difference

问题 As per my research, there is a significant difference in the concept of backstack and how they exist: Activity When an activity is placed to the backstack of activities the user can navigate back to the previous activity by just pressing the back button. Activity can exist independently. Fragment When an fragment is placed to the activity we have to request the instance to be saved by calling addToBackstack() during the fragment transaction . Fragment has to live inside the activity Are there

问题 Hello I am having troubles with my application. I am trying to load a list into listbox1 and then refresh the same list in listbox2 (but with possibly different results) and then compare the two and display in textbox1 the differences between the two list boxes. I have gotten to a point where I am able to tell if there are differences but when it goes to post into the textbox it displays the entire listbox and not the differences. That's a little wordy. Sorry. Below is my code: TextBox1.Text

问题 I want to get the age of users. I tried: $dStart = strtotime('1985-10-24'); $dEnd = strtotime('2014-07-30'); $dDiff = $dEnd - $dStart; echo date('Y',$dDiff); But get 1998 instead 28, what would be the right code? 回答1: strtotime() is not made for date math. DateTime() is much better suited for this: $dStart = new DateTime('1985-10-24'); $dEnd = new DateTime('2014-07-30'); $dDiff = $dStart->diff($dEnd); echo $dDiff->y; Demo 来源： https://stackoverflow.com/questions/25026602/php-strtotime-date

问题 I have a nested dictionary to which I would like to obtain the differences between each value. locsOne = {1:[100], 2:[200], 3:[250]} (these values here are just examples) I'm attempting to apply a abs(-) function to each key:value to get the distance between each and create a dictionary with the results. How I'd like the results to be formatted would be: locsTwo = {1:{2:100, 3:150}, 2:{1:100, 3:50}, 3:{1:150, 2: 50 }} My current attempt is: for i in range(len(listOne)): if abs(listOne[i] -

问题 This question already has an answer here : thrust set difference fails to compile with calling a __host__ function from a __host__ __device__ function is not allowed (1 answer) Closed last year . I tried a simple program using thrust::set. It finds the difference of two sets. However I get compilation error. #include <thrust/set_operations.h> #include <thrust/execution_policy.h> #include <thrust/device_vector.h> int main() { thrust::device_vector<int> A1(7); thrust::device_vector<int> A2(5);

问题 Lets say i have long currentMillis and long oldMillis. The difference between the two timestamps is very tiny and always less than 1 second. If i want to know the difference between the timestamps in milleseconds, i can do the following: long difference = currentmillis-oldmillis; And if i want to convert difference to seconds, i can just divide it by 1000. However if the difference in milliseconds is less than 1000 milliseconds(<1 second), dividing it by 1000 will result in 0. How can i get

问题 I'm developing a script which takes the difference between 2 csv files and makes a new csv file as output with the differences BUT only if the same 2 rows (refers to row number) between the two input files contain different data e.g. row 3 has "mike", "basketball player" in file 1 and row 3 in file 2 has "mike", "baseball player". The output csv would grab these print them and write them to a csv. It works but there are some issues (I know that this question has also been asked several times

问题 I need to find difference between two strings. const string1 = 'lebronjames'; const string2 = 'lebronnjames'; The expected output is to find the extra n and log it to the console. Is there any way to do this in JavaScript? 回答1: Another option, for more sophisticated difference checking, is to make use of the PatienceDiff algorithm. I ported this algorithm to Javascript at... https://github.com/jonTrent/PatienceDiff ...which although the algorithm is typically used for line-by-line comparison

问题 I am running into some issues when trying to find the difference between two dates. As an example I have date1 as 2015-09-14 and date2 as 2015-09-18. The difference would be 5 days, however the code is returning 4 days. Below is the code: $datetime1 = new DateTime($startdate); $datetime2 = new DateTime($enddate); $interval = $datetime1->diff($datetime2); $ptohours = $interval->format('%d %H'); where startdate is 2015-09-14 07:00:00 and enddate is 2015-09-14 16:00:00 . I am trying to calculate

问题 preface: I'm new and self taught. This is my first coding project. I know it's terrible. I'm going to rewrite it once it's complete and working. I'm trying to write a python script that will compare 2 excel files and highlight the cells that are different. I can print out the differences (using pandas) and highlight a cell (only by hard coding a specific cell). I can't figure out how to highlight cells based on the printed out differences. df1 = pd.read_excel(mxln) # Loads master xlsx for