digit

问题 Ho to add class to the tab in TabContainer? Only thing I've found is set iconClass. However I need to add class to the parent div in tab. Not to some nested divs inside it. 回答1: Not a simple way, but I got access to the tab button in the tabcontainer object. var tabContainer = ...; dojo.addClass(tabContainer.tablist.pane2button["123"].domNode, "myTabClass"); http://jsfiddle.net/cswing/N2hsG/ 回答2: Building on Craig's suggestion, here's the modern way of doing it: // assuming there is only one

问题 I am using MySQL with Spring JDBC template for my web application. I need to store phone number with only digits (10). I am little bit confused about data type using data type. What is preferable data type for it in MySQL? What should be Java data type in Bean (POJO) classes for that? How can I validate that datatype with javax validations/constrains for length and also only digit allowed? 回答1: Strings & VARCHAR. Do not try storing phone numbers as actual numbers. it will ruin the formatting,

问题 I am using MySQL with Spring JDBC template for my web application. I need to store phone number with only digits (10). I am little bit confused about data type using data type. What is preferable data type for it in MySQL? What should be Java data type in Bean (POJO) classes for that? How can I validate that datatype with javax validations/constrains for length and also only digit allowed? 回答1: Strings & VARCHAR. Do not try storing phone numbers as actual numbers. it will ruin the formatting,

问题 I'm trying to find the n th digit of an integer of an arbitrary length. I was going to convert the integer to a string and use the character at index n... char Digit = itoa(Number).at(n); ...But then I realized the itoa function isn't standard. Is there any other way to do this? 回答1: (number/intPower(10, n))%10 just define the function intPower . 回答2: You can also use the % operator and / for integer division in a loop. (Given integer n >= 0, n % 10 gives the units digit, and n / 10 chops off

问题 I come across a strange problem dealing with python isdigit function. For example: >>> a = u'\u2466' >>> a.isdigit() Out[1]: True >>> a.isnumeric() Out[2]: True Why this character is a digit? Any way to make this return False instead, thanks? Edit, If I don't want to treat it as a digit, then how to filter it out? For example, when I try to convert it to a int: >>> int(u'\u2466') Then UnicodeEncodeError happened. 回答1: U+2466 is the CIRCLED DIGIT SEVEN (⑦), so yes, it's a digit. If your

问题 I wish to output large numbers with thousand-separators (commas or spaces) — basically the same as in How to display numeric in 3 digit grouping but using printf in C (GNU, 99). If printf does not support digit grouping natively, how can I achieve this with something like printf("%s", group_digits(number)) ? It must support negative integers and preferably floats, too. 回答1: If you can use POSIX printf, try #include <locale.h> setlocale(LC_ALL, ""); /* use user selected locale */ printf("%'d",

问题 I'm searching for an algorithm for Digit summing. Let me outline the basic principle: Say you have a number: 18268 . 1 + 8 + 2 + 6 + 8 = 25 2 + 5 = 7 And 7 is our final number. It's basically adding each number of the whole number until we get down to a single (also known as a 'core') digit. It's often used by numerologists. I'm searching for an algorithm (doesn't have to be language in-specific) for this. I have searched Google for the last hour with terms such as digit sum algorithm and

问题 I'm searching for an algorithm for Digit summing. Let me outline the basic principle: Say you have a number: 18268 . 1 + 8 + 2 + 6 + 8 = 25 2 + 5 = 7 And 7 is our final number. It's basically adding each number of the whole number until we get down to a single (also known as a 'core') digit. It's often used by numerologists. I'm searching for an algorithm (doesn't have to be language in-specific) for this. I have searched Google for the last hour with terms such as digit sum algorithm and

问题 I wish to change an integer such as 23457689 to 689, 12457245 to 245 etc. I do not require the numbers to be rounded and do not wish to have to convert to String. Any ideas how this can be done in Python 2.7? 回答1: Use the % operation: >>> x = 23457689 >>> x % 1000 689 % is the mod (i.e. modulo) operation. 回答2: To handle both positive and negative integers correctly: >>> x = -23457689 >>> print abs(x) % 1000 689 As a function where you can select the number of leading digits to keep: import

问题 testing= testing.match(/(\d{5})/g); I'm reading a full html into variable. From the variable, want to grab out all numbers with the pattern of exactly 5 digits. No need to care of whether before/after this digit having other type of words. Just want to make sure whatever that is 5 digit numbers been grabbed out. However, when I apply it, it not only pull out number with exactly 5 digit, number with more than 5 digits also retrieved... I had tried putting ^ in front and $ behind, but it making