datediff

问题 My goal is to make fortran return the difference between two times that were passed in as character strings, very simular to VBA's TimeDiff. I've been going through the handling of date and time in fortran for quite a while now, but couldn't find what I need in this perticular case. The first problem in fortran is how to turn a string into a further computable time variable. time_and_dates ctime for example converts the time into a character string, but whats needed in my case is the exact

问题 I'm pulling some data in an SQL query to output to PHP as below. , DATEDIFF('d',Activity.CreatedOn, NOW()) As Dif , DATEDIFF('d',qSWxSRLastUpdated.MaxOfCreatedOn, NOW()) As LastUpd , FORMAT((qSWxSRLastUpdated.MaxOfCreatedOn), 'DD-MMM-YYYY') AS Start , FORMAT((Activity.CreatedOn), 'DD-MMM-YYYY') AS CreatedOn , DATEDIFF('d',(Select CASE WHEN Activity.CreatedOn > qSWxSRLastUpdated.MaxOfCreatedOn THEN Activity.CreatedOn ELSE qSWxSRLastUpdated.MaxOfCreatedOn END), NOW()) AS MostRecentDate Now the

问题 I am working on migrating functions from SQL Server 2000 to MySQL. The following statement executed in SQL Server 2000, gives the output as 109. SELECT DATEDIFF(wk,'2012-09-01','2014-10-01') AS NoOfWeekends1 The equivalent query of in mysql uses timestampdiff() instead of datediff and gives the output as 108. SELECT TIMESTAMPDIFF(WEEK, '2012-09-01', '2014-10-01') AS NoOfWeekends1 I need the output to match when executed in MySQL, so it returns 109. 回答1: I think this could be caused by one of

问题 I have 5 different schedules for 5 weeks: first week = Monday to Friday (8am to 5pm) && Rest days on Saturday and Sunday second week = Monday to Friday (10am to 6pm) && Rest days on Saturday and Sunday third week = Monday to Friday (11am to 7pm) && Rest days on Saturday and Sunday fourth week = Monday Rest Day && Tuesday to Saturday (10:30 am to 6:30pm) && Sunday Rest Day fifth week = Monday Rest Day && Tuesday to Saturday (8:30 am to 5:30pm) && Sunday Rest Day Base on my calculation array [0

问题 I got the time difference between dates like this : $time1 = "2013-02-25 12:00:00"; $time2 = "2013-01-01 12:00:00"; $tdiff = strtotime($time1) - strtotime($time2); I want extract days, hours and minutes from $tdiff . Output should like : 35 days 6 hours 14 minutes I really searched and try to do something by myself. But I can't get true value. ---- EDIT ---- I can found date diff. I want extract days, hours, minutes from calculated time... ---- EDIT 2 ---- Here is my complete mysql code

问题 I have table that holds records with tasks, status and time when triggered: Table tblwork: +-------------+------------+---------------------+-----+ | task | status | stime | id | +-------------+------------+---------------------+-----+ | A | 1 | 2018-03-07 20:00:00 | 1 | | A | 2 | 2018-03-07 20:30:00 | 2 | | A | 1 | 2018-03-07 21:00:00 | 3 | | A | 3 | 2018-03-07 21:30:00 | 4 | | B | 1 | 2018-03-07 22:30:00 | 5 | | B | 3 | 2018-03-07 23:30:00 | 6 | +-------------+------------+-----------------

问题 In pandas I have a function similar to indices = df.dateColumn.apply(holidays.index.searchsorted) df['nextHolidays'] = holidays.index[indices] df['previousHolidays'] = holidays.index[indices - 1] which calculates the distance to the nearest holiday and stores that as a new column. searchsorted http://pandas.pydata.org/pandas-docs/version/0.18.1/generated/pandas.Series.searchsorted.html was a great solution for pandas as this gives me the index of the next holiday without a high algorithmic

问题 I have a query from mysql that has been running on a table I recently migrated to DB2. The query now fails on DB2 due to the line below, saying that DATEDIFF cannot be found. I'm assuming only because this isn't a valid function on db2. Is there an equivalent to this on DB2 that will maintain performance as well as function? SELECT DISTINCT LEAST(180, DATEDIFF(curdate(), start_date)) as days FROM table2 where expire_date > curdate() 回答1: I use the DAYS() function to convert the dates to

问题 In a view have these two dates coming from a table: 2014-12-17 14:01:03.523 - 2014-12-20 09:59:28.783 I need to know the date diff in hours assuming that in a day i can count the hours just from 08 AM and 5 PM. Of course saturdays and sundays must not be included. I tried using this code inside the select but i only got the diff in days, excluding saturdays and sundays. (DATEDIFF(HOUR, convert(datetime,t.EXT_DATAINS-2), convert(datetime,b.EXT_DATAINS-2)) + 1) -(DATEDIFF(wk, convert(datetime,t

问题 This question already has answers here : How to calculate difference in hours (decimal) between two dates in SQL Server? (8 answers) Closed 3 years ago . This question have been asked many times but i cannot find any easy answers on how to get hours and minutes from a datediff() . From To OUTPUT 08:00 16:30 8,5 10:00 16:30 6,5 08:00 15:00 7 I would like to use datediff() and want the output as my result 回答1: just take datediff() by minute and then divide by 60 select datediff(minute, '08:00',