diamond-problem

问题 Java is not allowing inheritance from multiple classes (still it allows inheritance from multiple interfaces.), I know it is very much inline with classic diamond problem. But my questions is why java is not allowing multiple inheritance like C++ when there is no ambiguity (and hence no chances of diamond problem) while inheriting from multiple base class ? 回答1: It was a design decision of Java. You'll never get it, so don't worry too much about it. Although MI might help you make Mixins,

问题 In Java there used to be a subtle but important difference between abstract classes and interfaces: default implementations. Abstract classes could have them, interfaces could not. Java 8 though introduces default implementations for interfaces, meaning this is no longer the critical difference between an interface and an abstract class. So what is? As best as I can tell, the only remaining difference (besides perhaps some under the hood efficiency stuff) is that abstract classes follow

问题 class A { public: void eat(){ cout<<\"A\";} }; class B: virtual public A { public: void eat(){ cout<<\"B\";} }; class C: virtual public A { public: void eat(){ cout<<\"C\";} }; class D: public B,C { public: void eat(){ cout<<\"D\";} }; int main(){ A *a = new D(); a->eat(); } I understand the diamond problem, and above piece of code does not have that problem. How exactly does virtual inheritance solve the problem? What I understand: When I say A *a = new D(); , the compiler wants to know if

问题 In an attempt to fully understand how to solve Java\'s multiple inheritance problems I have a classic question that I need clarified. Lets say I have class Animal this has sub classes Bird and Horse and I need to make a class Pegasus that extends from Bird and Horse since Pegasus is both a bird and a horse. I think this is the classic diamond problem. From what I can understand the classic way to solve this is to make the Animal , Bird and Horse classes interfaces and implement Pegasus from