constants

问题 I am working on the some kind of the 2D Regression Deep network with keras, but the network has constant output for every datasets, even I test with handmade dataset in this code I feed the network with a constant 2d values and the output is linear valu of the X (2*X/100) but the out put is constant. import resource import glob import gc rsrc = resource.RLIMIT_DATA soft, hard = resource.getrlimit(rsrc) print ('Soft limit starts as :', soft) resource.setrlimit(rsrc, (4 * 1024 * 1024 * 1024,

问题 I am using Ruby on Rails 3.0.7 and I would like to find some records at run time for validation purposes but passing\setting a value for that finder method. That is, in a my class I have the following: class Group < < ActiveRecord::Base validates :relation_id, :presence => true, :inclusion => { :in => ... # Read below for more information about } end If I set :in to be :in => User.find(1).group_ids it works, but I would like to set "some-dynamic-things" for the finder method instead of the 1

问题 I am using Ruby on Rails 3.0.7 and I would like to find some records at run time for validation purposes but passing\setting a value for that finder method. That is, in a my class I have the following: class Group < < ActiveRecord::Base validates :relation_id, :presence => true, :inclusion => { :in => ... # Read below for more information about } end If I set :in to be :in => User.find(1).group_ids it works, but I would like to set "some-dynamic-things" for the finder method instead of the 1

问题 I am using Ruby on Rails 3.0.7 and I would like to find some records at run time for validation purposes but passing\setting a value for that finder method. That is, in a my class I have the following: class Group < < ActiveRecord::Base validates :relation_id, :presence => true, :inclusion => { :in => ... # Read below for more information about } end If I set :in to be :in => User.find(1).group_ids it works, but I would like to set "some-dynamic-things" for the finder method instead of the 1

问题 Given an example const int limit = 500; const int * const cpci = &limit; const int * const * pcpci = &cpci; I am having difficulty understanding what the last line means. Basically in array terms the value pcpci it's just an array of (const int * const)'s. But i can't seem to make multiple copies inside pcpci since it is not supposed to be a constant pointer. For Example const int limit = 500; const int * const cpci = &limit; const int * const * pcpci = &cpci; const int limit2 = 600; const

问题 Given an example const int limit = 500; const int * const cpci = &limit; const int * const * pcpci = &cpci; I am having difficulty understanding what the last line means. Basically in array terms the value pcpci it's just an array of (const int * const)'s. But i can't seem to make multiple copies inside pcpci since it is not supposed to be a constant pointer. For Example const int limit = 500; const int * const cpci = &limit; const int * const * pcpci = &cpci; const int limit2 = 600; const

问题 This question about syntax/syntax capabilities in PHP. Take for example, using variables to store class names when declaring objects: $className= 'myClass'; $obj = new $className; I was wondering if there were some way to do the same with constants. Something along the lines of: define('CLASS_NAME','myClass'); $obj = new {CLASS_NAME}; This doesn't work. Obviously I could just use a variable as an intermediary step, but I was mostly just wondering for edification purposes whether this was a

问题 I was not sure what to call these flags, but what I am referring to is: #define TEST_DEF 50000U //<- the "U" here Google searching when you are not familiar with the jargon used to describe your question is futile. What I am trying to do is use these constant definitions and make sure the value is only of a certain length, namely 8 or 16 bits. How can I do this and what is it referred to as? 回答1: There are five integer literal suffixes in C: u , l , ul , ll , and ull . Unlike nearly

问题 I have a function that I am trying to run but it shows the message as CONSTANT already defined. I tried to put a condition saying "if defined" about the function but still nothing. Is there any method to ignore this and see the output? 回答1: Replace this: define('constant', 'value'); with this: if (!defined('constant')) define('constant', 'value'); 回答2: define() Example: /* Note the use of quotes, this is important. This example is checking * if the string 'TEST' is the name of a constant

问题 Upgrade advisor says "Non-integer constants are not allowed in the ORDER BY clause in 90 or later compatibility mode". But, when I try the below statement in SQL Server 2008 , it works just fine. So, my questions is - What exactly is a non-integer constant? select POS_NO ,EMP_NO ,ORG_NAME ,EMP_LAST_NAME + ', ' + EMP_FIRST_NAME AS "Name" FROM dbo.MyEmpTable ORDER BY "Name" 回答1: Here is what the MSDN have to say about character constant that are in a sense the non-integer constant Character