data-management

I have this code and can't figure out what I'm doing wrong. As you can see in the code below I have a plist file called shifts.plist which is in my supporting files folder. Here is my plist structure. NSString *path = [[NSBundle mainBundle] pathForResource:@"shifts" ofType:@"plist"]; dictionary = [[NSMutableDictionary alloc]initWithContentsOfFile:path]; cell.textLabel.text = [secondTableInfo objectAtIndex:indexPath.row]; NSLog(@"%@",[[dictionary objectForKey:@"name"]objectAtIndex:0]); I would ultimately like to read the name entries and populate a UITableView with them. I used NSLog to output

I have the following data: id tests testvalue 1 A 4 1 B 5 1 C 3 1 D 3 2 A 3 2 B 3 3 C 3 3 D 4 4 A 3 4 B 5 4 A 1 4 B 3 I would like to change the above long data format into following wide data. id testA testB testC testD index 1 4 5 3 3 1 2 3 3 . . 2 3 . . 3 4 3 4 3 5 . . 4 4 1 3 . . 5 I am trying reshape wide testvalue, i(id) j(tests) It gives error because there are no unique values within tests . What would be the solution to this problem? You need to create an extra identifier to make replicates distinguishable. clear input id str1 tests testvalue 1 A 4 1 B 5 1 C 3 1 D 3 2 A 3 2 B 3 3 C 3

This code works: library(plyr) x <- data.frame(V= c("X", "Y", "X", "Y", "Z" ), Z = 1:5) ddply(x, .(V), function(df) sum(df$Z),.parallel=FALSE) While this code fails: library(doSMP) workers <- startWorkers(2) registerDoSMP(workers) x <- data.frame(V= c("X", "Y", "X", "Y", "Z" ), Z = 1:5) ddply(x, .(V), function(df) sum(df$Z),.parallel=TRUE) stopWorkers(workers) >Error in do.ply(i) : task 3 failed - "subscript out of bounds" In addition: Warning messages: 1: <anonymous>: ... may be used in an incorrect context: ‘.fun(piece, ...)’ 2: <anonymous>: ... may be used in an incorrect context: ‘.fun

I am trying to reshape a dataframe: Currently it looks like this: ID | Gender |A1 | A2 | A3 | B1 | B2 | B3 ID_1 | m | 3 | 3 | 3 | 2 | 3 | 2 ID_2 | f | 1 | 1 | 1 | 4 | 4 | 4 I want to have something like: ID | Gender | A1 | A2 | A3 ID_1 | m | 3 | 3 | 3 <- this would be columns A1 - A3 for ID 1 ID_1 | m | 2 | 2 | 2 <- this would be columns B1 - B3 for ID 1 ID_2 | f | 1 | 1 | 1 <- this would be columns A1 - A3 for ID 2 ID_2 | f | 4 | 4 | 4 <- this would be columns B1 - B3 for ID 2 (A1 and B1 / A2 and B2 are the same variables (with regard to the content), so for example: A1 and B1 would be both

I have a data frame like this: id y1 y2 y3 y4 --+--+--+--+-- a |12|13|14| b |12|18| | c |13| | | d |13|14|15|16 I want to reshape in such a way that I end with two columns. The above example would then become: id from to --+----+--- a |12 |13 a |13 |14 a |14 | b |12 |18 b |18 | c |13 | d |13 |14 d |14 |15 d |15 |16 Each id has a 'from' and a 'to' per pair of year values. Does anybody know of an easy way to do this? I tried using reshape2 . I also looked at Combine Multiple Columns Into Tidy Data but I think my case is different. You can use lapply to loop over the pairs of columns and rbind to