create-table

问题 I've been stuck at creating tables. Here is the code I am stuck at how to make the code work in loan_type to write office worker or non office worker create table loaner ( loan_id number(5) primary key, loan_type VARCHAR2 (16), loan_start_date date, loan_end_date date, ) create table office_worker ( worker_id number(5) primary_key, loan_id number(5) references loaner(loan_id), worker_name varchar2(50) ) create table nonoffice_worker ( nonworker_id number(5) primary_key, loan_id number(5)

问题 This is the message I'm getting ER_WRONG_VALUE_COUNT_ON_ROW: Column count doesn't match value count at row 1 This is my whole code. Where is my mistake? DROP TABLE student; CREATE TABLE employee ( emp_id INT PRIMARY KEY, first-name VARCHAR(40), birth_day DATE, sex VARCHAR(1), SALARY INT, super_id INT, branch_id INT ); CREATE TABLE branch ( branch_id INT PRIMARY KEY, branch_name VARCHAR(40), mgr_id INT, mgr_start_date DATE, FOREIGN KEY(mgr_id) REFERENCES employee(emp_id) ON DELETE SET NULL );

问题 I need some functionality for dynamic creation table in DB. Algorithm is: 1) register new user -> make record in DB (this is simple) 2) after registration create table like user_data_abcdef123456... where abcdef123456 - is random pregenerated hash. this table must created from (for example) existing default entity (user_data_) Entity: Path\To\Entity\UserData: type: entity table: user_data_ .... in Controller do like this: $doctrine = $this->getDoctrine(); /** @var AbstractSchemaManager

问题 Sorry for the wall of text guys but this one requires expliaining, way too much code to post... I'm importing fixed width files into access in methods that require data entry. I import the file using transferText into two specs (ones global, the other is special circumstance). I have a function that uses DAO to cycle through all Field objects in TableDefs to build a duplicate table including an AutoIncrement PK so I have the ability to edit these records. I push the data into that table with

问题 I am trying to create a table in mySQL. This is my php page below, when I run the page there are no errors but the table is not in mySQL and when I test the code in mySQL I'm getting the error #1064 - You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near '$user = "root"' at line 1. I've done a bit of research into what this error means but I'm getting no where. I don't really understand what it means. If I'm

问题 I'm using HSQLDB for persisting a small data, in my query I want to create tables at first time and if they are not exist anymore. However with HSQLDB I cannot execute the query "CREATE TABLE XYS IF NOT EXISTS" like other dbms like mysql or mssql. Please give me solution for this case. 回答1: HSQLDB supports the syntax like the example below: CREATE TABLE IF NOT EXISTS xyx (a int, b varchar(10)) The syntax is supported by recent HSQLDB 2.3.X versions. 来源： https://stackoverflow.com/questions

问题 I make a query with INNER JOIN and the result was 12 millions lines. I like to put this in a table. I did some tests and when I created the table using clause AS SELECT was more faster than, create the table first and run a INSERT with SELECT after. I don't understand why. Somebody can explain for me? Tks 回答1: If you use 'create table as select' (CTAS) CREATE TABLE new_table AS SELECT * FROM old_table you automatically do a direct-path insert of the data. If you do an INSERT INTO new_table AS

问题 I'm using PostgreSQL and am an SQL beginner. I'm trying to create a table from a query, and if I run: CREATE TABLE table_name AS (....query...) it works just fine. But then if I add 'if not exists' and run: CREATE TABLE IF NOT EXISTS table_name AS (....query...) using exactly the same query, I get: ERROR: syntax error at or near "as" Is there any way to do this? 回答1: CREATE TABLE AS is considered a separate statement from a normal CREATE TABLE, and until Postgres version 9.5 (see changelog

问题 I've read the rather cool styled BNF grammar for the SQLite create table statement found here: http://www.sqlite.org/lang_createtable.html I was wondering how I'd go about creating a link table between these I have one table, lets say, houses, and another electrical_items. I want to create a link table to have the house_id and the item_id as a composite key, but I'm not sure how I'd go about doing it, it doesn't appear to allow a primary key to be a foreign key ? N.B I want a third field pap

问题 In a MySQL script you can write: CREATE TABLE IF NOT EXISTS foo ...; ... other stuff ... and then you can run the script many times without re-creating the table. How do you do this in PostgreSQL? 回答1: This feature has been implemented in Postgres 9.1: CREATE TABLE IF NOT EXISTS myschema.mytable (i integer); For older versions , here is a function to work around it: CREATE OR REPLACE FUNCTION create_mytable () RETURNS void AS $func$ BEGIN IF EXISTS (SELECT FROM pg_catalog.pg_tables WHERE