The type signature of a combinator does not match the type signature of its equivalent Lambda function
Consider this combinator: S (S K) Apply it to the arguments X Y: S (S K) X Y It contracts to: X Y I converted S (S K) to the corresponding Lambda terms and got this result: (\x y -> x y) I used the Haskell WinGHCi tool to get the type signature of (\x y -> x y) and it returned: (t1 -> t) -> t1 -> t That makes sense to me. Next, I used WinGHCi to get the type signature of s (s k) and it returned: ((t -> t1) -> t) -> (t -> t1) -> t That doesn't make sense to me. Why are the type signatures different? Note: I defined s, k, and i as: s = (\f g x -> f x (g x)) k = (\a x -> a) i = (\f -> f) We start