check-constraints

How to specify the cardinality of a @OneToMany in EclipseLink/JPA

邮差的信 提交于 2019-12-06 11:26:11
问题 I'm trying to impose a @Oneto7 association. I'd have imagined an attribute that specifies the target many value, but have found none. If there is no such attribute, how else, in JPA/EclipseLink would one achieve it? 回答1: You could use the Bean Validation API (JSR-303) - Hibernate Validator being the RI - and add a Size constraint on your collection: @Size(min = 7, max = 7) protected Set<Foo> foos = new HashSet<Foo>(); If you're using JPA 1.0, have a look at this previous answer to see how to

OCL constraints checking on Eclipse Papyrus

∥☆過路亽.° 提交于 2019-12-06 01:37:38
Does anyone manage to check OCL constraints on a class diagram modeled in Eclipse Papyrus ? I have definied a simple test profile with only one constraint on a stereotype attribute : {OCL} self.property > 0 The stereotype extends the Property metaclass so I applied it on a class attribute and I set the property of the stereotype to 0. But I never got an error with the Validation > Validate Model command from the context menu. Any help would be much appreciate. Thanks by advance. I answer to myself for other people who might have the same problem. OCL constraints checking doesn't work for

Using a case statement in a check constraint

血红的双手。 提交于 2019-12-05 18:56:18
i'v been learning SQL for the last week but I am unsure how to correctly add a case statement within a check constraint. Can anybody give me any pointers? I have the following grade table: CREATE TABLE Grade ( salary_grade char(1) NOT NULL CHECK (salary_grade = UPPER(salary_grade)), CONSTRAINT ck_grade_scale CHECK( CASE WHEN salary_grade = '[A-D]' THEN salary_scale = 'S1' WHEN salary_grade = '[D-G]' THEN salary_scale = 'S2' END) salary_scale char(2) DEFAULT 'S1' NOT NULL, CONSTRAINT pk_grade PRIMARY KEY (salary_grade), CONSTRAINT ck_salary_grade CHECK (REGEXP_LIKE(salary_grade, '[A-G]', 'c')),

Hibernate Check Annotation

人盡茶涼 提交于 2019-12-05 03:46:01
I have a table with three fields, say a, b, c. I would like to add a constraint ensuring that if a is not null, then also b and c are not null. I have done that using following SQL ALTER TABLE sample ADD CONSTRAINT no_nulls CHECK (CASE WHEN a IS NOT NULL THEN b IS NOT NULL AND c IS NOT NULL END) Is there a way to achieve same effect using hibernate annotation @Check? I can't find a helpful example with that annotation, do developers tend not to use it at all? Yes it is possible if @Check is used at class level like this: @Entity @Check(constraints = "COL_A IS NULL OR (COL_B IS NOT NULL and COL

How much cost check constraints in Postgres 9.x?

最后都变了- 提交于 2019-12-04 19:45:54
I'd like to know if there are some benchmark to compare how much cost insert some check constraints on a table of 60 columns where on 20 i'd like to insert a constraints of NotEmpty and on 6 rows NotNull. My case is that i have on my table Empty values and Null values (that in my case means always "no data"). I'd like to unify that data values with just one. That's why I'm thinking to insert NotEmpty constraints on columns, because as i have read null value are not heavy (in byte size) as like empty values (and respect his real meaning). But from other side NotNull Constraint are more deep

How to constrain the number of records allowed in an SQL table?

▼魔方 西西 提交于 2019-12-04 19:08:17
Say I have two tables, Parent and Child. Parent has a MaxChildren (int) field and Child has an Enabled (bit) field and a ParentID (int) field linking back to the parent record. I'd like to have a constraint such that there can't be more than MaxChildren records for each parent where Enabled = 1. This would mean that any attempt to insert or update any record in the Child table will fail if it goes over the applicable MaxChildren value, or any attempt to lower MaxChildren to below the current number of applicable Child records will fail. I'm using MS SQL Server, but I'm hoping there's a

How do I have a check constraint that refers to another table?

拥有回忆 提交于 2019-12-04 11:28:23
问题 I have the following tables in a SQL Server 2008 db: tblItem , which has an ItemID field; tblGoodItem , which also has an ItemID field, and has a foreign key pointing to tblItem; tblBadItem , which also has an ItemID field, and also has a foreign key pointing to tblItem. An item cannot be both a good item and a bad item; it must either be the one or the other. However, whether the item is good or bad, it must be an item. My question is this: how do I add a constraint to the ItemID fields in

MySql workbench CHECK constraint [duplicate]

戏子无情 提交于 2019-12-04 08:24:28
This question already has an answer here: CHECK constraint in MySQL is not working 8 answers Here I want to create 2 CHECK constraint before the record insert to the database. ALTER TABLE SubjectEnrollment ADD CONSTRAINT register CHECK (register <= classSize AND register >=0), ADD CONSTRAINT available CHECK (available <= classSize AND available >= 0); register attribute should not more than classSize attribute and less than 0. available attribute should not more than classSize attribte and less than 0. When I type in this syntax in MySql Workbench, it complaints "Syntax Error: unexpected

sql CHECK constraint not working properly [duplicate]

↘锁芯ラ 提交于 2019-12-04 05:16:02
问题 This question already has answers here : CHECK constraint in MySQL is not working (8 answers) Closed 10 months ago . I have created a table schedule with a check constraint: mysql> create table schedule(order_date date, dely_date date check(dely_date>order_date)); Query OK, 0 rows affected (0.50 sec) When I insert a value which violates check constraint, sql reports no error. mysql> insert into schedule values('2015-11-20','2014-12-25'); Query OK, 1 row affected (0.10 sec) mysql> select *

PostgreSQL check constraint for foreign key condition

六眼飞鱼酱① 提交于 2019-12-03 19:07:14
问题 I have a table of users eg: create table "user" ( id serial primary key, name text not null, superuser boolean not null default false ); and a table with jobs: create table job ( id serial primary key, description text ); the jobs can be assigned to users, but only for superusers. other users cannot have jobs assigned. So I have a table whereby I see which job was assigned to which user: create table user_has_job ( user_id integer references "user"(id), job_id integer references job(id),