compare

问题 I have three RichTextBoxes . I want to compare all the words of RichTextbox1 with Richtextbox2 one by one with space or comma as the delimiter. If they are same do nothing, if not highlight the text to some color and save it in RichTextBox3 . I am having some trouble with the loop. 回答1: Explanation First we will declare some variables to shorten our writing work. We'll then use the For Each command. Here we will take two rounds to scan the differences, first of Richtextbox1 which is not in

问题 I have three RichTextBoxes . I want to compare all the words of RichTextbox1 with Richtextbox2 one by one with space or comma as the delimiter. If they are same do nothing, if not highlight the text to some color and save it in RichTextBox3 . I am having some trouble with the loop. 回答1: Explanation First we will declare some variables to shorten our writing work. We'll then use the For Each command. Here we will take two rounds to scan the differences, first of Richtextbox1 which is not in

问题 Ive just written the following code, which will order strings by their native string.Compare() but allow a collection of exceptions (in this case customPriority ) that will place priority over the default string.Compare() function. It all seems a bit long winded, I was wondering if there was something built into .NET to allow this? var unorderered = new[] { "a", "b", "c", "x", "y", "z" }; var ordered = unorderered.OrderBy(a => a, new CustomStringComparer()); //expected order y,x,a,b,c,z class

问题 I've found a bug (in my code) that results from String.CompareTo and binary search because my custom IComparer (for the wrapping type) uses String.Compare(x, y, StringComparison.Ordinal) . This is because items.OrderBy(i => i.Name) (where Name is of type string) used to build the Array to search used the string object itself as the IComparable - and such has different rules: The comparison uses the current culture to obtain culture-specific information such as casing rules and the alphabetic

问题 I've found a bug (in my code) that results from String.CompareTo and binary search because my custom IComparer (for the wrapping type) uses String.Compare(x, y, StringComparison.Ordinal) . This is because items.OrderBy(i => i.Name) (where Name is of type string) used to build the Array to search used the string object itself as the IComparable - and such has different rules: The comparison uses the current culture to obtain culture-specific information such as casing rules and the alphabetic

问题 Since you can store a regexp in a variable var regexp = /a/; why do console.log(/a/ == /a/); and even var regexp1 = /a/; var regexp2 = /a/; console.log(regexp1 == regexp2); both return false ? 回答1: Try this: String(regexp1) === String(regexp2)) You are getting false because those two are different objects. 回答2: "Problem": regex is an object - a reference type , so the comparsion is done by reference , and those are two different objects. console.log(typeof /a/); // "object" If both operands

问题 I have a dataframe df_in like so: import pandas as pd dic_in = {'A':['aa','aa','bb','cc','cc','cc','cc','dd','dd','dd','ee'], 'B':['200','200','200','400','400','500','700','700','900','900','200'], 'C':['da','cs','fr','fs','se','at','yu','j5','31','ds','sz']} df_in = pd.DataFrame(dic_in) I would like to investigate the 2 columns A and B in the following way. I 2 consecutive rows[['A','B']] are equal then they are assigned a new value (according to a specific rule which i am about to describe

问题 I have two lists of ranked items. Each item has an rank and an associated score. The score has decided the rank. The two lists can contains (and usually do) different items, that is their intersection can be empty. I need measures to compare such rankings. Are there well-known algorithms (in literature or real-world systems) to do so ? The measure of distance should take into account the scores as well as the ranks of the items. 回答1: This question has never been answered before, but I still

问题 I have two lists of ranked items. Each item has an rank and an associated score. The score has decided the rank. The two lists can contains (and usually do) different items, that is their intersection can be empty. I need measures to compare such rankings. Are there well-known algorithms (in literature or real-world systems) to do so ? The measure of distance should take into account the scores as well as the ranks of the items. 回答1: This question has never been answered before, but I still

问题 I have two seemingly equal double values in PHP (at least when echoing them). But when comparing them with double equals, for some reason, it evaluates to false. Are there any special considerations when performing this kind of comparison? 回答1: You shouldn't compare floating point numbers using the == operator. See the big warning and explanation in the php manual What will work is asserting that the two numbers are within a certain small distance of each other like this: if(abs($a - $b) < 0