chunking

ne_chunk without pos_tag in NLTK

由 三世轮回 提交于 2019-11-27 04:47:33
问题 I'm trying to chunk a sentence using ne_chunk and pos_tag in nltk. from nltk import tag from nltk.tag import pos_tag from nltk.tree import Tree from nltk.chunk import ne_chunk sentence = "Michael and John is reading a booklet in a library of Jakarta" tagged_sent = pos_tag(sentence.split()) print_chunk = [chunk for chunk in ne_chunk(tagged_sent) if isinstance(chunk, Tree)] print print_chunk and this is the result: [Tree('GPE', [('Michael', 'NNP')]), Tree('PERSON', [('John', 'NNP')]), Tree('GPE

Transferring large payloads of data (Serialized Objects) using wsHttp in WCF with message security

由 Deadly 提交于 2019-11-27 00:31:09
问题 I have a case where I need to transfer large amounts of serialized object graphs (via NetDataContractSerializer) using WCF using wsHttp. I'm using message security and would like to continue to do so. Using this setup I would like to transfer serialized object graph which can sometimes approach around 300MB or so but when I try to do so I've started seeing a exception of type System.InsufficientMemoryException appear. After a little research it appears that by default in WCF that a result to

how to split an iterable in constant-size chunks

由 孤街浪徒 提交于 2019-11-26 17:25:39
Possible Duplicate: How do you split a list into evenly sized chunks in Python? I am surprised I could not find a "batch" function that would take as input an iterable and return an iterable of iterables. For example: for i in batch(range(0,10), 1): print i [0] [1] ... [9] or: for i in batch(range(0,10), 3): print i [0,1,2] [3,4,5] [6,7,8] [9] Now, I wrote what I thought was a pretty simple generator: def batch(iterable, n = 1): current_batch = [] for item in iterable: current_batch.append(item) if len(current_batch) == n: yield current_batch current_batch = [] if current_batch: yield current

How do I avoid Clojure's chunking behavior for lazy seqs that I want to short circuit?

由 对着背影说爱祢 提交于 2019-11-26 12:19:14
问题 I have a long, lazy sequence that I want to reduce and test lazily. As soon as two sequential elements are not = (or some other predicate) to each other, I want to stop consuming the list, which is expensive to produce. Yes, this sounds like take-while , but read further. I wanted to write something simple and elegant like this (pretending for a minute that every? works like reduce ): (every? = (range 100000000)) But that does not work lazily and so it hangs on infinite seqs. I discovered

how to split an iterable in constant-size chunks

由 末鹿安然 提交于 2019-11-26 05:26:06
问题 Possible Duplicate: How do you split a list into evenly sized chunks in Python? I am surprised I could not find a \"batch\" function that would take as input an iterable and return an iterable of iterables. For example: for i in batch(range(0,10), 1): print i [0] [1] ... [9] or: for i in batch(range(0,10), 3): print i [0,1,2] [3,4,5] [6,7,8] [9] Now, I wrote what I thought was a pretty simple generator: def batch(iterable, n = 1): current_batch = [] for item in iterable: current_batch.append
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