but I am working on improving my skills as a programmer. Currently, I am working on a problem I gave myself where I am trying to take a variable number and make each of its digits a separate number in an array. I don't care about the order of the digits, so if they are reversed, then it doesn't matter to me. I know people have asked this question numerous times, but they always seem to use a lot of things that I don't understand. Since my school doesn't

C# string starts with a number regex

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问题 I've been searching around for a little while to figure out how to confirm a string begins with a number. I came across a regex statement '/^\d/' which I can confirm says if starts with digit. However I can not seem to get it to work in the code below. Where did I went wrong in the statement if(Regex.Match(info,"/^\d/")) ? //String attachbody is the attachment body from an email C read into a string string[] data = Regex.Split(attachbody, "\n"); foreach (String info in data) { if (Regex.Match

One or two numeric digits Regex

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问题 I have the below code. It works only when I have 2 digits. If I have 1 digit doesn't work. I want to work in both cases: one or two digit. var numberRegex = /^[1-9][0-9]$/; I've tried something like this but unfortunately doesn't work: var numberRegex = /^[1-9]?[1-9][0-9]$/; Thanks for support. 回答1: Try this one out: /^\d{1,2}$/; Reading what you have it looks like you don't want to accept numbers like 01 . /^\d{1}|[1-9]\d{1}$/; 回答2: Try this. /^[0-9]|[0-9][0-9]$/ This should do the job.

Turkish Identity Number Verification in Swift

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How can I make sure that the given text is Turkish Identity Number? I have seen js version here and phthon version here Turkish Identity Verification is not checks only if its numeric, it has some other functions too. Let me be more clear, It is numeric and has 11 digits. For example Let assume that first 9 digits are represented by d, and the last ones represented by c: Identity Number = d1 d2 d3 d4 d5 d6 d7 d8 d9 c1 c2 10th digit must be, c1 = ( (d1 + d3 + d5 + d7 + d9) * 7 - (d2 + d4 + d6 + d8) ) mod10 11th must be, c2 = ( d1 + d2 + d3 + d4 + d5 + d6 + d7 + d8 + d9 + c1 ) mod10 and it never

Objective C- How to add digits in a number?

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问题 How do I add the digits in a particular number for example if the number is 3234 the result should be 3+2+3+4 = 12? 回答1: Something along the lines of this should do it: int val = 3234; int sum = 0; while (val != 0) { sum += (val % 10); val = val / 10; } // Now use sum. For continued adding until you get a single digit: int val = 3234; int sum = val; while (sum > 9) { val = sum; sum = 0; while (val != 0) { sum += (val % 10); val = val / 10; } } // Now use sum. Note that both of these are

Difference in digits10 between GCC and MSVC

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问题 I have the following code: #include <iostream> #include <limits> int main() { std::cout << std::numeric_limits<unsigned long long>::digits10 << std::endl; return 0; } GCC 4.4 returns 19 MS VS 9.0 returns 18 Can someone please explain Why is there a difference between the two? I would have expected such a constant would be the same regardless of the compiler. 回答1: If Visual C++ 2008 returns 18 for std::numeric_limits<unsigned long long>::digits10 , it is a bug (I don't have Visual C++ 2008

R: formatting the digits in xtable

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I have the data: transaction <- c(1,2,3); date <- c("2010-01-31","2010-02-28","2010-03-31"); type <- c("debit", "debit", "credit"); amount <- c(-500, -1000.97, 12500.81); oldbalance <- c(5000, 4500, 17000.81) evolution <- data.frame(transaction, date, type, amount, oldbalance, row.names=transaction, stringsAsFactors=FALSE); evolution$date <- as.Date(evolution$date, "%Y-%m-%d"); evolution <- transform(evolution, newbalance = oldbalance + amount); evolution If I want to create a table with the digits in amount just equal to 1 decimal place, does such a command work? > tab.for <- formatC

Fastest way to sum digits in a number

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Given a large number, e.g. 9223372036854775807 ( Int64.MaxValue ), what is the quickest way to sum the digits? Currently I am ToStringing and reparsing each char into an int : num.ToString().Sum(c => int.Parse(new String(new char[] { c }))); Which is surely horrifically inefficent. Any suggestions? And finally, how would you make this work with BigInteger ? Thanks Well, another option is: int sum = 0; while (value != 0) { int remainder; value = Math.DivRem(value, 10, out remainder); sum += remainder; } BigInteger has a DivRem method as well, so you could use the same approach. Note that I've

Using django haystack autocomplete with elasticsearch to search for digits/numbers?

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I'm using Django Haystack backed by Elasticsearch for autocomplete, and I'm having trouble searching for digits in a field. For example, I have a field called 'name' on an object type that has some values like this: ['NAME', 'NAME2', 'NAME7', 'ANOTHER NAME 8', '7342', 'SOMETHING ELSE', 'LAST ONE 7'] and I'd like to use autocomplete to search for all objects with the number '7' in the name. I've set up my search_index with this field: name_auto = indexes.EdgeNgramField(model_attr='name') and I'm using a search query like so: SearchQuerySet().autocomplete(name_auto='7') However, this search