concatenation

问题 I have a table in MS Access composed of items, and there's another table where salespeople tie into those items. So for example the item "pencil" could have 4 people that sold it associated. Once everything comes out of the query I have something like this: item seller pencil joe pencil bob pencil charles pen john eraser ruth paper charles I have a report form where I'd like to list each item's sellers on a single line. Kind of like: pencil: bob, joe, charles pen: john eraser: ruth paper:

问题 IS it possible to concatenate A1 and A2 from the particular table (for example): CREATE TABLE MY_SCHEME.CONC_BLOB ( A1 BLOB, A1_SORT NUMBER(20), T_TYPE VARCHAR2(9 BYTE), A2 BLOB, A2_SORT NUMBER(20), A3 VARCHAR2(32 BYTE), A4 BLOB, A5 VARCHAR2(8 BYTE) ) ? How? 回答1: BLOBs can be concatenated with the DBMS_LOB package, in particular with the APPEND procedure. But you will need to use some PL/SQL that iterates over the relevant rows and calls the procedure. I don't quite understand what you mean

问题 This might be a silly question but I'm trying to concatenate the source of an image in React to be rendered on the screen, but it's not working. <img src=`https://www.cryptocompare.com/{this.state.cryImage}` /> In this.state.cryImage, I only get the second half of the link (I'm pulling data from an API) so for example it would be something like: media/19633/btc.png Am I concatenating incorrectly or is this just not possible? 回答1: You've missed $ sign and brackets for attribute <img src={

问题 I'm trying to update the value of a field in a MongoDB collection by concatenating it with a literal string. Besides this, the field is an integer, and I want to add a "0" in front, so it will became a string. I've read that I can't use the old value of the field in a single update instruction, so I'm using a forEach() method. Here is the code: db.col_1.find({"field_1": {$lt: 10000}}).forEach( function(i){ db.col_1.update({_id: i._id}, {$set: { "field_1": {$concat: ["0", i.field_1]}}} ) });

问题 I need to concatenate column values into a single column. I have column names in a variable as colnames=col1,col2,col3 . I am writing the below query from a unix shell and calling the hive. But when I do this, I am getting only the column names concatenated not the values of those columns. select concat('regexp_replace("${colnames}",",","^")) as result from table; I would like the output as: ABCD^10^XYZ ( ABCD , 10 , XYZ are the column values) 回答1: You need concat_ws function to concatenate

问题 I feel uncomfortable asking, but how do I convert an array of words to make a sentence ? I keep finding the other way round. Something like: var a = ['hello', 'world']; and obtain : hello world 回答1: This doesn't need jquery. Javascript has a very simple way of doing this with the join function: a.join(" "); 回答2: Just join the elements of the array into a string using a space as a separator: var sentence = a.join(" "); https://developer.mozilla.org/en/JavaScript/Reference/Global_Objects/Array

问题 I feel uncomfortable asking, but how do I convert an array of words to make a sentence ? I keep finding the other way round. Something like: var a = ['hello', 'world']; and obtain : hello world 回答1: This doesn't need jquery. Javascript has a very simple way of doing this with the join function: a.join(" "); 回答2: Just join the elements of the array into a string using a space as a separator: var sentence = a.join(" "); https://developer.mozilla.org/en/JavaScript/Reference/Global_Objects/Array

问题 I feel uncomfortable asking, but how do I convert an array of words to make a sentence ? I keep finding the other way round. Something like: var a = ['hello', 'world']; and obtain : hello world 回答1: This doesn't need jquery. Javascript has a very simple way of doing this with the join function: a.join(" "); 回答2: Just join the elements of the array into a string using a space as a separator: var sentence = a.join(" "); https://developer.mozilla.org/en/JavaScript/Reference/Global_Objects/Array

问题 I created a function that accepts multiple arguments of dictionaries, and returns a concatenated dictionary. I researched online for a while about concatenating a merging dictionaries and tested the interesting ones. They all resulted in updating the values (or overwriting them). My use case is passing in dictionaries where each key has a single value, and want a dictionary with the same or different keys, with a list of values for each key. That is my definition of what a so-called

问题 For list of strings, define the multiplication operation in as concatenating here: l1 = ['aa', 'bb', 'cc'] l2 = ['11', '22'] l3 = l1 op l2 Expected output: l3 = ['aa11', 'aa22', 'bb11', 'bb22', 'cc11', 'cc22'] Simply we can use for l in l1: for ll in l2: l3.append(l+ll) But I'd be grateful to hear a pythonic solution. 回答1: from itertools import product l1 = ['aa', 'bb', 'cc'] l2 = ['11', '22'] l3 = [x+y for (x,y) in product(l1,l2)] print(l3) But it's effectively the same thing as what you're