clamp

问题 What is the difference between Uint8Array and Uint8ClampedArray in JavaScript? I understand that Uint8ClampedArray is used with canvas for pixel manipulations. Why is that and what is the benefit? 回答1: Looking at the examples for Uint8ClampedArray and Uint8Array, it looks like the difference is how values are treated when assigned. If you are trying to set one element to a clamped array to any value outside of the range 0-255 , it will simply default to 0 or 255 (depending on whether the

问题 I am working on a game that rotates an object on the z axis. I need to limit the total rotation to 80 degrees. I tried the following code, but it doesn't work. minAngle = -40.0f and maxAngle = 40.0f Vector3 pos = transform.position; pos.z = Mathf.Clamp(pos.z, minAngle, maxAngle); transform.position = pos; 回答1: The code you posted clamps the z position. What you want is to use transform.rotation void ClampRotation(float minAngle, float maxAngle, float clampAroundAngle = 0) { //clampAroundAngle

问题 I am working on a game that rotates an object on the z axis. I need to limit the total rotation to 80 degrees. I tried the following code, but it doesn't work. minAngle = -40.0f and maxAngle = 40.0f Vector3 pos = transform.position; pos.z = Mathf.Clamp(pos.z, minAngle, maxAngle); transform.position = pos; 回答1: The code you posted clamps the z position. What you want is to use transform.rotation void ClampRotation(float minAngle, float maxAngle, float clampAroundAngle = 0) { //clampAroundAngle

问题 Is there a more efficient way to clamp real numbers than using if statements or ternary operators? I want to do this both for doubles and for a 32-bit fixpoint implementation (16.16). I'm not asking for code that can handle both cases; they will be handled in separate functions. Obviously, I can do something like: double clampedA; double a = calculate(); clampedA = a > MY_MAX ? MY_MAX : a; clampedA = a < MY_MIN ? MY_MIN : a; or double a = calculate(); double clampedA = a; if(clampedA > MY_MAX

问题 I have a problem with my clamp macro, when when my value is over 10 and my high is over 17 it stops working. Any idea? #define CLAMP(value, low, high) (((value)<(low))?(low):(((value)>(high))?(high):(value))) 回答1: I would suggest using a safer way than a macro: template <typename T> T CLAMP(const T& value, const T& low, const T& high) { return value < low ? low : (value > high ? high : value); } 回答2: Your macro is fine. If you pass in a high that is less than low , you'll see strange results,

问题 I am trying to implement a Microfacet BRDF shading model (similar to the Cook-Torrance model) and I am having some trouble with the Beckmann Distribution defined in this paper: https://www.cs.cornell.edu/~srm/publications/EGSR07-btdf.pdf Where M is a microfacet normal, N is the macrofacet normal and ab is a "hardness" parameter between [0, 1]. My issue is that this distribution often returns obscenely large values, especially when ab is very small. For instance, the Beckmann distribution is

问题 Suppose I have a value , I usually do this to "clamp" it to a range, here the range [0..1] . That is if it is below the range start, increase it to the range start, it above the range end, reduce it to the range end. clampedValue = Math.max(0, Math.min(1, value)); Is there any built in function for clamping to a range? 回答1: Is there any built in function for clamping to a range? No. 回答2: Having looked at the generic clamp method offered up in another answer, it is worth noting that this has

问题 I have the following code: new_index = index + offset if new_index < 0: new_index = 0 if new_index >= len(mylist): new_index = len(mylist) - 1 return mylist[new_index] Basically, I calculate a new index and use that to find some element from a list. In order to make sure the index is inside the bounds of the list, I needed to write those 2 if statements spread into 4 lines. That's quite verbose, a bit ugly... Dare I say, it's quite un-pythonic . Is there any other simpler and more compact

问题 I have the following code: new_index = index + offset if new_index < 0: new_index = 0 if new_index >= len(mylist): new_index = len(mylist) - 1 return mylist[new_index] Basically, I calculate a new index and use that to find some element from a list. In order to make sure the index is inside the bounds of the list, I needed to write those 2 if statements spread into 4 lines. That's quite verbose, a bit ugly... Dare I say, it's quite un-pythonic . Is there any other simpler and more compact

问题 I have a list of several thousand floats that I want to be able to slice by min and max values. E.G. using: flist = [1.9842, 9.8713, 5.4325, 7.6855, 2.3493, 3.3333] (my actual list is 400,000 floats long, but the above is a working example) I want something like def listclamp(minn, maxn, nlist): such that print listclamp(3, 8, flist) should give me [3.3333, 5.4325, 7.6855] I also need to do this 10,000 to 30,000 times, so speed does count. (I have no sample code for what I've tried so far,